C/C++ :: Program To Print Out Binary Value Of 16 Bit Number

Write a program to print out the binary value of a 16 bit number.

Create integers i, count, and mask.

Set 'i' to a hex value of 0x1b53.

Set mask to a value of 0x8000. Why?

print a line to show the hex value of i and then the leader for the binary value like this: Hex value = 1b53 Binary=

Use a for loop to loop 16 times and print 16 digits, using count as the loop counter

To test for each digit value, bitwise and 'i' with 'mask'

when the result for the bitwise and is true, print the number '1'

when the result for the bitwise and is false, print the number '0'

then shift mask one place to the right

print a new line and then quit

Use prtscrn and make a hard copy of the code with the console output.

Extra: use the modulus of count and print a space after every 4th digit to make the binary easier to read

The output should look like this: Hex value = 1b53, Binary= 0001 1011 0101 0011

so far this is what i have

#include <stdio.h>
#include <stdlib.h>  
int main() {
    int i, count, mask;
    //   1B53  0001 1011 0101 0011
    //   8000  1000 0000 0000 0000
    i = 0x1b53;

[Code] ....

it is telling me that there is an "else" without previous "if", also is the program that I wrote correct?