C :: How To Reserved Int Number And Print As Float Number
Nov 24, 2013How to reserved int number and print as float number ?
View 1 RepliesHow to reserved int number and print as float number ?
View 1 RepliesI need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
I am entering numbers to float ... I want program to find out, which first number is not from specific interval. How to do it ? Example: Enter input : 5 10 20 30 50 46 . 30 is invalid. Here is the code :
Code:
while(scanf("%f",&input)!=EOF || input==0) {
sum=input+sum;
if (getchar() == '
[Code]....
how can I check if the number is float point number without converting the number to string and then find '.'?
For example, this number (5.0) should not be integer. I found the following way in Python but it didn't work in C++
abs(n - (int)n) < 0.000001
I'm doing some exercises in c and i have to do one which shows me this output:
Quote
I=0 J=1
I=0 J=2
I=0 J=3
I=0.2 J=1.2
I=0.2 J=2.2
I=0.2 J=3.2
.....
I=2 J=?
I=2 J=?
I=2 J=?
I want to convert a float number like 2.3 to 0002.3.Is therany inbuilt function in C/C++ for this.
View 4 Replies View RelatedHow do you convert a number float in a range of -10.0f to 17.0f to a eqivalent number in the range of 0.0f to 1.0f?The code does not work well. floaty is the float to change.
//change range to 0..1
diamond[x][y] = (floaty - minY) / (maxY - minY);
I need to read a float number and show the rest of his division by an integer, but i'm having the following error message:
Quote
error: invalid operands of types 'float' and 'int' to binary 'operator%'
I have a program that runs fine but outputs garbage and skips processes when I input a decimal. It compiles fine and has no errors.
Code:
#include <iostream>
#include <float.h>
using namespace std;
int main() {
int x;
int y;
[Code] ....
What would be the best way to remove the decimal point from a float number? For instance if I have a float number .2546 I would like to be able to remove the dot and use just the number (int) 2546 for some calculations.
Maybe, convert to string than remove the first character from the string than convert the string back to an int?
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() {
int x;
while(1){
cin>>x;
cout <<x;
}
return 0;
}
So, I'm supposed to do : Create a function with unlimited number of arguments, which forms a dynamic string based on the following form (%d, %s, %f, %lf, %c), with the following prototype:
char*create(char*form, ...);
The function is supposed to have the following output:
create("Peter is %d years old and is in %s-%c class.",7,"second",'A');
-> Peter is 7 years old and is in 7-A class.
create("His GPA is %lf.",4.96);
-> His GPA is 4.96.
create("His favourite subject is math!");
-> His favourite subject is math!
I've managed to do the following :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>
char *create(char *form, ...) {
char *res =(char*)calloc(1,1),*pos_int,*pos_float,*pos_str,pos_char,*pos_long;
[Code] ....
The part with %d and %s string was not that hard, but now I'm supposed to convert %f and %lf to string, I've tried using sprintf but I've had no luck so far, another problem is the fact that I've gotta use lists to complete the task. I've been trying to convert float to string for the past 2 hours, but I'm drawing a blank now.
is there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c", m, ' ',*);
}
This is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
How can i print out the SECOND MIN number and MAX number without using array?
cout << "Please input a positive integer: ";
cin >> input;
min = input, max = input, secondmin = input;
do {
cout << "Please input a positive integer: ";
cin >> input;
[Code] .....
#include<stdio.h>
#define TRUE 1
int formOddInt(int n);
[Code]....
i just started learning programming and i just wanna know how come when i try to print the last digit of a number the output always become 6?
View 4 Replies View Relatedi want to print Largest number from any 5 rows.Th number printed should be any one of the largest in the five rows of 2d arrays.I have created code for largest number in each row but how to pick and print them randomly?.
Code:
#include<conio.h>
main( )
{
int a,b,c,d,e,x;
int arr[] = {a,b,c,d,e};
int Matrix[5][5] ={ /*Initializing array*/
2,4,3,5,9,
6,8,2,2,10,
[Code]...
Print the inverse number. Ex: 2178*4=8712
Write down a program which can satisfy the prerequisite and print out the screen.
The answer is:
Code:
void inverse2 ()
{
int i,j;
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
if (i*j==inverse (i))
printf("%5d%2d",i,j);
}
I can't understand the double for loop.
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
And The meaning for
i*j==inverse (i)
when i compile and run it it gives me the number 0 and not the proper number stored in array.
Code:
#include <stdio.h>
int main()
{
int myArray[11] = { 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 };
}
[code]....
Basically i want to input a number for example 123456 and get back how many 7's are in the input number and also to print out that same number with stars in between like this *1*2*3*4*5*6*. Here is what i have so far:
#include <iostream>
using namespace std;
int countSeven(int x){
if(x == 7)return 1;
int c = 0;
while(x/10 > 9)c++;
return countSeven(x/10)+1;
when i compile it does not do what i tell it it just tells me there are 0 7's in the input number no matter how many there really are...
My objective is to check to see if a number is odd or even and print it to the screen just to make sure its working correctly.
The data file contains:
138
402 2 485
9
43
98 805
58
421
948 7 97
48
67
35
42
948
579 39 12
700 20 500 210
98
I can get the numbers to print fine using:
fstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
while(infile1.get(listNum))
cout << listNum;
}
However, when I check for odd or even numbers it will check each and every number.
printed like this (partial list):
1 is odd 3 is odd 8 is even
9 is odd
But it should print:
138 is even
9 is odd
I tried using getline, but it keeps giving me the errors:
invalid conversion from 'void*' to 'char**'
invalid conversion from 'char' to 'size_t*'
too few arguments to function 'ssize_t getline(char**, size_t*, FILE*)'
Here is the getline code, what am I doing wrong? I have tried switching things around, adding things. Just nothing works.
ifstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
getline(infile1, listNum);
cout << listNum;
}
The program works, but the rational number doesn't print as reduced. I guess i have to call the reduction function, but i'm not sure where
the output that i get is:
2/6 + 7/8 = 58/48
58/48 = 1.20833
2/6 - 7/8 = -26/48
-26/48 = -0.541667
2/6 x 7/8 = 14/48
14/48 = 0.291667
2/6 / 7/8 = 16/42
16/42 = 0.380952
the output that i suppose to get is:
1/3 + 7/8 = 29/24
29/24 = 1.20833
1/3 - 7/8 = -13/24
-13/24 = -0.541667
1/3 x 7/8 = 7/24
7/24 = 0.291667
1/3 / 7/8 = 8/21
8/21 = 0.380952
here is my header file
//Prevent multiple inclusions of header
#ifndef RATIONAL_H
#define RATIONAL_H
//Rational class definition
class Rational {
[Code] .....
Write a program to print out the binary value of a 16 bit number.
Create integers i, count, and mask.
Set 'i' to a hex value of 0x1b53.
Set mask to a value of 0x8000. Why?
print a line to show the hex value of i and then the leader for the binary value like this: Hex value = 1b53 Binary=
Use a for loop to loop 16 times and print 16 digits, using count as the loop counter
To test for each digit value, bitwise and 'i' with 'mask'
when the result for the bitwise and is true, print the number '1'
when the result for the bitwise and is false, print the number '0'
then shift mask one place to the right
print a new line and then quit
Use prtscrn and make a hard copy of the code with the console output.
Extra: use the modulus of count and print a space after every 4th digit to make the binary easier to read
The output should look like this: Hex value = 1b53, Binary= 0001 1011 0101 0011
so far this is what i have
#include <stdio.h>
#include <stdlib.h>
int main() {
int i, count, mask;
// 1B53 0001 1011 0101 0011
// 8000 1000 0000 0000 0000
i = 0x1b53;
[Code] ....
it is telling me that there is an "else" without previous "if", also is the program that I wrote correct?
I created a richtextbox to input the text that I want to print, the command for printing which is the button and instead of printdialog box((PrintDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)) to be display, I created combobox which will display the available printers and then print.
Like this code bellow .
To get the available printers:
foreach (String printer in PrinterSettings.InstalledPrinters)
{
cbox.Items.Add(printer.ToString());
}
And the button for printing :
PrintDocument1.PrinterSettings.PrinterName = cbox.SelectedItem.ToString();
PrintDocument1.Print();
Now what I want to do is I will add some textbox to input the page number to be printed . For example the current pages in the richtextbox are 12pages when I'm going to run the program I will input in the textbox the page/s that I want like (3-7pages). How could it be ?
C programming, make it use a function call to print the smallest number? this is a program which prints out the smallest of three numbers within the main function that I was asked to write.Now the other question i am asked,5. Re-write the program, uses a function call to print the smallest number?
Code:
# include <stdio.h>
main()
{
int a,b,c;
int temp, min;
a = 100;
b = 23;
c = 5;
}
[code]....
I've written a program which takes a character string and then prints each character vertically so that for instance the string 123 can be written as
1
2
3
no what i need is for all the numbers from zero to the inputted number to print the numbers digits vertically but each number to be printed horizontally so that for instance an input of 11 prints
1 2 3 4 5 6 7 8 9 1 1
0 1
i've made it so that i can print all numbers up to the inputted number vertically; however, i am stuck with a method for making each number print horizontally as described above.