using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111 Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010 Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102 Number entered is not a binary number
#include <iostream> using namespace std; int main() { int num;
I got this algorithm of conversion and now I'm stuck at how to code it.
"Algorithm to Convert From any Base to Base 10 Decimal."
Let 'n' be the number of digits in the number. For example, 104 has 3 digits, so 'n'=3. Let 'b' be the base of the number. For example, 104 is decimal so 'b' = 10. Let 's' be a running total, initially 0.
For each digit in the number, working left to right do:
Subtract 1 from 'n'. Multiply the digit times b^n and add it to 's'.
When done with all the digits in the number, the decimal value should be 's' .
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){ char* binNum = decToBin(25); int i = 0; while(binNum != NULL){
I need to convert an integer, for example 10, to its base 16 equivalent, 16. I found this code that converts a base 16 number to base 10, but I need the opposite. Plus, this code doesn't seem to work properly with input values under 32.
I'm working on a program and I need to convert big numbers to radix 64. I would like to shorter them whit conversion that's why I choosed base 64. I have two problems:
1. The conversion works only for not so big numbers. Untill about 2^32. I would like to convert bigger numbers. Is there any solution? (I thought on GMP/MPIR library, but I can't managed it.)
2. The conversion back to decimal base doesn't works, because I use 'strtoul()' which doesn't support bigger bases like 36.
I've been trying to write some code to do what I mentioned in the title, but I haven't had much luck. I get very confused when I deal with bitwise operators, so it's hard for me to write this kind of encoding on my own. I need this encodement so I can login to an email account using smtp.
I am making a number base conversion program in c++, suppose that user enters an base 2 number and want to convert that number in base 4. when he enter the number (which he wants to be converted), how can i detect that number is belongs to base 2 number system or not.
For example: if user enter 1001011001 , program should continue and convert that number to base 4. and if user enter 1200101 or 1001012 , program should not convert that number and output that this number is not belongs to base 2 number system.
You enter decimal number into the program and what base you want. The integer part of the decimal is being handled fine, but the decimal is not.
For example, I enter 15.6847 and base 10, which means I'm going from base 10 to base 10. It spits out 68469999999999 for the decimal part. (Do not worry about the first block of numbers. The second block seperated from the first by a space is where the decimal will appear in order.)
#include <iostream> #include <string> #include <math.h> using namespace std; int baseConverter(int, int, int *, int *);
I just wanted to add strings in any base form (example 1101+100 = 10001 in base-2 but it could be added using any base-form like in base-3 to base-36) and I'm having a big trouble with my code because it gave me incorrect results.
addition(char st[], char st2[], int base){ int i, j, carry = 0, ans, len, o=0, z=1, l=0; char final[50]; if(strlen(st)>=strlen(st2)) len = strlen(st); else len = strlen(st2);
How do I convert ifstream to binary and display the binary at the end. I have a file that when it contains numbers it can do it but when reading strings it has trouble. It acts as if there is no binary in the file.
i need to code a function that converts an array of 64 bits into a hexadecimal value, the one is tested gives me correct value except for the last hexadecimal letter.
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
I am new to programming and have written the code for the following program.
PROGRAM: Input 2 arrays => arrays 1 and 2 from the user each containing 5 elements. Sum is another array which is sum of elements of array 1 and array 2. Convert each of the elements of the sum array into binary. Count number of 1's in each binary element and output it to another array "arr".
Example: arr1 = {1,2,3,4,5} arr2 = {6,7,8,9,10} sum = {7,9,11,13,15} binary of 7 [111], 9[1001], 11[1011], 13[1101], 15[1111] No of 1's in 7 [3], 9 [2], 11 [3], 13 [3], 15 [4] arr array will be {3, 2, 3, 3, 4}
I am not getting the desired output. My code is:-
include <iostream> using namespace std; int main() { int array1[5];
What is the difference between the two functions below? I created the function in the top and my friend created the function in the bottom. I just want to know why the function with the while loop prints the binary numbers backwards. And the recursive function prints the binary numbers correctly.
void findBinary(int num) { int remainder = 0; while ( num > 0) { remainder = num % 2; cout << remainder; num = num / 2;
