How to add double quotes into string.I want to prepare command into following way with string.
awk 'BEGIN {printf "x
%10s %10s
", "Vol", "Current"}{if($1+0==$1){printf "%10.5f %10.5f
", $2, $3}} END {printf "y
"}'
So imagine you have this string:
"somedata here "some data here" some more data here"
I need to parse this:
somedata here "some data here" some more data here
I tried to do it with Regex and was capable of parsing
[0] = somedata here
[1] = some data here
[2] = some more data here
Here is my current code:
string Buffer = string.Empty;
foreach (Match match in Regex.Matches(strLine, "".*?""))
Buffer = match.ToString();
I am working on a String compare program and i got the program to work properly i was just wondering how to put user input into quotes.
here is my programming
int main {
const int LENGTH = 40;
char s1[LENGTH], s2[LENGTH];
cout << "== String Compare ==" << endl;
cout << "Enter a word" << endl;
[Code] ....
the input is :
Dorito
dorito
the output needs to look like this:
"Dorito" comes before "dorito".
When one of the cells in my DGV contains quotes, it throws off the data in the CSV file by splitting the string into seperate columns.
foreach (DataGridViewRow row in dgv_NewData.Rows) {
if (!row.IsNewRow) {
for (int i = 0; i < row.Cells.Count; i++) {
sb.Append(row.Cells[i].Value + ",");
var value = row.Cells[i].Value.ToString();
[Code] ....
I am trying to highlight integers in a textbox.
The problem, is that I dont know how to make Regex get Integers no matter what (e.g. even if an =, >,<,>=,<= sign is in front or anything) unless it is encased in a string e.g. "'s or whatever.
My current code does this:
I do not want the numbers to be highlighted if they are in a string.
I want to convert string to double. I refered this strtod() - C Library Function Example
Code:
#include <stdio.h>
#include <string.h>
int main() {
const char string[] = "$$GPRMC,013732.000,A,3150.7238,N,11711.7278,E,0.00,0.00,220413,,,A*68";
char term;
const char delims[] = ",";
}
[code]....
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
View 1 Replies View Relatedi think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width;
int height;
int area;
double gop;
String ^strWidth;
String ^strHeight;
String ^strArea;
String ^strGop;
strWidth=width1->Text;
[Code]....
In the below function, it muliplies "10.0 * val". Why does it use 10.0? If you remove the 10.0, the return value will still be a double.
#include <ctype.h>
/* atof: convert string s to double */
double atof(char s[])
{
[Code]....
I would like to convert the string without losing the decimal part and obtaining the same accuracy... This is my code:
#include "stdafx.h"
#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
using namespace std;
int _tmain(int argc, char* argv[]){
string param = "1.65";
double L3;
L3=atof(param.c_str());
}
If I use atoi L3 = 1.00000; and if I use atof L3 = 1.6499999999;
Because MinGW C++ doesn't have the atod() or atoi() functions for some reason, I had to code a string to double function myself.
double stringToDouble(std::string input) {
bool isDecimal;
int decimalLoc;
double output = 0;
double n;
[Code] ....
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
Take this string for an example, "asdf 9.000 1.232 9.00 23.1 545.3"..Is there a way to replace any of the doubles with another double? Example: Replace the first "9.000" with a "10.0". I am aware that string::replace will do the trick, but how do I make it work for arbitrary cases? By arbitrary I mean that I don't know the size of the string to be replaced, I just want to be able to replace any number with a given number.
View 1 Replies View RelatedI have a problem with converting a C++ string into a long double. In order to do this, I used the function strtold, but the result I get is only the integral part, that is: if for example the input string is 12.476, I only get 12 as the converted long double value. This happens with atof too.
Here is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <sstream>
string test = "12.345";
long double test_longd = strtold(test.c_str(),NULL);
[Code] .....
I am having a lot of trouble extracting values from a string into a double array.
I have a string that looks something like this: "asdf 1.320 1 234.43 5.00000 3"
All I want to do is extract the doubles and store them in an array of doubles.
I know how to find the occurrences of a character in a string, but I have a more specific problem.
For example, consider the string:
" C 1.3825 4.0000 12.0000 1.9133 0.1853 0.9000 -1.1359 4.0000 "
I want to extract a vector that contains the positions of every first character for each number.
For the example above, the output should be a vector with elements [6 15 23 33 etc...]. These are the positions of the first character for every number.
I need to be able to do this for any arbitrary string with any arbitrary amount of numbers and characters in it (I also need to account for negative numbers).
So I have problem with my code, I'm trying to convert string to long and then string to double, but I get this when I compile it:
terminating with uncaught exception of type std::invalid_argument: stod: no conversion
I was thinking if there is a way to do this without using (stol) or (stod)
Market::Market(string filename)
{
string line, word, date, stockprice;
long realdate;
[Code].....
I have the following piece of code:
string ss = findNodeValue( str, "Horizon");
cout << "ss is: " << ss << endl;
double dd = atof( ss.c_str());
cout << "dd is: " << dd << endl;
When the value of 'ss' is printed, I find it prints 1.0, but when the value of 'dd' is printed, it prints 1 whereas it is supposed to print 1.0.
I have to convert string to double. i'm using "atof" function to achieve same.
I have string as "0.0409434228722337" and i'm converting with "atof" But i'm getting double value as "0.040943422872233702". Why it adds 02 additionally at the end?
More example :
"0.0409434228722337" converts to "0.040943422872233702"
"0.067187778121134" converts to "0.067187778121133995"
Is there any other possibility to convert string to double without changing data ?
I have a function:
const void insertStuff(const void *key, const int value){
// I want to convert the void pointer into one
// of three types of pointers(int, string, or double)
switch(value){
case 0:
int *intPtr = key;
[Code] .....
But this causes an error of: "crosses initialization of int*intPtr"
What's the correct way of implementing this?
#include<iostream>
using namespace std;
int main() {
double x,i;
cout<<"Enter the value of the number
[Code] ....
why I am not getting exact square root if I take x as double,but if I am taking it as int I got the correct result.
I am very new to programming and would like to know where to even start when evaluating a double integral. I wanted to evaluate this double integral: 6x^3 + y^2 +7x from 0 to 1 (for both).
View 1 Replies View RelatedGiven this code
Code:
double x=1.00,y=2,z=4;
if (y/z||++x)
x+=y/z;
printf("%f
",x); So (y/z||++x)
is true if at least one expression is true, that is either (y/z)!=0 or (++x)!=0 or both. I wonder how the comparison is done? Is (y/z) be truncated to integer or 0 be promoted to double?
I'm having a small issue here with my linked list.I built a linked list with strings and it worked perfectly.Now since i'm using strtok() to separate the string.for now here's what i've got:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct dict_word *word;
typedef struct node *Node;
typedef struct double_linked_list *DLL;
}
[code]....
The main is not working properly, I get strange missing parenthesis notices and array errors which I am not understanding. How to identify the errors. Functions are included.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int menu ();
double change_value (double * value);
[Code] ......
this is what I got so far
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
[Code].....
he problem is that when I print out the three sums at the end of the program I dont get any decimal points but just zeros like something.00 instead of something.50 etc
