C/C++ :: Program That Complete Binary Number Using Recursion

Mar 12, 2015

So Im trying to make a program that completes a binary number and I have to use Recursion. Heres an example:

1] ./binary_string.out 01x0
0100
0110

2] ./binary_string.out xx
00
01
10
11

Here's what I got so far but Im stuck and I don't know what's wrong/what to do.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* convertString(char *c,int len);
int main(int argc,char *argv[]) {
int i,length;
char *cs;

[Code] ....

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C++ :: Converting Decimal To Binary Using Recursion

Feb 25, 2013

I'm trying to write a program that converts a decimal number to a binary one. I have most of the program written, but I am having a little bit of trouble. Whenever I enter a decimal number, the program will convert it correctly to binary, however, the last number is not included in the conversion. EX: Converting 37 into binary (0100101) yields 010010 when entered into the program. BTW the program must utilize recursion to achieve this goal.

#include <iostream>
using namespace std;
void decToBinary(int num1);
int main() {
int num1;

[code]....

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/*
*(*matrix(matrix+i)+j)
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I tried changing some of the bool expressions thinking I mixed up the true and false parts. After that the program ran and it created the new output file, but the file was empty. So, I don't think I mixed any of those expressions after all.

#include <iostream>
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[code]....

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I recently wrote a program to convert numbers to binary in c++, Well here it is:

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}
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[Code] ....

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C/C++ :: Program To Print Out Binary Value Of 16 Bit Number

Sep 22, 2013

Write a program to print out the binary value of a 16 bit number.

Create integers i, count, and mask.

Set 'i' to a hex value of 0x1b53.

Set mask to a value of 0x8000. Why?

print a line to show the hex value of i and then the leader for the binary value like this: Hex value = 1b53 Binary=

Use a for loop to loop 16 times and print 16 digits, using count as the loop counter

To test for each digit value, bitwise and 'i' with 'mask'

when the result for the bitwise and is true, print the number '1'

when the result for the bitwise and is false, print the number '0'

then shift mask one place to the right

print a new line and then quit

Use prtscrn and make a hard copy of the code with the console output.

Extra: use the modulus of count and print a space after every 4th digit to make the binary easier to read

The output should look like this: Hex value = 1b53, Binary= 0001 1011 0101 0011

so far this is what i have

#include <stdio.h>
#include <stdlib.h>  
int main() {
    int i, count, mask;
    //   1B53  0001 1011 0101 0011
    //   8000  1000 0000 0000 0000
    i = 0x1b53;

[Code] ....

it is telling me that there is an "else" without previous "if", also is the program that I wrote correct?

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[code].....

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10 12 14 16
18 20 22 24

I have to use a structure named Point and a structure named Sequence.

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const int MAXCOLS = 4;
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typedef struct {
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[Code] .....

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Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.

Sample Output 1:

8-bit Binary Number => 11111111
Decimal Number = 255

Sample Output 2:

8-bit Binary Number => 10101010
Decimal Number = 170

Sample Output 3:

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Number entered is not a binary number

#include <iostream>
using namespace std;
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[code]....

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Code:
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[Code] .....

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Code:
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Code:

#include <stdio.h>#include <string.h>
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