So im trying to parse a string into a Ip Address but i have a problem, the IPAddress.Parse method only works for ipv4 address's how do i parse ANY Ip address into a string, if i use the IPaddress.Parse method on my public(remote) IP it throws an exception but on ipv4 local ip it doesn't how do i parse ANY ip address the user inputs as a string as an Ip Address?
I have been here for almost 3 months looking for answers in my C++ problems.here's some type of code for this.
cout << "Enter value of x: " << endl; //Let's say 5. cin >> x; cout << "Enter equation: "; //Let's say x+1 cin >> equation;
Then the program analyzes that this character "x" has an initial value of 5.I already have the parser for the equation functions (+,-,*,/)This is the only thing lacking. Is there some type of function that i missed?
I have an input file that contains any number of lines. Each line will follow the same structure. There will be 5 fields, separated by 4 commas. Fields 1 and 3 will be single characters, fields 2,4,5 will be integers. Example:
<A, 123, B, 456, 789>
I need to iterate over each line, parse out the fields, and capture each field value into a separate variables.
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
i think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width; int height; int area; double gop; String ^strWidth; String ^strHeight; String ^strArea; String ^strGop; strWidth=width1->Text;
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() { char* str = new char[30]; float flt = 2.4567F; sprintf(str, "%.4g", flt ); cout<<str<<endl; //Exponential form even after 6 digits without decimal return 0; }
Take this string for an example, "asdf 9.000 1.232 9.00 23.1 545.3"..Is there a way to replace any of the doubles with another double? Example: Replace the first "9.000" with a "10.0". I am aware that string::replace will do the trick, but how do I make it work for arbitrary cases? By arbitrary I mean that I don't know the size of the string to be replaced, I just want to be able to replace any number with a given number.
I have a problem with converting a C++ string into a long double. In order to do this, I used the function strtold, but the result I get is only the integral part, that is: if for example the input string is 12.476, I only get 12 as the converted long double value. This happens with atof too.
Here is my code:
#include <stdio.h> #include <stdlib.h> #include <string> #include <sstream> string test = "12.345"; long double test_longd = strtold(test.c_str(),NULL);
I know how to find the occurrences of a character in a string, but I have a more specific problem.
For example, consider the string: " C 1.3825 4.0000 12.0000 1.9133 0.1853 0.9000 -1.1359 4.0000 "
I want to extract a vector that contains the positions of every first character for each number.
For the example above, the output should be a vector with elements [6 15 23 33 etc...]. These are the positions of the first character for every number.
I need to be able to do this for any arbitrary string with any arbitrary amount of numbers and characters in it (I also need to account for negative numbers).
I am parsing a binary data file by casting a buffer to a struct. It seems to work really well apart from this one double which is always being accessed two bytes off, despite being in the correct place.
If I attempt to print GROSS using printf("%f", row->GROSS) I get 0.0000. However, if I change the type of GROSS to char[8] and then use the following code, I am presented with the correct number...
Code:
typedef struct example { double d; }
example; example *blah = (example*)row->GROSS; printf("%f", blah->d);
I have to convert string to double. i'm using "atof" function to achieve same.
I have string as "0.0409434228722337" and i'm converting with "atof" But i'm getting double value as "0.040943422872233702". Why it adds 02 additionally at the end?
More example :
"0.0409434228722337" converts to "0.040943422872233702" "0.067187778121134" converts to "0.067187778121133995"
Is there any other possibility to convert string to double without changing data ?
const void insertStuff(const void *key, const int value){ // I want to convert the void pointer into one // of three types of pointers(int, string, or double) switch(value){ case 0: int *intPtr = key;
[Code] .....
But this causes an error of: "crosses initialization of int*intPtr"
What is the efficiency of the two assignments (line 1 and 2), i.e. (function calls, number of copies made, etc), also the Big O notation. I know there are function calls for retrieving the size of each string in order to produce a new buffer for the concatenated string...any difference between line 1 and 2 in terms of efficiency?
String s("Hello"); String t("There"); 1. s = s + t; 2. s += t;