I am using MCC18 for use with MPLAB.
0bnnnnnnnn means a binary representation.
0x00 means a hex number representation.
What does sd001 means? signed decimal 1? if so how do I represent a -1 using this sdnnnn format?
How to convert e.g. number 75 to base 4 representation? The result should be 1023. I plan to use uint32_t
x = a3.43 + a2.42 + a1.41 + a0.40 = a3.64 + a2.16 + a1.4 + a0
How would you convert say "238273615237287352536266362524382737272" base 10 to a base x number contained within a string of characters?
View 2 Replies View RelatedThe program is supposed to convert a two digit hexadecimal number to its binary representation. My code runs without any problems but I do not know how to limit the user's input to two digits only. For example the person can input "1ABC" and the program will give the binary representation and I need it to only accept two digit only like for example "1A".
#include<stdio.h>
#define MAX 1000
int main(){
char binaryNumber[MAX],hexaDecimal[MAX];
long int i=0;
printf("Enter a two digit hexadecimal number: ");
[Code] ....
I had an exercise that required me to convert a number to binary (base 2) which as simple enough.
Code:
#include <iostream>#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ....
I am making a number base conversion program in c++, suppose that user enters an base 2 number and want to convert that number in base 4. when he enter the number (which he wants to be converted), how can i detect that number is belongs to base 2 number system or not.
For example: if user enter 1001011001 , program should continue and convert that number to base 4. and if user enter 1200101 or 1001012 , program should not convert that number and output that this number is not belongs to base 2 number system.
You enter decimal number into the program and what base you want. The integer part of the decimal is being handled fine, but the decimal is not.
For example, I enter 15.6847 and base 10, which means I'm going from base 10 to base 10. It spits out 68469999999999 for the decimal part. (Do not worry about the first block of numbers. The second block seperated from the first by a space is where the decimal will appear in order.)
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
int baseConverter(int, int, int *, int *);
[Code] ....
I just wanted to add strings in any base form (example 1101+100 = 10001 in base-2 but it could be added using any base-form like in base-3 to base-36) and I'm having a big trouble with my code because it gave me incorrect results.
addition(char st[], char st2[], int base){
int i, j, carry = 0, ans, len, o=0, z=1, l=0;
char final[50];
if(strlen(st)>=strlen(st2))
len = strlen(st);
else
len = strlen(st2);
[Code] ....
I have the code working on converting a decimal number to base 1 through 16. I need getting the code to output the one's and two's complement.
Code:
#include <stdio.h>
int main(void) {
char base_digits[16] =
{'0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
int converted_number[64];
long int number_to_convert;
int next_digit, base, index=0, a;
/* get the number and base */
[Code] ....
I got this algorithm of conversion and now I'm stuck at how to code it.
"Algorithm to Convert From any Base to Base 10 Decimal."
Let 'n' be the number of digits in the number. For example, 104 has 3 digits, so 'n'=3.
Let 'b' be the base of the number. For example, 104 is decimal so 'b' = 10.
Let 's' be a running total, initially 0.
For each digit in the number, working left to right do:
Subtract 1 from 'n'.
Multiply the digit times b^n and add it to 's'.
When done with all the digits in the number, the decimal value should be 's' .
Consider this piece of code from the following website: [URL] .....
Code:
unsigned intx = 50;
x += (x << 2) + 1;
The website above says the following about the code:
Although this is a valid manipulation, the result of the shift depends on the underlying representation of the integer type and is consequently implementation-defined.
How exactly would a legal left shift operation on an unsigned integer result in implementation-defined behaviour?
I need to convert an integer, for example 10, to its base 16 equivalent, 16. I found this code that converts a base 16 number to base 10, but I need the opposite. Plus, this code doesn't seem to work properly with input values under 32.
Code:
uint32_t input = 16;
uint8_t temp;
temp = ((input>>8)*100)|((input>>4)*10)|(input&0x0f);
I'm looking for something that can hold the current time, but is independent of the user adjusting the OS's time, and that can be converted to a std::string and back and that meets the requirements of LessThanComparable and EqualityComparable, I search online but I couldn't find anything suitable.
I can't use The C++ Standard Chrono Library because:
std::chrono::system_clock you can change the OS's time
std::chrono::steady_clock and std::chrono::high_resolution_clock cannot be converted to a std::string and back
I'm currently trying to learn about floating point representation in depth, so I played around a bit. While doing so, I stumbled on some strange behaviour; I can't really work out what's happening...
#include <iostream>
#include <cmath>
using namespace std;
int main(){
float minVal = pow(2,-149); // set to smallest float possible
float nextCheck = ((float)((minVal/2.0f))); // divide by two
[Code] ....
Essentially what's happening is:
- I set minVal to be the smallest float that can be represented using single precision
- Dividing by 2 should yield 0 -- we're at the minimum
- Indeed, isZero2 does return true, but isZero returns false.
What's going on -- I would have thought them to be identical? Is the compiler trying to be clever, saying that dividing any number cannot possibly yield zero?
"My Programm is crashing and i dont know why?"
#include<iostream>
using namespace std;
int arr[3];
struct edges {
int edge_data;
edges *next;
[code]....
Data structure problem. I have a table of the following format:
Code:
C/R 1 2 3 4 5 6 7 ...
1 x x x
2 x
3 x
4 x
5 x x x
6
... s
So my column and row names are integer numbers if an outcome of some game for a certain column and row lable is a match then we have an x on that position. The size of the integer names for both column and row name is quite large (let us imagine that it is so large that you would need a machine with 500GB of RAM memory to hold this type of table even if x's are treated as regular char's) . In every row there is at least one x and for every column the same holds for the columns. However, the number of x's for a row or a column can be bigger then 1. How to store this table efficiently? (using as less memory as possible).
The data structure should be efficiently accessed in the column fashion that is, if i want to get all values for column 4 I should be able to do that in O(N) time where N= the number of rows.
I need to convert the bit representation of an unsigned char into a string.
so like 254 would be "11111111"
I'm having some trouble where no matter what number I try to convert I get 01111111.
string bin2string(unsigned char N) {
string sN(8,'0');
unsigned char X;
unsigned char Y = 0;
for(int i = 0; i < 8; i++){
[Code] ....
I have matrix in C with size m x n. Size n isn't known. I want to have operations on matrix such as : delete first element and find i-th element. (where size m woudn't be too big , from 10 to 50 columns).
What is more efficient to use, linked list or hash table? How can I map each column of matrix to different element of linked list or hash table; depends what I choose to use?
Write a program that reads in the numeric representation of a date and prints it out in a formatted manner as the box below.
1. If the user entered an invalid number for the month it should display "Invalid Month"
2. If the user entered an invalid number for the date it should display "Invalid Date"
3. Check to see if the day is outside the range for that particular month
An example of the input and the output:
Enter the date: 1 24 2013
The date you entered is: 1242013
Im not sure on how to go about this problem, but this is what I have.
#include <stdio.h>
int main(void) {
int a, b, c;
int status;
printf("Enter the Date");
status = scanf("%d,%d,%d",&a, &b, &c);
printf(" The Date is : %d",status);
return 0;
}
Am I going about this right? Is there an easier or better way to go about it? All that happens is that the program reads the first number and spits that back out.
i am converting a base 10 number to base 4.
View 1 Replies View RelatedI was wondering if there is a standard for converting something like this:
HELLO 27 to ?3
I have run into a problem which is mostly just an annoyance. I need to know if i can have pass a derived class to a function which has the base class as its parameter. For example i have been creating a program but i have a function which needs to work for multiple classes all derived from the BaseObject class
Code :
class folder : public BaseObject
{}
class BaseObject
{void function(BaseObject B)}
how would i get the following to work:
function(folder)
I'm working on a program and I need to convert big numbers to radix 64. I would like to shorter them whit conversion that's why I choosed base 64. I have two problems:
1. The conversion works only for not so big numbers. Untill about 2^32. I would like to convert bigger numbers. Is there any solution? (I thought on GMP/MPIR library, but I can't managed it.)
2. The conversion back to decimal base doesn't works, because I use 'strtoul()' which doesn't support bigger bases like 36.
Is there any good method for that?
A pointer to base class, if assigned to a derived class, only points to the base part right? So you can only use the base part of the derived class with that pointer and no methods from the derived class?
View 8 Replies View RelatedI have 2 classes with a Function with the same definition (both inherited from the same base class) and in my derived class I derive from both of those 2. Is it possible to use the Methods of both classes? for example with an other name?
class A {
protected:
int print(int a) { std::cout << "int A: " << a << std::endl; }
};
class B : A
[Code] ....
is there something like using C::print as printc;?
The Problem, I have a Sprite class that derives from a Rectangle with properties Position, Size, Origin and Angle and a Text class that derives from Rectangle. Now i have a Button class deriving from both Sprite and Text.
- The Position, when moving the Button i have to change the position of both so i Implemented a new Method which calls SetPosition from the Sprite and the Text.
- The SetSize just affects the Button so i just did using Sprite::SetSize;
- The angle affects both so i just implemented a new Method and hide the other two
The problem is here:
- The Origin: writing button.SetOrigin(-1,0) should set the Origin of the Button and writing button.SetTextOrigin should set the Origin of the text.
Should i just reimplement a Mehtod named SetTextOrigin and call Text::SetOrigin from there and hide the button.Text::SetOrigin or is there something like using Text::SetOrigin as SetTextOrigin?
How can i calculate a logarithm with my own base for example log on base 0.52 ?
View 2 Replies View Related