C++ :: Convert Big Numbers To Other Base 64
Oct 2, 2014
I'm working on a program and I need to convert big numbers to radix 64. I would like to shorter them whit conversion that's why I choosed base 64. I have two problems:
1. The conversion works only for not so big numbers. Untill about 2^32. I would like to convert bigger numbers. Is there any solution? (I thought on GMP/MPIR library, but I can't managed it.)
2. The conversion back to decimal base doesn't works, because I use 'strtoul()' which doesn't support bigger bases like 36.
Is there any good method for that?
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Apr 15, 2013
How would you convert say "238273615237287352536266362524382737272" base 10 to a base x number contained within a string of characters?
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Mar 25, 2013
I got this algorithm of conversion and now I'm stuck at how to code it.
"Algorithm to Convert From any Base to Base 10 Decimal."
Let 'n' be the number of digits in the number. For example, 104 has 3 digits, so 'n'=3.
Let 'b' be the base of the number. For example, 104 is decimal so 'b' = 10.
Let 's' be a running total, initially 0.
For each digit in the number, working left to right do:
Subtract 1 from 'n'.
Multiply the digit times b^n and add it to 's'.
When done with all the digits in the number, the decimal value should be 's' .
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Mar 20, 2014
I need to convert an integer, for example 10, to its base 16 equivalent, 16. I found this code that converts a base 16 number to base 10, but I need the opposite. Plus, this code doesn't seem to work properly with input values under 32.
Code:
uint32_t input = 16;
uint8_t temp;
temp = ((input>>8)*100)|((input>>4)*10)|(input&0x0f);
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Dec 7, 2014
I had an exercise to convert from decimal to binary with base 2, it was simple simple i did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
[Code] .....
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ......
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Mar 6, 2015
How to convert e.g. number 75 to base 4 representation? The result should be 1023. I plan to use uint32_t
x = a3.43 + a2.42 + a1.41 + a0.40 = a3.64 + a2.16 + a1.4 + a0
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Dec 1, 2013
I've been trying to write some code to do what I mentioned in the title, but I haven't had much luck. I get very confused when I deal with bitwise operators, so it's hard for me to write this kind of encoding on my own. I need this encodement so I can login to an email account using smtp.
Here is my code so far :
Code:
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <string.h>
const char base64_table[] =
[Code]......
Gives the output :
Code:
11C
byte offset 0, new_text_sz = 5
11C
byte offset 1, new_text_sz = 5
11C
byte offset 2, new_text_sz = 5
11C
byte offset 3, new_text_sz = 5
AAAA
When according to wikipedia, it should be : T W F u
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Dec 7, 2014
I had an exercise that required me to convert a number to binary (base 2) which as simple enough.
Code:
#include <iostream>#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ....
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Jun 14, 2014
I have written this function.
void intToBase(unsigned int val,char *buff, unsigned int base) {
int digit = val%base;
if(val == 0)
return;
intToBase((val / base), buff + 1, base);
if(digit >= 0 && digit <= 9)
*buff = (digit + '0');
if(digit >= 10 && digit <= 15)
*buff = (digit + 'A' - 10);
}
This function is suppose to convert a decimal number (val) to any other base number and put it into a string (buff).
But the function puts the value in a opposite way, like if the answer is suppose to be "123" i get this "321".
Note: the function must be recursive and i can't use loops.
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Apr 23, 2012
I'm sure this is pretty simple, but any way to do this. Essentially if I have an array with P collumns and V^P rows, how can I fill in all the combinations, that is, essentially, all possible numbers in base V of P digits.
For example, for P=3 and V=2
000
001
010
011
100
101
110
111
Keep in mind that this is an 2 dimensional array, not an array of ints.
For P=4 and V=3.
0000
0001
0002
0010
0011
0012
....
Having this array generated, the rest of work for what I'm trying to develop is trivial
This is a code I've written that should do the trick, but for some reason it gives this error on compiling:
"main.cpp:65: error: invalid types `double[3][9][double]' for array subscript"
Code:
for(i=0;i<P;i++) {
for(j=0;j<pow(V,i);j++) {
for(k=0;k<V;k++) {
for(l=0;l<pow(V,(P-i-1));l++) {
a[i][(j*V*pow(V,P-i-1) + l + k*pow(V,P-i-1))];
}
}
}
}
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Feb 27, 2015
I just wanted to add strings in any base form (example 1101+100 = 10001 in base-2 but it could be added using any base-form like in base-3 to base-36) and I'm having a big trouble with my code because it gave me incorrect results.
addition(char st[], char st2[], int base){
int i, j, carry = 0, ans, len, o=0, z=1, l=0;
char final[50];
if(strlen(st)>=strlen(st2))
len = strlen(st);
else
len = strlen(st2);
[Code] ....
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Apr 29, 2014
How to convert numbers into words using ragged dynamic arrays? this is my solution:
int main()
{
char *Units[]={"ZERO", "ONE", "TWO", "THREE","FOUR","FIVE", "SIX","SEVEN", "EIGHT", "NINE"};
char *teens []={"TEN", "ELEVEN", "TWELVE","THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN" };
char *hundreds []= {"HUNDRED"};
char *tens []={ "ZERO", "TEN", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"};
char *currency []={"Dollars"};
[code]....
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Sep 26, 2014
I'm trying to get two numbers longer than long long int and add them together and multiply. I'm not sure how to convert the numbers to a string.
#ifndef BIG_INTEGER_H
#define BIG_INTEGER_H
#include "BigIntegerException.h"
class BigInteger {
private:
int biginteger[500];
int bigintegertwo[500];
[Code] .....
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Apr 29, 2014
Write a c++program that asks the user to enter positive integer numbers without points between 0 and 999. Then check the amount and print in words. You need to use dynamic ragged arrays..
This is my solution but I'm not sure if this is the right way for dynamic ragged array???:
int main()
{
char *Units[]={"ZERO", "ONE", "TWO", "THREE","FOUR","FIVE", "SIX","SEVEN", "EIGHT", "NINE"};
char *teens []={"TEN", "ELEVEN", "TWELVE","THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN" };
char *hundreds []= {"HUNDRED"};
char *tens []={ "ZERO", "TEN", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"};
[Code].....
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Mar 27, 2013
The code should convert binary numbers to decimal but it doesn't..
Code:
#include <stdio.h>
#include <math.h>
#include <string.h>
int main()
{
[Code] ....
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Jan 27, 2015
i want to convert in loop for example this
char number[]="54465465445646848640";
and in loop convert these element to int one by one.
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Oct 26, 2012
Here`s the text:
You have to expect the following input : an arbitrary amount of lines, each line consists of 5 int32 numbers. The full input will be terminated by an EOF.
E.g.:
1 2 3 4 5
6 7 8 9 0
...
You`re then supposed to convert the numbers to integers and do some calculations. I would know how to parse a single line of 5 numbers via scanf(). That`s easy, and that`s exactly what they did in class.
But how do i go about splitting the lines? What about the EOF? Even if could hack something together, by using errno or something, it would be way beyond what they are doing atm. The input is received via user input, ie stdin.
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Jan 6, 2015
I am supposed to convert a string made of many numbers between every number spaces are between, to an integer variable for every number..
How am I supposed to get over this problem?
Example: String: " 322 52 231"
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Oct 11, 2013
So I am trying to write a program that converts roman numerals into decimal numbers. I so far have come up with:
Code:
#include <stdio.h>
#include <ctype.h> // importing the tolowerfunction
//variables
int decimal, total;
char numeral[];
[Code] .....
But each time I compile it, it times out as if it were hitting an infinite loop. I have a feeling that I am not passing an individual character to the roman_to_decimal function but am unsure why.
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Jan 28, 2015
Having problem with my code. i keep getting an error towards the bottom of the code. i need the user to enter a word. and with that word convert it to numbers. once i have convert it if it is bigger than 20 i have to add the two digits together and get print out the array that response to it.
example" ALEX
A=1
L=12
E=5
X=23
1+12+5+23= 41 //since its bigger than 20 you add 4 and 1 together so it will be 5. after that you print the 5th element of array
#include <iomanip>
#include <iostream>
#include <string>
using namespace std;
int main()
{
string name;
[Code]...
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May 4, 2014
I have a fascination with Roman numerals and would like to create a C program that converts Roman numeral inputs to normal numbers.
I want to keep everything simple and only use the C library for the coding.
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Feb 5, 2015
I have been playing around with .txt and .dat files lately. I only manage to load the files, but I don't seem to be able to load files using a variable.
Also modifying the data after it is imported is also currently problematic. I know how to go about the process without the need to import anything, but whenever I import the data I am having trouble modifying/ editing the ".txt" or ".dat" data.
Below is my current code:
#include <iostream>
#include <fstream>
#include <string>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
ifstream file;
ofstream result;
char in_file_name[8], out_file_name[8];
[Code] ....
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Sep 23, 2014
I am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3
10110101
11111111
10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
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May 7, 2013
i am converting a base 10 number to base 4.
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Feb 8, 2013
I was wondering if there is a standard for converting something like this:
HELLO 27 to ?3
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Sep 23, 2012
Code:
template<class T>
class Convert {
T data;
public:
Convert(const T& tData = T()) : data(tData)
[Code] ....
Why do we use operator? Is float and double function names below?
Code:
Convert<int>::operator<float> float();
Convert<int>::operator<double> double();
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