when i compile and run it it gives me the number 0 and not the proper number stored in array.
Code:
#include <stdio.h>
int main()
{
int myArray[11] = { 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 };
}
[code]....
So I have an issue with a homework assignment that I am coding. I am attempting to get a function to iterate through an array and search for a number that was stored in an array by the user. So far I can take the number, get the numbers displayed but in my menuChoice2 function, for some reason the program is not confirming whether or not the number is entered, and is only telling me that the number has not been found, instead of confirming that the number is in the array.
Here is my code thusfar:
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
// Variables that are Globally declared
int menuChoice = 0;
int usernum[1000] = { ' ' };
[Code] .....
To be clear I am not getting any errors but something is telling me that the error is in the formatting of menuChoice2.
How can i print out the SECOND MIN number and MAX number without using array?
cout << "Please input a positive integer: ";
cin >> input;
min = input, max = input, secondmin = input;
do {
cout << "Please input a positive integer: ";
cin >> input;
[Code] .....
I am/we developing in C and we have a number of different programs. We also have problem to keep track of different versions of a specific exe file.
Is there any way to add version number when build a file so the version is added in the properties.
I doing this in a MFC c++ project in a .rc file. Is there a way (or a similar way) of doing this in C? Here its stored in the details section with product version 6.0.8:
My C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */
void printFrequencies( const int list[], int size );
int main (void) {
int status = EXIT_SUCCESS; /* defaulting status to success. */
FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
[Code] .....
is there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c", m, ' ',*);
}
This is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
I want to declare a char* array, and then make any future variables declared to be stored in a specific location within the char* array. Is this even possible, and if it is how would I go about doing it. (I plan on storing any primitive data type in it (not classes or structs), and they may signed or unsigned).....
View 12 Replies View RelatedFor my code, I want the user to enter 4 integers, which get stored in an array. Here are the lines I wrote relevant to this part:
Code:
printf("Enter 4 integers:
");
scanf("%d %d %d %d," &a, &b, &c, &d);
z[4] = { a, b, c, d};
Would this be correct?
I am writing a C program to access a string into an array from a pointer array in Visual Studio 2010. Program is given below:-
Code:
#include <stdio.h>
#include <string.h>
void main() {
char data_a[6],data_b[6]="ABcde",*ptr;
ptr=&data_b[0];
data_a[0]=*ptr;
printf("%s",a);
}
I am getting some junk character first and then my actual data on console window. I want to where I am getting wrong and how to resolve it.
how to save text stored in an array to a txt file. can sum1 how to save the text in an array to a file/txt file......
View 7 Replies View RelatedI want to declare a char* array, and then make any future variables declared to be stored in a specific location within the char* array. Is this even possible, and if it is how would I go about doing it (I plan on storing any primitive data type in it (no classes or structs), and they may signed or unsigned). I want to be able to use the variables like any other variable, I just want the variable's address to be within the char* array.
I am trying to make a program that is similar to a virtual machine and an emulator put together, and it can only run one os (which will be hard-coded into to the program). The reason I wanted to do this is because it would be the easiest way to make sure that all variables in memory are in one contiguous block, that way the part that manages memory wouldn't have to store the locations of each variable (which would have been necessary for the virtual memory manager).
An example of what I am wanting to do is
char* ram [256]; // Address 0x00 to 0xff
// Code to make sure that new variables' addresses are in ram[] if necessary
unsigned short a = 5; // Gets stored at address 0x00
unsigned int b = a; // Gets stored at address 0x00+sizeof(a)
How to reserved int number and print as float number ?
View 1 Replies View RelatedDevelop a function that finds the greatest difference between two consecutive elements stored in an array. Develop a 9 element array of doubles to test your code. Print to the screen which two numbers have the greatest difference as well as the value of the difference. Finally include an overloaded version of the function that will work if the array is composed of integers. Include your code used to test this function.
View 8 Replies View RelatedGoal: Write a program that compares the values stored in the first array to the user inputted values in the second array.
In order to fix this error: [URL]...
I had to change my array initialization to one with a star in front of it:
char a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
to:
char *a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
I also changed my 2nd array to one with a star in front of it: char *a2[20];
What does this mean exactly? Putting a star in front of an array?
Also, I am now getting an "unhandled exception" when I try to get input for my 2nd array:
cin>>a2[i];
#include<stdio.h>
#define TRUE 1
int formOddInt(int n);
[Code]....
i just started learning programming and i just wanna know how come when i try to print the last digit of a number the output always become 6?
View 4 Replies View Relatedi want to print Largest number from any 5 rows.Th number printed should be any one of the largest in the five rows of 2d arrays.I have created code for largest number in each row but how to pick and print them randomly?.
Code:
#include<conio.h>
main( )
{
int a,b,c,d,e,x;
int arr[] = {a,b,c,d,e};
int Matrix[5][5] ={ /*Initializing array*/
2,4,3,5,9,
6,8,2,2,10,
[Code]...
Print the inverse number. Ex: 2178*4=8712
Write down a program which can satisfy the prerequisite and print out the screen.
The answer is:
Code:
void inverse2 ()
{
int i,j;
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
if (i*j==inverse (i))
printf("%5d%2d",i,j);
}
I can't understand the double for loop.
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
And The meaning for
i*j==inverse (i)
Basically i want to input a number for example 123456 and get back how many 7's are in the input number and also to print out that same number with stars in between like this *1*2*3*4*5*6*. Here is what i have so far:
#include <iostream>
using namespace std;
int countSeven(int x){
if(x == 7)return 1;
int c = 0;
while(x/10 > 9)c++;
return countSeven(x/10)+1;
when i compile it does not do what i tell it it just tells me there are 0 7's in the input number no matter how many there really are...
My objective is to check to see if a number is odd or even and print it to the screen just to make sure its working correctly.
The data file contains:
138
402 2 485
9
43
98 805
58
421
948 7 97
48
67
35
42
948
579 39 12
700 20 500 210
98
I can get the numbers to print fine using:
fstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
while(infile1.get(listNum))
cout << listNum;
}
However, when I check for odd or even numbers it will check each and every number.
printed like this (partial list):
1 is odd 3 is odd 8 is even
9 is odd
But it should print:
138 is even
9 is odd
I tried using getline, but it keeps giving me the errors:
invalid conversion from 'void*' to 'char**'
invalid conversion from 'char' to 'size_t*'
too few arguments to function 'ssize_t getline(char**, size_t*, FILE*)'
Here is the getline code, what am I doing wrong? I have tried switching things around, adding things. Just nothing works.
ifstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
getline(infile1, listNum);
cout << listNum;
}
The program works, but the rational number doesn't print as reduced. I guess i have to call the reduction function, but i'm not sure where
the output that i get is:
2/6 + 7/8 = 58/48
58/48 = 1.20833
2/6 - 7/8 = -26/48
-26/48 = -0.541667
2/6 x 7/8 = 14/48
14/48 = 0.291667
2/6 / 7/8 = 16/42
16/42 = 0.380952
the output that i suppose to get is:
1/3 + 7/8 = 29/24
29/24 = 1.20833
1/3 - 7/8 = -13/24
-13/24 = -0.541667
1/3 x 7/8 = 7/24
7/24 = 0.291667
1/3 / 7/8 = 8/21
8/21 = 0.380952
here is my header file
//Prevent multiple inclusions of header
#ifndef RATIONAL_H
#define RATIONAL_H
//Rational class definition
class Rational {
[Code] .....
Write a program to print out the binary value of a 16 bit number.
Create integers i, count, and mask.
Set 'i' to a hex value of 0x1b53.
Set mask to a value of 0x8000. Why?
print a line to show the hex value of i and then the leader for the binary value like this: Hex value = 1b53 Binary=
Use a for loop to loop 16 times and print 16 digits, using count as the loop counter
To test for each digit value, bitwise and 'i' with 'mask'
when the result for the bitwise and is true, print the number '1'
when the result for the bitwise and is false, print the number '0'
then shift mask one place to the right
print a new line and then quit
Use prtscrn and make a hard copy of the code with the console output.
Extra: use the modulus of count and print a space after every 4th digit to make the binary easier to read
The output should look like this: Hex value = 1b53, Binary= 0001 1011 0101 0011
so far this is what i have
#include <stdio.h>
#include <stdlib.h>
int main() {
int i, count, mask;
// 1B53 0001 1011 0101 0011
// 8000 1000 0000 0000 0000
i = 0x1b53;
[Code] ....
it is telling me that there is an "else" without previous "if", also is the program that I wrote correct?
I created a richtextbox to input the text that I want to print, the command for printing which is the button and instead of printdialog box((PrintDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)) to be display, I created combobox which will display the available printers and then print.
Like this code bellow .
To get the available printers:
foreach (String printer in PrinterSettings.InstalledPrinters)
{
cbox.Items.Add(printer.ToString());
}
And the button for printing :
PrintDocument1.PrinterSettings.PrinterName = cbox.SelectedItem.ToString();
PrintDocument1.Print();
Now what I want to do is I will add some textbox to input the page number to be printed . For example the current pages in the richtextbox are 12pages when I'm going to run the program I will input in the textbox the page/s that I want like (3-7pages). How could it be ?
C programming, make it use a function call to print the smallest number? this is a program which prints out the smallest of three numbers within the main function that I was asked to write.Now the other question i am asked,5. Re-write the program, uses a function call to print the smallest number?
Code:
# include <stdio.h>
main()
{
int a,b,c;
int temp, min;
a = 100;
b = 23;
c = 5;
}
[code]....
I've written a program which takes a character string and then prints each character vertically so that for instance the string 123 can be written as
1
2
3
no what i need is for all the numbers from zero to the inputted number to print the numbers digits vertically but each number to be printed horizontally so that for instance an input of 11 prints
1 2 3 4 5 6 7 8 9 1 1
0 1
i've made it so that i can print all numbers up to the inputted number vertically; however, i am stuck with a method for making each number print horizontally as described above.
