I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
i think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width; int height; int area; double gop; String ^strWidth; String ^strHeight; String ^strArea; String ^strGop; strWidth=width1->Text;
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() { char* str = new char[30]; float flt = 2.4567F; sprintf(str, "%.4g", flt ); cout<<str<<endl; //Exponential form even after 6 digits without decimal return 0; }
Take this string for an example, "asdf 9.000 1.232 9.00 23.1 545.3"..Is there a way to replace any of the doubles with another double? Example: Replace the first "9.000" with a "10.0". I am aware that string::replace will do the trick, but how do I make it work for arbitrary cases? By arbitrary I mean that I don't know the size of the string to be replaced, I just want to be able to replace any number with a given number.
I have a problem with converting a C++ string into a long double. In order to do this, I used the function strtold, but the result I get is only the integral part, that is: if for example the input string is 12.476, I only get 12 as the converted long double value. This happens with atof too.
Here is my code:
#include <stdio.h> #include <stdlib.h> #include <string> #include <sstream> string test = "12.345"; long double test_longd = strtold(test.c_str(),NULL);
I know how to find the occurrences of a character in a string, but I have a more specific problem.
For example, consider the string: " C 1.3825 4.0000 12.0000 1.9133 0.1853 0.9000 -1.1359 4.0000 "
I want to extract a vector that contains the positions of every first character for each number.
For the example above, the output should be a vector with elements [6 15 23 33 etc...]. These are the positions of the first character for every number.
I need to be able to do this for any arbitrary string with any arbitrary amount of numbers and characters in it (I also need to account for negative numbers).
I have to convert string to double. i'm using "atof" function to achieve same.
I have string as "0.0409434228722337" and i'm converting with "atof" But i'm getting double value as "0.040943422872233702". Why it adds 02 additionally at the end?
More example :
"0.0409434228722337" converts to "0.040943422872233702" "0.067187778121134" converts to "0.067187778121133995"
Is there any other possibility to convert string to double without changing data ?
I see that the function itself does not return anything but calls another function. The main difficulty I have is with the "dev->dev->" operator, where dev, I expect is a pointer to a structure.
I have int pointer called p and i want to calculate average.Since average involves using double or float so i am trying to convert this in the function averagetemp. It still gives me an error saying "cannot be converted"...
#include <iostream> using namespace std; int* createArray(int n); int lowesttemp(int *p,int f); int highesttemp(int *p,int f); double averagetemp(int *k,double f); void print(int *p,int lowest_temp,int highesttemp,int average_temp);
I need to write a function that will merge the content of two sorted arrays of type double values. The function should not assume that both its input parameter arrays are the same length.
Here is my program so far - I know there is alot of errors and mistakes:
const void insertStuff(const void *key, const int value){ // I want to convert the void pointer into one // of three types of pointers(int, string, or double) switch(value){ case 0: int *intPtr = key;
[Code] .....
But this causes an error of: "crosses initialization of int*intPtr"
How would I call a string that sits within a switch loop in the main function, into a separate function?
Like this:
void statistics() { cout << "Here are the statistics for your entry: " << endl; cout << " The size of your entry is " << s.length() << " characters." << endl; }
I am calling string s from this:
switch (toupper(myChoice)) { case 'A': cin.ignore(); cout <<" Please enter your text: "; getline(cin, s);
I am new to C, but I recently completed an exercise from a book that finds a string in another string, removes the string, and replaces it with another string.