Because MinGW C++ doesn't have the atod() or atoi() functions for some reason, I had to code a string to double function myself.
double stringToDouble(std::string input) {
bool isDecimal;
int decimalLoc;
double output = 0;
double n;
[Code] ....
So imagine you have this string:
"somedata here "some data here" some more data here"
I need to parse this:
somedata here "some data here" some more data here
I tried to do it with Regex and was capable of parsing
[0] = somedata here
[1] = some data here
[2] = some more data here
Here is my current code:
string Buffer = string.Empty;
foreach (Match match in Regex.Matches(strLine, "".*?""))
Buffer = match.ToString();
I want to convert string to double. I refered this strtod() - C Library Function Example
Code:
#include <stdio.h>
#include <string.h>
int main() {
const char string[] = "$$GPRMC,013732.000,A,3150.7238,N,11711.7278,E,0.00,0.00,220413,,,A*68";
char term;
const char delims[] = ",";
}
[code]....
How to add double quotes into string.I want to prepare command into following way with string.
awk 'BEGIN {printf "x
%10s %10s
", "Vol", "Current"}{if($1+0==$1){printf "%10.5f %10.5f
", $2, $3}} END {printf "y
"}'
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
View 1 Replies View Relatedi think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width;
int height;
int area;
double gop;
String ^strWidth;
String ^strHeight;
String ^strArea;
String ^strGop;
strWidth=width1->Text;
[Code]....
In the below function, it muliplies "10.0 * val". Why does it use 10.0? If you remove the 10.0, the return value will still be a double.
#include <ctype.h>
/* atof: convert string s to double */
double atof(char s[])
{
[Code]....
I would like to convert the string without losing the decimal part and obtaining the same accuracy... This is my code:
#include "stdafx.h"
#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
using namespace std;
int _tmain(int argc, char* argv[]){
string param = "1.65";
double L3;
L3=atof(param.c_str());
}
If I use atoi L3 = 1.00000; and if I use atof L3 = 1.6499999999;
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
Take this string for an example, "asdf 9.000 1.232 9.00 23.1 545.3"..Is there a way to replace any of the doubles with another double? Example: Replace the first "9.000" with a "10.0". I am aware that string::replace will do the trick, but how do I make it work for arbitrary cases? By arbitrary I mean that I don't know the size of the string to be replaced, I just want to be able to replace any number with a given number.
View 1 Replies View RelatedI have a problem with converting a C++ string into a long double. In order to do this, I used the function strtold, but the result I get is only the integral part, that is: if for example the input string is 12.476, I only get 12 as the converted long double value. This happens with atof too.
Here is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <sstream>
string test = "12.345";
long double test_longd = strtold(test.c_str(),NULL);
[Code] .....
I am having a lot of trouble extracting values from a string into a double array.
I have a string that looks something like this: "asdf 1.320 1 234.43 5.00000 3"
All I want to do is extract the doubles and store them in an array of doubles.
I know how to find the occurrences of a character in a string, but I have a more specific problem.
For example, consider the string:
" C 1.3825 4.0000 12.0000 1.9133 0.1853 0.9000 -1.1359 4.0000 "
I want to extract a vector that contains the positions of every first character for each number.
For the example above, the output should be a vector with elements [6 15 23 33 etc...]. These are the positions of the first character for every number.
I need to be able to do this for any arbitrary string with any arbitrary amount of numbers and characters in it (I also need to account for negative numbers).
So I have problem with my code, I'm trying to convert string to long and then string to double, but I get this when I compile it:
terminating with uncaught exception of type std::invalid_argument: stod: no conversion
I was thinking if there is a way to do this without using (stol) or (stod)
Market::Market(string filename)
{
string line, word, date, stockprice;
long realdate;
[Code].....
I have the following piece of code:
string ss = findNodeValue( str, "Horizon");
cout << "ss is: " << ss << endl;
double dd = atof( ss.c_str());
cout << "dd is: " << dd << endl;
When the value of 'ss' is printed, I find it prints 1.0, but when the value of 'dd' is printed, it prints 1 whereas it is supposed to print 1.0.
I have to convert string to double. i'm using "atof" function to achieve same.
I have string as "0.0409434228722337" and i'm converting with "atof" But i'm getting double value as "0.040943422872233702". Why it adds 02 additionally at the end?
More example :
"0.0409434228722337" converts to "0.040943422872233702"
"0.067187778121134" converts to "0.067187778121133995"
Is there any other possibility to convert string to double without changing data ?
I have recently come across a function call that I do not understand. It uses the arrow operator for a function call, twice, and I don't understand.
Code:
static inline void b43_write32(struct b43_wldev *dev, u16 offset, u32 value)
{
dev->dev->write32(dev->dev, offset, value);
}
I see that the function itself does not return anything but calls another function. The main difficulty I have is with the "dev->dev->" operator, where dev, I expect is a pointer to a structure.
I have int pointer called p and i want to calculate average.Since average involves using double or float so i am trying to convert this in the function averagetemp. It still gives me an error saying "cannot be converted"...
#include <iostream>
using namespace std;
int* createArray(int n);
int lowesttemp(int *p,int f);
int highesttemp(int *p,int f);
double averagetemp(int *k,double f);
void print(int *p,int lowest_temp,int highesttemp,int average_temp);
[Code] ....
ok here is the question: Write a function that will initialize a double data array element to 0.0 ?
View 4 Replies View RelatedI have two listboxes and what I would like to do is use the double click function to copy what is clicked in listbox1 to listbox2.
I would also like it so if anything else is clicked in listbox1 it is added below the previous clicked item in listbox2.
I need to write a function that will merge the content of two sorted arrays of type double values. The function should not assume that both its input parameter arrays are the same length.
Here is my program so far - I know there is alot of errors and mistakes:
Code:
#include<stdio.h>
void merge(int firstArray[],int secondArray[],int size) {
int mergedArray[size],i=0,j=0,k=0;
while(i<size||j<size) {
if(i==size) {
[Code]...
I have a function:
const void insertStuff(const void *key, const int value){
// I want to convert the void pointer into one
// of three types of pointers(int, string, or double)
switch(value){
case 0:
int *intPtr = key;
[Code] .....
But this causes an error of: "crosses initialization of int*intPtr"
What's the correct way of implementing this?
How would I call a string that sits within a switch loop in the main function, into a separate function?
Like this:
void statistics() {
cout << "Here are the statistics for your entry: " << endl;
cout << "
The size of your entry is " << s.length() << " characters." << endl;
}
I am calling string s from this:
switch (toupper(myChoice)) {
case 'A': cin.ignore();
cout <<"
Please enter your text: ";
getline(cin, s);
[Code] ....
How can I pass the name from the user input to the constructor ?
Code:
#include <iostream>
#include <string>
using namespace std;
class myClass {
[Code]....
I am new to C, but I recently completed an exercise from a book that finds a string in another string, removes the string, and replaces it with another string.
Code:
// Replace String
#include <stdio.h>
#include <stdbool.h>
bool replaceString (char source[], char s1[], char s2[])
}
[code]....
I need a function to return a string..i need to pass input as "a,b,c,a,c,d,e" function should return out put as "a,b,c,d,e".
View 3 Replies View Related