I would like to convert the string without losing the decimal part and obtaining the same accuracy... This is my code:
#include "stdafx.h"
#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
using namespace std;
int _tmain(int argc, char* argv[]){
string param = "1.65";
double L3;
L3=atof(param.c_str());
}
If I use atoi L3 = 1.00000; and if I use atof L3 = 1.6499999999;
So imagine you have this string:
"somedata here "some data here" some more data here"
I need to parse this:
somedata here "some data here" some more data here
I tried to do it with Regex and was capable of parsing
[0] = somedata here
[1] = some data here
[2] = some more data here
Here is my current code:
string Buffer = string.Empty;
foreach (Match match in Regex.Matches(strLine, "".*?""))
Buffer = match.ToString();
I want to convert string to double. I refered this strtod() - C Library Function Example
Code:
#include <stdio.h>
#include <string.h>
int main() {
const char string[] = "$$GPRMC,013732.000,A,3150.7238,N,11711.7278,E,0.00,0.00,220413,,,A*68";
char term;
const char delims[] = ",";
}
[code]....
How to add double quotes into string.I want to prepare command into following way with string.
awk 'BEGIN {printf "x
%10s %10s
", "Vol", "Current"}{if($1+0==$1){printf "%10.5f %10.5f
", $2, $3}} END {printf "y
"}'
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
View 1 Replies View Relatedi think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width;
int height;
int area;
double gop;
String ^strWidth;
String ^strHeight;
String ^strArea;
String ^strGop;
strWidth=width1->Text;
[Code]....
In the below function, it muliplies "10.0 * val". Why does it use 10.0? If you remove the 10.0, the return value will still be a double.
#include <ctype.h>
/* atof: convert string s to double */
double atof(char s[])
{
[Code]....
Because MinGW C++ doesn't have the atod() or atoi() functions for some reason, I had to code a string to double function myself.
double stringToDouble(std::string input) {
bool isDecimal;
int decimalLoc;
double output = 0;
double n;
[Code] ....
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
Take this string for an example, "asdf 9.000 1.232 9.00 23.1 545.3"..Is there a way to replace any of the doubles with another double? Example: Replace the first "9.000" with a "10.0". I am aware that string::replace will do the trick, but how do I make it work for arbitrary cases? By arbitrary I mean that I don't know the size of the string to be replaced, I just want to be able to replace any number with a given number.
View 1 Replies View RelatedI have a problem with converting a C++ string into a long double. In order to do this, I used the function strtold, but the result I get is only the integral part, that is: if for example the input string is 12.476, I only get 12 as the converted long double value. This happens with atof too.
Here is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <sstream>
string test = "12.345";
long double test_longd = strtold(test.c_str(),NULL);
[Code] .....
I am having a lot of trouble extracting values from a string into a double array.
I have a string that looks something like this: "asdf 1.320 1 234.43 5.00000 3"
All I want to do is extract the doubles and store them in an array of doubles.
I know how to find the occurrences of a character in a string, but I have a more specific problem.
For example, consider the string:
" C 1.3825 4.0000 12.0000 1.9133 0.1853 0.9000 -1.1359 4.0000 "
I want to extract a vector that contains the positions of every first character for each number.
For the example above, the output should be a vector with elements [6 15 23 33 etc...]. These are the positions of the first character for every number.
I need to be able to do this for any arbitrary string with any arbitrary amount of numbers and characters in it (I also need to account for negative numbers).
So I have problem with my code, I'm trying to convert string to long and then string to double, but I get this when I compile it:
terminating with uncaught exception of type std::invalid_argument: stod: no conversion
I was thinking if there is a way to do this without using (stol) or (stod)
Market::Market(string filename)
{
string line, word, date, stockprice;
long realdate;
[Code].....
I have the following piece of code:
string ss = findNodeValue( str, "Horizon");
cout << "ss is: " << ss << endl;
double dd = atof( ss.c_str());
cout << "dd is: " << dd << endl;
When the value of 'ss' is printed, I find it prints 1.0, but when the value of 'dd' is printed, it prints 1 whereas it is supposed to print 1.0.
i have seen many example for to get the data from wmi using c++. will it work on turbo c++ or vc++. if it is written in vc++ means could we develop the same concept using c++?
Note: the link that i have seen the example [url="hi, i have seen many example for to get the data from wmi using c++. will it work on turbo c++ or vc++. if it is written in vc++ means could we develop the same concept using c++? Note: the link that i have seen the example[URL]
I have to convert string to double. i'm using "atof" function to achieve same.
I have string as "0.0409434228722337" and i'm converting with "atof" But i'm getting double value as "0.040943422872233702". Why it adds 02 additionally at the end?
More example :
"0.0409434228722337" converts to "0.040943422872233702"
"0.067187778121134" converts to "0.067187778121133995"
Is there any other possibility to convert string to double without changing data ?
How can I obtain the length of an array that has been sent throughout a function. In the following code, I obtain "2" as output, while I was expecting "5".
void call(int a[]) {
cout<<sizeof(a)/sizeof(int);
}
int main() {
int* a=new int[5];
call(a);
}
How can I properly call this function so I can obtain the correct array size?
I am trying to use fscanf to obtain a set of 14 or so strings per line, in a line where there are around 80 or so different sets of strings. I only need the first 14 and whenever I call scan f it starts at column 209 as opposed to column 1 where it should. Here's a sample of the code:
FILE *d;
d=fopen("t.dat","rb");
where a, n are all strings.
fscanf(d,"%s %s %s %s %s %s %s %s %s %s %s %s %s %s",&a,&b,&c,..(etc)..,&n);
A sample of the Input file looks like this:
USB270.15385-29.63146 270.153847 -29.631455 2.966699e+03 -9.99 1.300391e+03 -9.99 -9.99 A-A-- 6.787463e+01 -9.99 1.555773e+02 -9.99 -9.99 10100 | ----- ------ ------ ------ | 0.373 13.554 12.928 12.670 AAA | ----- -------- - -------- - -------- - -------- - | --- ---------- - ---------- - --------- - --------- - --------- - ---------- -
I was just reviewing some code, and my eye fell on a bit of regex that's intended to parse a date/time stamp into a date and time.
The timestamp uses shorted month names. The regex had all the possible month names to match the entire pattern. If it does, it went through a 2Nd loop to convert the month name into a 1 to 12 numeric value...
This made me wonder, since the regex is already doing the work to verify the alternation, can't it at the same time tell me which of the possible alternations it matched and use that to calculate the numeric value. So basically
Code:
std::regex reMonth("Some more regex stuff here (Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec).");
CString strTest("Some more regex stuff here Aug.");
std::cmatch res;
if (std::regex_match(strTest.GetString(), res, reMonth)) {
//int iMonthNum = res[1].something(); // some code here that returns 8 for Aug.
}
Or is there really no other way out than doing a 2nd level verification to figure out the actual month number. (The real regex is a bit more complex than this).
I'm using SQLBulkOperations to insert rows in bulk. I'm using SQLBindCol to bind the columns before SQLBulkOperations().
But how do I obtain the Identities? The bound buffer for the Identity column does not get filled after SQLBulkOperations()
At first I tried to use Bookmarks (column 0), but it seems that that is some other value (thought it would be filled with identities). But now I thought it must be that the bound buffer for the Identity column itself must be updated, but it's not happening. Maybe I need to do something extra?
I have to obtain a check number from a datafile and then also get company information also from a datafile.
So my first question is about the:
Code:
char outputFilename[]= "out.list"
Is this the name of the output file I'm going to write to? And also the file has to be created before being used...is that line of code creating the file or do i have to create it in notepad?
Code:
FILE *ifp, *ofp;
char *mode = "r";
char outputFilename[] = "out.list";
ifp = fopen("in.list", mode);
if (ifp == NULL) {
fprintf(stderr, "Can't open input file in.list!
[Code] .....
I am facing a problem which i could not obtain the total numbers which is greater than the average value. For example:
#include <iostream>
using namespace std;
int main (){
int size , count;
double no, max, min ,total, sum , average;
[Code] ....
In this case im able to compute the average of the numbers but when it comes to capture the total of numbers which is greater than the average value, how to compile the code , because the average number is only been compute once all the value capture by the input of user is sum up.
I have a function:
const void insertStuff(const void *key, const int value){
// I want to convert the void pointer into one
// of three types of pointers(int, string, or double)
switch(value){
case 0:
int *intPtr = key;
[Code] .....
But this causes an error of: "crosses initialization of int*intPtr"
What's the correct way of implementing this?
#include<iostream>
using namespace std;
int main() {
double x,i;
cout<<"Enter the value of the number
[Code] ....
why I am not getting exact square root if I take x as double,but if I am taking it as int I got the correct result.
I am very new to programming and would like to know where to even start when evaluating a double integral. I wanted to evaluate this double integral: 6x^3 + y^2 +7x from 0 to 1 (for both).
View 1 Replies View Related