The following piece of code is supposed to output the binary representation of a given integer and it does exactly that. However, if the given integer is 2, then output is 01. Is there a way to make the program output 0001. I am working on a C program that outputs 4-bit gray code.
#include <stdio.h>
#include <math.h>
int main(void) {
long int n=2;
while (n) {
if (n & 1)
printf("1");
[Code] ......
I am looking to eliminate the leading zeroes of the input. The format has to stay the same and output must be as hinted in formatting.
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
using namespace std;
void process(ifstream& infile, char&ch, int&dec, int&c, int&w);
int main(){
[code]....
I want to convert a float number like 2.3 to 0002.3.Is therany inbuilt function in C/C++ for this.
View 4 Replies View RelatedI just wanted to know a way to cut off any remaining zeroes from a double data type. I' trying to calculate cost and output it but it keeps adding a bunch of zeroes on the end. I know there must be a way to
View 1 Replies View RelatedI'm trying to create a two dimensional array that displays zeroes in a 10 by 10 format. But I don't really know how.I've been playing around and this is what I have so far:
Code:
#include<stdio.h>
int main(void) {
int my_array[10][10]={0};
int i,j;
[code]....
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111
Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010
Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102
Number entered is not a binary number
#include <iostream>
using namespace std;
int main()
{
int num;
[code]....
I am working on pset4 in the CS50 online coarse. The goal is to resize a bmp image. I have it working except adding the padding back to new resized image. The image I am using uses 3 bites of padding. If the factor I resize the image by works out to have 3 bites of padding it works perfect and if the image has no padding it works perfectly I need a fresh pair of eyes. I am not sure how to add the images so here is the address to download the images and the skelton of the source code they gave to modify. [URL] .... The image that requires the padding is labled as small.bmp.
#include <stdio.h>
#include <stdlib.h>
#include "bmp.h"
int main(int argc, char* argv[]) {
// ensure proper usage
if (argc != 4)
[Code] .....
Here's the part of the codes where I tried to use boolean expression:
Code:
#include <iostream>
using namespace std;
int main() {
int num;
cout << "8-bit Binary Number=";
cin >> num;
[Code] .....
How can I get started with the body?
Here's the part of the codes where I tried to use boolean expression:
#include <iostream>
using namespace std;
int main()
[Code].....
May I know that how can I get started with the body?
i want a C program to convert 2.3 to 0002.3 . Any in built function is there for this conversion?
View 10 Replies View RelatedI am using atomic instructions on x64 and variables so used must be 16 byte aligned.
I use a number of structures where their members are so operated upon.
The structures accordingly needs must be 16 byte aligned and padded - their internal members must be on 16 byte boundaries and, crucially, there must be tail padding to a 16 byte boundary, so I can allocate arrays of these structures and use pointer math to iterate. (I am naturally using aligned malloc).
The problem I am finding is that it is not apparent to me how to achieve this end. Here below we have a test structure (currently I'm working with the latest Amazon Linux GCC, 4.6.3, on x64);
Code:
#define LFDS700_ALIGN_DOUBLE_POINTER 16
#define LFDS700_ALIGN(alignment) __attribute__( (aligned(alignment)) )
LFDS700_ALIGN(LFDS700_ALIGN_DOUBLE_POINTER) struct test_element
{
struct lfds700_freelist_element
[Code] ....
I allocate an array of test elements, thus;
Code:
te_array = abstraction_aligned_malloc( sizeof(struct test_element) * 100000, LFDS700_ALIGN_DOUBLE_POINTER );
The problem manifest is that sizeof(struct test_element) is 40 bytes! So the second element does not begin on a 16 byte boundary and we all fall down. Printing the addresses of the first element in the test element array, I see the following;
Code:
(gdb) print *ts->te_array
$2 = {fe = {next = {0x7fffec0008d0, 0x2}, user_data = 0x7fffdc0008d0}, thread_number = 3, datum = 0}
(gdb) print sizeof(struct test_element)
$3 = 40
(gdb) print &ts->te_array->fe.next
[Code] ....
So we see fe->next is the first element and so is correctly aligned curtsey of aligned malloc, where fe->next is 16 bytes, fe->user_data is correctly aligned, but then te->thread_number is misaligned and te->datum is given eight bytes rather than four, leaving us in the end without correct tail padding to a 16 byte boundary.
So, what gives? how *am* I supposed to indicate to the compiler it must pad structures to 16 byte boundaries?
#include<iostream>
#include<fstream>
#include<iomanip>
#include <sstream>
using namespace std;
string padLeft(string,char,int);
string padRight(string,char,int);
string fromMoneyToStr(double);
[Code] ....
And don't know how to use padding functions so I can space my receipt.
struct st
{
char a;
short b;
char c;
}
what will be size of structue.
i am writing a program that accepts a decimal number from the user and convert it to binary numbers. After the conversion, i should count the number of 1's and 0's in the said binary number. I got upto converting and counting 1's using Brian Kernighan’s Algorithm. But, i can't seem to get it to count the number of 0's.
#include <iostream>
#include<bitset>
using namespace std;
int main() {
int num,count=0,Zero,count1 =0;
cout<<"Enter the number:";
cin>>num;
string binary;
[code].....
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h>
#include <math.h>
char* ReverseString (char _result[]) {
int start, end, length = strlen(_result);
char swap;
for (start = 0, end = length-1; start < end; start++, end--)
[code]....
For example if we have 101010 First half is 101 which you get by multiplying 101010 * 10 ^-3
now how do you get the second half (010) ??
I have a code and am asked to modify it so that it will take as input as unsigned binary number up to 16 digits in length and convert it into its equivalent decimal number and output that decimal number.
All I know is that I use library function strlen() in <cstring> to calculate the length of the input string.
I also know I have to use something called pow(2,4);
//pow (); is found in cmath
I was told to use sum = sum >>16-l; (l is the length of />/>
#include <iostream>
using namespace std;
int main() {
[Code]....
how to take binary number as an input, generate partial products by bit-wise multiplication and in last step to add all the partial products to generate final products".
View 5 Replies View RelatedI had an exercise that required me to convert a number to binary (base 2) which as simple enough.
Code:
#include <iostream>#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ....
I have to do a code for a encoder, decoder and converter for binary number and hexadecimal...
View 1 Replies View RelatedI recently wrote a program to convert numbers to binary in c++, Well here it is:
#include <iostream>
void recur(int convert) {
if(convert == 0) //if input is 0 , return nothing. {
return;
}
recur(convert/2); // divide convert by 2, get only a 1 or 0
[Code] ....
Write a program to print out the binary value of a 16 bit number.
Create integers i, count, and mask.
Set 'i' to a hex value of 0x1b53.
Set mask to a value of 0x8000. Why?
print a line to show the hex value of i and then the leader for the binary value like this: Hex value = 1b53 Binary=
Use a for loop to loop 16 times and print 16 digits, using count as the loop counter
To test for each digit value, bitwise and 'i' with 'mask'
when the result for the bitwise and is true, print the number '1'
when the result for the bitwise and is false, print the number '0'
then shift mask one place to the right
print a new line and then quit
Use prtscrn and make a hard copy of the code with the console output.
Extra: use the modulus of count and print a space after every 4th digit to make the binary easier to read
The output should look like this: Hex value = 1b53, Binary= 0001 1011 0101 0011
so far this is what i have
#include <stdio.h>
#include <stdlib.h>
int main() {
int i, count, mask;
// 1B53 0001 1011 0101 0011
// 8000 1000 0000 0000 0000
i = 0x1b53;
[Code] ....
it is telling me that there is an "else" without previous "if", also is the program that I wrote correct?
Write a program to determine the number of binary palindromes in a given range [a;b]. A binary palindrome is a number whose binary representation is reading the same in either forward or reverse direction (leading zeros not accounted for). Example: the decimal number 5 (binary 101) is palindromic.
View 2 Replies View RelatedBasically i need to make a number guessing game where user thinks of a numbver from 1 - 100 and the machine will try to guess it in the least number of times. Once it guesses the number it will also say how many tries it took to guess.
My code so far is
#include<iostream>
using namespace std;
const int MAX = 100;
int main() {
char ch;
cout << "Think of an integer number between 0 and " << MAX<<endl;
cout << "Write it down on a piece of paper then hit a key to continue"<<endl<<endl;
cin.get(ch);
[Code] ....
If I have a number 117, represented in binary as : 01110101 and I wanted to grab the top nibble. What would be the decimal value I would be extracting?
Would it be 0111 or 0101 decimal values 112 or 5 or is my understanding completely wrong?
Windows 7, 64 bits, Visual Studio 10.
I have a problem to read a large number of binary files, process them and store them under a new name. The program and routines go very well for 505 files. After reading 506 files, the program now refuses to read the next file. I have 16 Gb of memory and tried to close all other programs and restart the PC. it always stops after 506 files (512 files would be more understanding in a way...).
Here is my code. I have tried many things without success. This is only part of the loop that stops. The if test if (myfile.is_open() returns false by some reason. I can start the process again starting with the file that does not open and then it stops again after 506 files.
char * tfiBlock;
ifstream myfile (OrigFilename, ios::in|ios::binary|ios::ate);
if (myfile.is_open()) {
int lengde = myfile.tellg();
tfiBlock = new char [lengde];
//static char memblock [size];
[Code] .....
Clean up procedure:
delete[] tfiBlock;
Are there any limits to how many files that can be opened, or is it maybe someting to be set in the compiler?