In the below function, it muliplies "10.0 * val". Why does it use 10.0? If you remove the 10.0, the return value will still be a double.
#include <ctype.h>
/* atof: convert string s to double */
double atof(char s[])
{
[Code]....
I want to convert string to double. I refered this strtod() - C Library Function Example
Code:
#include <stdio.h>
#include <string.h>
int main() {
const char string[] = "$$GPRMC,013732.000,A,3150.7238,N,11711.7278,E,0.00,0.00,220413,,,A*68";
char term;
const char delims[] = ",";
}
[code]....
I have to convert string to double. i'm using "atof" function to achieve same.
I have string as "0.0409434228722337" and i'm converting with "atof" But i'm getting double value as "0.040943422872233702". Why it adds 02 additionally at the end?
More example :
"0.0409434228722337" converts to "0.040943422872233702"
"0.067187778121134" converts to "0.067187778121133995"
Is there any other possibility to convert string to double without changing data ?
I have a function:
const void insertStuff(const void *key, const int value){
// I want to convert the void pointer into one
// of three types of pointers(int, string, or double)
switch(value){
case 0:
int *intPtr = key;
[Code] .....
But this causes an error of: "crosses initialization of int*intPtr"
What's the correct way of implementing this?
How to convert char array into double?,i.e. store char array values into a single double variable. Below is the code that i'm working. Im extracting the value "2255.1682" from char array gpsdata1. I used while loop, extracted the value and stored in "myChar", but i want to store it in double variable "lat1".
Code:
#include <stdio.h>
#include <stdlib.h>
int main(){
unsigned char gpsdata1[]="$GPGGA,091310.000,2255.1682,N,11356.3605,E,1,4,1.62,164";
char myChar;
double lat1;
[Code] .....
So I'm trying to run this program and I get 2 errors:
error C2078: too many initializers & error C2440: 'initializing' : cannot convert from 'double' to 'CStock'
Seems to have something to do with "no suitable constructor exists to convert from "const char[5]" to "CStock".
Stock.h:
#ifndef Stock_h
#define Stock_h
#include <string>
using namespace std;
class CStock {
public:
static string Company;
static string Symbol;
[Code] ....
I receive a byte stream. The first 8 bytes contain an Identification number. I receive at first the lowest byte and at the end the highest byte of the number. How can I transform this into a double value and later back into the bytestream? In the past I hard only 2 Byte values and there I could use things like MAKEWORD and HIBYTE and LOWBYTE to convert the values
View 4 Replies View RelatedMy goal is to read a one line file of a comma separated numbers into a floating point array. The numbers have up to 25 positions after the decimal. I'm having two issues with the following code.
1) atof() seems to be returning zeros every time. Why?
2) The last number includes the new line character. How do I get rid of it?
Note that I adapted the scanf command from here: The power of scanf() - [URL], and don't completely understand it.
Code:
#include <stdio.h>
#include <math.h>
//The following will be calculated in the real program.
#define DIM 1
#define N 8
int main()
[Code]......
In the "real" program, N is calculated and known before reading in the file and the file will always have 2 times N numbers.
So imagine you have this string:
"somedata here "some data here" some more data here"
I need to parse this:
somedata here "some data here" some more data here
I tried to do it with Regex and was capable of parsing
[0] = somedata here
[1] = some data here
[2] = some more data here
Here is my current code:
string Buffer = string.Empty;
foreach (Match match in Regex.Matches(strLine, "".*?""))
Buffer = match.ToString();
How to add double quotes into string.I want to prepare command into following way with string.
awk 'BEGIN {printf "x
%10s %10s
", "Vol", "Current"}{if($1+0==$1){printf "%10.5f %10.5f
", $2, $3}} END {printf "y
"}'
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
View 1 Replies View Relatedi think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width;
int height;
int area;
double gop;
String ^strWidth;
String ^strHeight;
String ^strArea;
String ^strGop;
strWidth=width1->Text;
[Code]....
I would like to convert the string without losing the decimal part and obtaining the same accuracy... This is my code:
#include "stdafx.h"
#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
using namespace std;
int _tmain(int argc, char* argv[]){
string param = "1.65";
double L3;
L3=atof(param.c_str());
}
If I use atoi L3 = 1.00000; and if I use atof L3 = 1.6499999999;
Because MinGW C++ doesn't have the atod() or atoi() functions for some reason, I had to code a string to double function myself.
double stringToDouble(std::string input) {
bool isDecimal;
int decimalLoc;
double output = 0;
double n;
[Code] ....
Ok, so I'm writing this code and when I build it keeps saying cannot implicitely convert type int to string even though I declared my variables as string. Why is it giving me this error?
private static string Repair()
{
string result="";
string beep;
string spin;
Console.WriteLine("Does your computer beep on startup?:(y,n)");
[Code]...
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
Take this string for an example, "asdf 9.000 1.232 9.00 23.1 545.3"..Is there a way to replace any of the doubles with another double? Example: Replace the first "9.000" with a "10.0". I am aware that string::replace will do the trick, but how do I make it work for arbitrary cases? By arbitrary I mean that I don't know the size of the string to be replaced, I just want to be able to replace any number with a given number.
View 1 Replies View RelatedI have a problem with converting a C++ string into a long double. In order to do this, I used the function strtold, but the result I get is only the integral part, that is: if for example the input string is 12.476, I only get 12 as the converted long double value. This happens with atof too.
Here is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <sstream>
string test = "12.345";
long double test_longd = strtold(test.c_str(),NULL);
[Code] .....
I am having a lot of trouble extracting values from a string into a double array.
I have a string that looks something like this: "asdf 1.320 1 234.43 5.00000 3"
All I want to do is extract the doubles and store them in an array of doubles.
I know how to find the occurrences of a character in a string, but I have a more specific problem.
For example, consider the string:
" C 1.3825 4.0000 12.0000 1.9133 0.1853 0.9000 -1.1359 4.0000 "
I want to extract a vector that contains the positions of every first character for each number.
For the example above, the output should be a vector with elements [6 15 23 33 etc...]. These are the positions of the first character for every number.
I need to be able to do this for any arbitrary string with any arbitrary amount of numbers and characters in it (I also need to account for negative numbers).
So I have problem with my code, I'm trying to convert string to long and then string to double, but I get this when I compile it:
terminating with uncaught exception of type std::invalid_argument: stod: no conversion
I was thinking if there is a way to do this without using (stol) or (stod)
Market::Market(string filename)
{
string line, word, date, stockprice;
long realdate;
[Code].....
I have the following piece of code:
string ss = findNodeValue( str, "Horizon");
cout << "ss is: " << ss << endl;
double dd = atof( ss.c_str());
cout << "dd is: " << dd << endl;
When the value of 'ss' is printed, I find it prints 1.0, but when the value of 'dd' is printed, it prints 1 whereas it is supposed to print 1.0.
heres the function:
string ToString ( const char * format, ... )
{
char buffer[256];
[Code]....
these function do the same of the sprintf() function. but instead we use a variable for add the result, i want to return the result. when i use it:
string f;
f=ToString("hello world");
gives me several errors:
"error: crosses initialization of 'std::string f'"
"error: jump to case label [-fpermissive]"
I am using Visual Studio 2008. I just wonder if there are any library function in Windows SDK or MFC, or from third-parties, that can convert a UTF-8 string into Windows Unicode string(used in CString object).
Can MultiByteToWideChar or ATL String conversion macro like A2W to the conversion?
I would like to convert a value into a string, and extract a value from a string. And then call these functions in the main.
template<class T>
string toString (T value) // convert a value into a string {
stringstream ss;
[Code[ .....
Are above functions correct? And how should I call in main?
int main() {
const int SIZE=10;
toString<int> intValue(SIZE); //seems not right
toString<double> doubleValue(SIZE); // seems not right
}
I've got this string: Code: char * string = "2+2"; I want to get an integer value = 4 from this. How would I go about doing this.
View 1 Replies View Related