I am very new to programming and would like to know where to even start when evaluating a double integral. I wanted to evaluate this double integral: 6x^3 + y^2 +7x from 0 to 1 (for both).
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One of my last programs to write was to use the trapezoidal rule to approx. the definite integral defined in the program. It works, now i am looking for ways to improve this code, if there are any.
Code:
#include<stdlib.h>#include<stdio.h>
#include<math.h>
double integral (double x);
int main(void){
[Code] ....
the output is simple:
Code: ssma-imac:ENG-3211 ssma$ ./integralThe integral of x^2 Sin(x) dx from 1 to 5 is -18.953841
And yes this is a very good approximation of the actual integral.
I have a function written to calculate an integral using rectangles. I get this error: 'cannot convert double to double (*) (double) in assignment'. But whenever I remove one of the doubles something is undeclared.
double rect_integral(double a, double b, int n, int f) {
double x;
double (* fx) (double);
double func_1 = 5*(pow(x,4))+3*(pow(x,2))-10*(x)+2;
double func_2 = pow(x,2)-10;
[Code] .....
I've been having a problem concerning the initialization of const static integral members with floating point calculations. I'll let his sample program do the explaining:
class Foo {
public :
Foo() {}
const static int samplerate = 44100;
const static unsigned short tempo = 120;
[Code].....
I know you can't initialize const static non-integral types on the same line on which they're declared, but I don't see why even an implicit cast to an integral type should be disallowed. I make my calculations using doubles, so I'm surprised that even though it should degenerate into an integer - it's still a problem for the compiler.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
//chose to use #define since columns/rows are a constant in the program
#define x 5
#define y 3
int main() {
//declare variables
[code]....
I've been studying the heck out of the boost metafunction libraries. I understand a good deal of what things like varadic functions and integral sequence wrappers are, but I am having a hard time putting everything together to get working functions, such as performing arithmetic operations or functions like that of std::vector.
Here is an example of what I'm talking about:
// Sequences
template<typename T... N> struct seq;
template<typename T, T... N> struct seq_c;
// Integral constant wrapper
template<int T> struct int_
[Code] .....
My knowledge of all of this is pretty scattered and I've really been trying hard to put it all together. Is this correct? How can I apply this and use it to do more?
So far I have the following code:
// Purpose: To write a program that displays the number of millimeters higher the current level the ocean level will be in
// in 5, 7, and 10 years.
# include <iostream>
# include <string>
using namespace std;
int main() {
float X = 10;
string Y="";
[Code] ....
But I get the following error message:
IntelliSense: expession must have integral or unscoped enum type
three times in a row for lines 25, 27, and 29 and I don't understand or know why?
In case the purpose does make sense here are the directions:
2.7: Ocean Levels
Assuming the ocean’s level is currently rising at about 1.5 millimeters per year, write a program that displays
•The number of millimeters higher than the current level that the ocean’s level will be in 5 years,
•The number of millimeters higher than the current level that the ocean’s level will be in 7 years,
•The number of millimeters higher than the current level that the ocean’s level will be in 10 years,
Output labels:
Each value should be on a line by itself, preceded by the a label of the form:
In X years the ocean's level will be higher by Y millimeters.
where X is the number of years (5, 7 or 10) and Y is the value you calculate.
Can I use Shunting-yard algorithm to evaluate Expressions (arithmetic, relational, and logical) ?
View 8 Replies View RelatedHow to remake the code that i`ve written to have : a recursive function to evaluate the first n terms in series specified y= 1 - x + x^2/2 - x^3/6 + x^4/24 +....+(-1)^n x^n/n!
And this is my code:
#include <iostream>
using namespace std;
double power(int n, double x) {
double d =1;
for (int i = 1 ; i<=n ; i++)
[Code] ....
The program must evaluate the truth value of the conjunction, disjunction, and implication of each value row. For each logical operator, P is the argument to the left of the operator and Q is to the right.
For conjunction: P ^ Q, disjunction: P _ Q, and implication: P ! Q.
Example prog2 input.txt
P Q
T T
T F
F F
For each value row the program must output a corresponding row, in the following format:
P and Q:<T or F> ntP or Q:<T or F> ntP --> Q:<T or F> For the example input given above
the output is found below.
Example prog2 output.txt
P and Q : T P or Q : T P --> Q : T
P and Q : F P or Q : T P --> Q : F
P and Q : F P or Q : F P --> Q : T
.
This is what I did so far
# include<iostream>
#include<fstream>
using namespace std;
bool charTobool (char c) {
switch (c)
[Code] ....
The question was to evaluate postfix expression (floating point numbers). I had been able to implement stack data structure using one way singly linked list linked list but I am not been able to extract the original input by the user expressions like
ex:
1. 252.124 3453.7 * 46.3 346.2 23.6 ^/$
2.45.23 87.045 * 6.5 ^$
etc,($ELIMETER)
How to take such inputs from the user for proper evaluation . Previously I tried to extract separate digits from integer and decimal fields and computed numbers. The method is very lengthy. Any optimised way for taking such input!
Write a program that evaluates postfix expression using array implementation of stack.
The expression [the input] is evaluated from left to right using a stack. When the element read from the expression is an operand, push it into the stack.When the element read from the expression is an operator: Pop two operands from the stack.Evaluate the two operandsPush the result of the evaluation into the stack.
The final result lies on the top of the stack at the end of the calculation. Make sure to display the result before terminating the program.Write a program that evaluates postfix expression using array implementation of stack.
Code:
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#define M 20
typedef struct{
[Code] ....
The point of my code is to evaluate a mathematical expression that's already formed in a Binary Search Tree. : ((6+5)-3)*(2/1)=?
I've read other forums and they usually use cout, cin and << >> but I'm still in the learning process so this is basically primitive coding.
Anyway, The recursion is already correct (I think). My problem is how to return char* or should I say an element which has 2 or more digits.
typedef struct cell{
char elem[max];
struct cell *left;
struct cell *right;
}celltype, *node;
node A;
char* evaluate(node *A) //passed as evaluation(&A);
[Code] ....
And the reason that I'm using char is because the operators are also elements in different nodes.
The code above is actually the result when I remembered that you can't return 2-digit char.
The code below is before I remembered that. It works when all results are 1 digit numbers.
typedef struct cell{
char elem;
struct cell *left;
struct cell *right;
}celltype, *node;
node A;
[Code] ....
i'm implementing a templated function callback.
I get this error:
"error C2064: term does not evaluate to a function taking 1 arguments"
I'm not sure why.
Here's the code for the template function in the timer class header:
template<class T>
void TimerEvent(DateAndTime DateTime, std::function<void(T)> Callback);
Now the class body:
template<class T>
void GameTimer::TimerEvent(DateAndTime DateTime, std::function<void(T)> Callback)
{
DateAndTime time;
time.Now(false);
if (time.Compare(DateTime) == 1)
Callback(T);
}
and calling the class in the Engine:
int test1(int a)
{
}
void Main()
{
gameTime.TimerEvent<int>(gh, test1(1));
}
The first call of my function works with empty vectors but fails when dimensions are introduced to the vectors.
When "uncommented, the commented out function call fails with the error above.
These links might be useful for those unfamiliar to QuantLib:
[URL]
QuantLib: GeneralLinearLeastSquares Class Reference
Code:
#include "stdafx.h"
#include "boost/multi_array.hpp"
#include <cassert>
#include <qlmathgenerallinearleastsquares.hpp>
#include <vector>
#include <list>
#include <iostream>
#include "boostlambdalambda.hpp"
[code]....
#include<iostream>
using namespace std;
int main() {
double x,i;
cout<<"Enter the value of the number
[Code] ....
why I am not getting exact square root if I take x as double,but if I am taking it as int I got the correct result.
Given this code
Code:
double x=1.00,y=2,z=4;
if (y/z||++x)
x+=y/z;
printf("%f
",x); So (y/z||++x)
is true if at least one expression is true, that is either (y/z)!=0 or (++x)!=0 or both. I wonder how the comparison is done? Is (y/z) be truncated to integer or 0 be promoted to double?
I'm having a small issue here with my linked list.I built a linked list with strings and it worked perfectly.Now since i'm using strtok() to separate the string.for now here's what i've got:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct dict_word *word;
typedef struct node *Node;
typedef struct double_linked_list *DLL;
}
[code]....
The main is not working properly, I get strange missing parenthesis notices and array errors which I am not understanding. How to identify the errors. Functions are included.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int menu ();
double change_value (double * value);
[Code] ......
this is what I got so far
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
[Code].....
he problem is that when I print out the three sums at the end of the program I dont get any decimal points but just zeros like something.00 instead of something.50 etc
I want to convert string to double. I refered this strtod() - C Library Function Example
Code:
#include <stdio.h>
#include <string.h>
int main() {
const char string[] = "$$GPRMC,013732.000,A,3150.7238,N,11711.7278,E,0.00,0.00,220413,,,A*68";
char term;
const char delims[] = ",";
}
[code]....
How to add double quotes into string.I want to prepare command into following way with string.
awk 'BEGIN {printf "x
%10s %10s
", "Vol", "Current"}{if($1+0==$1){printf "%10.5f %10.5f
", $2, $3}} END {printf "y
"}'
I just wanted to know a way to cut off any remaining zeroes from a double data type. I' trying to calculate cost and output it but it keeps adding a bunch of zeroes on the end. I know there must be a way to
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double x = 3072.00000000;
double y = 3072.0000000;
when checking with if its not working
if(x==y) it not working
I am programming about some numerical problems. I know that vector supplies vector operations. But vector always allocate more memory (used when the size changes). My matrix or array never change size, and the vector operation is just +,-,dot,cross,distance
My question is that should I use vector, or simple double array with new & delete is enough for me?
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
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