C++ :: Zero Padding To A Float Number?
Aug 12, 2013I want to convert a float number like 2.3 to 0002.3.Is therany inbuilt function in C/C++ for this.
View 4 RepliesI want to convert a float number like 2.3 to 0002.3.Is therany inbuilt function in C/C++ for this.
View 4 RepliesThe following piece of code is supposed to output the binary representation of a given integer and it does exactly that. However, if the given integer is 2, then output is 01. Is there a way to make the program output 0001. I am working on a C program that outputs 4-bit gray code.
#include <stdio.h>
#include <math.h>
int main(void) {
long int n=2;
while (n) {
if (n & 1)
printf("1");
[Code] ......
How to reserved int number and print as float number ?
View 1 Replies View RelatedI am entering numbers to float ... I want program to find out, which first number is not from specific interval. How to do it ? Example: Enter input : 5 10 20 30 50 46 . 30 is invalid. Here is the code :
Code:
while(scanf("%f",&input)!=EOF || input==0) {
sum=input+sum;
if (getchar() == '
[Code]....
how can I check if the number is float point number without converting the number to string and then find '.'?
For example, this number (5.0) should not be integer. I found the following way in Python but it didn't work in C++
abs(n - (int)n) < 0.000001
I'm doing some exercises in c and i have to do one which shows me this output:
Quote
I=0 J=1
I=0 J=2
I=0 J=3
I=0.2 J=1.2
I=0.2 J=2.2
I=0.2 J=3.2
.....
I=2 J=?
I=2 J=?
I=2 J=?
How do you convert a number float in a range of -10.0f to 17.0f to a eqivalent number in the range of 0.0f to 1.0f?The code does not work well. floaty is the float to change.
//change range to 0..1
diamond[x][y] = (floaty - minY) / (maxY - minY);
I need to read a float number and show the rest of his division by an integer, but i'm having the following error message:
Quote
error: invalid operands of types 'float' and 'int' to binary 'operator%'
I have a program that runs fine but outputs garbage and skips processes when I input a decimal. It compiles fine and has no errors.
Code:
#include <iostream>
#include <float.h>
using namespace std;
int main() {
int x;
int y;
[Code] ....
What would be the best way to remove the decimal point from a float number? For instance if I have a float number .2546 I would like to be able to remove the dot and use just the number (int) 2546 for some calculations.
Maybe, convert to string than remove the first character from the string than convert the string back to an int?
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() {
int x;
while(1){
cin>>x;
cout <<x;
}
return 0;
}
So, I'm supposed to do : Create a function with unlimited number of arguments, which forms a dynamic string based on the following form (%d, %s, %f, %lf, %c), with the following prototype:
char*create(char*form, ...);
The function is supposed to have the following output:
create("Peter is %d years old and is in %s-%c class.",7,"second",'A');
-> Peter is 7 years old and is in 7-A class.
create("His GPA is %lf.",4.96);
-> His GPA is 4.96.
create("His favourite subject is math!");
-> His favourite subject is math!
I've managed to do the following :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>
char *create(char *form, ...) {
char *res =(char*)calloc(1,1),*pos_int,*pos_float,*pos_str,pos_char,*pos_long;
[Code] ....
The part with %d and %s string was not that hard, but now I'm supposed to convert %f and %lf to string, I've tried using sprintf but I've had no luck so far, another problem is the fact that I've gotta use lists to complete the task. I've been trying to convert float to string for the past 2 hours, but I'm drawing a blank now.
I am working on pset4 in the CS50 online coarse. The goal is to resize a bmp image. I have it working except adding the padding back to new resized image. The image I am using uses 3 bites of padding. If the factor I resize the image by works out to have 3 bites of padding it works perfect and if the image has no padding it works perfectly I need a fresh pair of eyes. I am not sure how to add the images so here is the address to download the images and the skelton of the source code they gave to modify. [URL] .... The image that requires the padding is labled as small.bmp.
#include <stdio.h>
#include <stdlib.h>
#include "bmp.h"
int main(int argc, char* argv[]) {
// ensure proper usage
if (argc != 4)
[Code] .....
i want a C program to convert 2.3 to 0002.3 . Any in built function is there for this conversion?
View 10 Replies View RelatedI am using atomic instructions on x64 and variables so used must be 16 byte aligned.
I use a number of structures where their members are so operated upon.
The structures accordingly needs must be 16 byte aligned and padded - their internal members must be on 16 byte boundaries and, crucially, there must be tail padding to a 16 byte boundary, so I can allocate arrays of these structures and use pointer math to iterate. (I am naturally using aligned malloc).
The problem I am finding is that it is not apparent to me how to achieve this end. Here below we have a test structure (currently I'm working with the latest Amazon Linux GCC, 4.6.3, on x64);
Code:
#define LFDS700_ALIGN_DOUBLE_POINTER 16
#define LFDS700_ALIGN(alignment) __attribute__( (aligned(alignment)) )
LFDS700_ALIGN(LFDS700_ALIGN_DOUBLE_POINTER) struct test_element
{
struct lfds700_freelist_element
[Code] ....
I allocate an array of test elements, thus;
Code:
te_array = abstraction_aligned_malloc( sizeof(struct test_element) * 100000, LFDS700_ALIGN_DOUBLE_POINTER );
The problem manifest is that sizeof(struct test_element) is 40 bytes! So the second element does not begin on a 16 byte boundary and we all fall down. Printing the addresses of the first element in the test element array, I see the following;
Code:
(gdb) print *ts->te_array
$2 = {fe = {next = {0x7fffec0008d0, 0x2}, user_data = 0x7fffdc0008d0}, thread_number = 3, datum = 0}
(gdb) print sizeof(struct test_element)
$3 = 40
(gdb) print &ts->te_array->fe.next
[Code] ....
So we see fe->next is the first element and so is correctly aligned curtsey of aligned malloc, where fe->next is 16 bytes, fe->user_data is correctly aligned, but then te->thread_number is misaligned and te->datum is given eight bytes rather than four, leaving us in the end without correct tail padding to a 16 byte boundary.
So, what gives? how *am* I supposed to indicate to the compiler it must pad structures to 16 byte boundaries?
#include<iostream>
#include<fstream>
#include<iomanip>
#include <sstream>
using namespace std;
string padLeft(string,char,int);
string padRight(string,char,int);
string fromMoneyToStr(double);
[Code] ....
And don't know how to use padding functions so I can space my receipt.
struct st
{
char a;
short b;
char c;
}
what will be size of structue.
I can do the folowing:
float var1 ;
var1 = 9.12345 ;
printf("%.2f",var1) ;
the output will be 9.12. What if I wanted to save that as another separate float with displaying it on screen?
#include <iostream>
#include <string.h>
#include <sstream>
[Code]....
I am trying to write my files to another subfolder . Below is my program.
Code:
cat th6.c
#include <pthread.h>
#include <stdio.h>
#include <string.h>
#define SIZE 8
#define NUMELM 8
[Code] ....
I observe my filename along with directory as text in the new file created in sublfolder. This is output.
[cporgs/apue/threads]: mkdir first
[cporgs/apue/threads]: ./a.out test.txt first
test.txt -- first/test.txt
dfdfdfdfdfdfdf-14
dfdfdfdfdfdfdf-14
in thread test.txt first
[cporgs/apue/threads]: cat first/test.txt
dfdfdfdfdfdfdffirst/test.txt
[cporgs/apue/threads]: cat test.txt
dfdfdfdfdfdfdf
I could not able to get from where this filename and folder is getting added.
I have a question here
How I want to convert an int to float in the middle of the program
#include <iostream>
using namespace std;
int main()
{
int x;
float y;
cin>> x;
y= (float)x;
cout<< y;
}
is this line correct y= (float)x;?
determining if a value entered in loop is an odd or even number. Also, the value can't be int because it may be a decimal value(therefore i cant use the if(x%==0).
I need to replace the if(value%2 ==0) else num_even++ statement in my code with something else that will work with float to determine odd vs even.
#include <iostream>
using namespace std;
int main() {
int num_values;
float sum_values = 0;
int num_neg_values = 0;
int num_pos_values = 0;
[code]....
this is my code
#include<stdio.h>
main()
{
[Code]....
N=1st number M=2nd number(accrding to my prof we will name it N and M
ctr= increment of factorial of N, ctr2= increment of factorial of (N-M)
the problem is when i got the factorial of N / factorial of (N-M) i need to get the last non zero digit. so i use mod if it has zero in it. but mod can be only used with an int value. and when i change it to int value, the value of fact1 which is a float change
I am looking for a math/big num library, that allows me to convert 32/64/80 bot float numbers to string and vice versa.
Precision & accuracy is of importance here, and since this is an IEEE standard, i have high hopes that there are libraries for this out there, which would save me the hassle of trying to implement this myself...
I am working from my "ansi c" book by steven lawlor, page 73 program 2. write a program that accepts two numbers from the keyboard and prints the following information.
variables
first
second
execution
First number ? 7
Second number ? 2
the second goes into the first 3 times
with a remainder of 1.
the quotient is 3.5.
Code:
#include <stdio.h>
main() {
int first, second;
scanf(" %1i %1i", &first, &second);
printf("First number ? %1i
[Code] ....
//I included this as I had some error message come up
// before, not sure if this is correct though?
} it shows what is expected but I cant get the 3.5.
I have tried %f and variations of width/precision but still not luck. Also, when I click on the application and put in the variables I press enter, the program executes and disappears so I cant see the result. how do I get the program to stay up until I want to get rid of it?
I just checking but confused with float. in that code same size int, and same type double are working but float showing nothing in printf..why?? i'm using GCC compiler int 32bit win7 os
Code:
#include <stdio.h>
int main() {
char arr[10] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' };
printf("Size of char=%c
", ((char *) (&arr[0]))[1]);
[Code] ....