C++ :: How To Convert Numbers From Char Array
Jan 27, 2015i want to convert in loop for example this
char number[]="54465465445646848640";
and in loop convert these element to int one by one.
i want to convert in loop for example this
char number[]="54465465445646848640";
and in loop convert these element to int one by one.
I want to convert int to char array for get the total of digits like this..
Code:
int total;
char charnum[2] = (char)total; //this is the problem
int num = 0;
for (int i = 0; i <2; i++)
{ num += charNum[i] -48;}
cout << num;
If total was 42 i want to get output as 6. for this purpose i want to convert int to char.
Currently I have:
Code:
char my_array[4] = { '1', '2', '3', '4' };
how do I convert the above to a string of: "1234"
.I have this string that I need to convert into a 2d char array like this:
String str= "A,E,B,I,M,Y#N,R,C,A,T,S";
I know how to use delimiter and split string and I know how to convert but only from string to char[].I need something like this:
Input: String str= "A,E,B,I,M,Y#N,R,C,A,T,S";
Output: [A] [E] [B] [I] [M] [Y][N] [R] [C] [A] [T] [S]
Without lossing information?
View 14 Replies View RelatedHow to convert char array into double?,i.e. store char array values into a single double variable. Below is the code that i'm working. Im extracting the value "2255.1682" from char array gpsdata1. I used while loop, extracted the value and stored in "myChar", but i want to store it in double variable "lat1".
Code:
#include <stdio.h>
#include <stdlib.h>
int main(){
unsigned char gpsdata1[]="$GPGGA,091310.000,2255.1682,N,11356.3605,E,1,4,1.62,164";
char myChar;
double lat1;
[Code] .....
How do I convert a string of unknown length to a char array? I am reading strings from a file and checking if the string is a Palindrome or not. I think my palindrome function is correct, but do I do something like char [] array = string.length(); ??
#include <iostream>
#include <fstream>
#include <string>
#include <cctype>
[Code].....
I have the following code which attempts to assign a u_int8 array of 256 to an unsigned char[256]:
Code:
unsigned char testData[256]=pSample->data;
I get the compilation error:
error C2440: 'initializing' : cannot convert from 'const uint8_t [256]' to 'unsigned char [256]'
What is the safe way to cast or convert here?
I'm writting program and need to convert int ot char array without simbol. I have tryed snprintf , but his returns array full of simbols if it is initilized elsware return full of garbidge. Is there any elegent way to aceave this? What I'm trying to aceave is liek this:
char buffer[10];
int temp = 1231423;
// Do conversation...
// After conversation char array should look like this
// 1 2 3 1 4 2 3 _ _ _
// without simbol
How do I convert just the number from position 4 to 15 from this char array and convert to int and save to variable
char numbers[]="54155444546546545643246543241465432165456";
the real char got 1000 digits this is just example how do i convert chars from numbers[4] to numbers[15] and save them as one number ? in this case i will get int x = 5444546546545643 as u can see char numbers as a example above
I am writing code to multiply two int arrays and in my one function i am trying to convert the char array into an int array. I have tested many parts however i can not find the problem.
Code:
struct integer* convert_integer(char* stringInt){
struct integer *converted = malloc(sizeof(struct integer));
int length, i, *ints;
ints = (int *)malloc(10001 * sizeof(int));
length = strlen(stringInt);
printf("stringInt: %s with length of %d
", stringInt, length);
converted->size = length;
[Code]...
how to convert an element of int type of an array to char type?
View 2 Replies View RelatedI have a file which contains a year and the name of an associated file to be read. I need to extract the data in the txt file and perform some calculations.
( year data file)
2004 2004data.txt
2005 2005data.txt
2006 2006data.txt
Here is what I do. I first declare "char yeardata" and then pass "2004data.txt" to it. Then I call yeardata in ifstream to extract the data inside the file "2004data.txt". The problem is that char yeardata is not constant so I cannot pass the file to it. It doesn't work if I change "char yeardata" to "const char yeardata".
Code:
int oldnewcomp_temp(char* lcfile) {
using namespace std;
int year;
char yeardata;
[Code] ....
I am writing a basic keylogger and i want to add data to log file, but it says that i cant convert char to int. Everything else works fine.
Code:
#include <iostream>#include <windows.h>
#include <stdio.h>
#include <time.h>
using namespace std;
[Code] ....
Example
char A[4]
gets(A) --> 1234
if we have int x = 5; and we want to convert x which is == 5 to char so for example char number = x doesnot work i understand why , but how to convert it ?
View 14 Replies View RelatedI'm having some problems with changing an array of numbers of type char to type int. Every time i try to sum 2 array indexed values it returns some letter or symbol. Also, if i change the type of the array in the functions the compiler gives me an error message. I would also like to add that the problem requires that the first two arrays be char so each individual number gets assigned to a different value.
My current code is:
Code:
#include <iostream>
void input(char a[], char b[], int& size_a, int& size_b);
void convert(char a[], int size);
void reverse(char a[], int size);
void add(char a[], char b[], int c[], int size);
int main()
[Code]....
Is there anyway to convert std::string to char*?
Like:
std::string x="hello world";
char* y=x;
I am trying to convert a char to a CString, I have tried to use the CString.Format method but didn't work. I have a char(char holder[10]) and I want to see if holder is a certain string, say for instance SeaLevel. Below is the code that I also tried.
if(holder == "SeaLevel")
{
//do something
}
I have this code working:
char tmp_wku[3];
tmp_wku[0]=0x01;
tmp_wku[1]=0x9D;
tmp_wku[2]=0x62;
char tmp_com[11];
[Code] ....
This sends the buffer to a LIN modem. My question is: can this be done better. If I have a astring of hex numbers like "09 98 88 55 42 FF 00 00 FF BD 89". How could I send this without manually makng a char with hex numbers?
when I was looking for a way how to convert char into numeric value for std::cout I found some old discussion with this statement: Operations on unsigned int are typically faster than on unsigned char, because your processor cannot fetch single bytes but has to get at least a multiple of 4 and mask out the other 3 bytes. Is this true? By using smaller (in bytes) variable I actually slow down my program? I always thought that it is a good practice if I use the smallest variable which will do the work. Is it also dependent on a compiler and OS?
View 2 Replies View RelatedI am trying to convert char to time and I found the following code. But it gives me a -1 on "converted" instead of time.
#include <stdio.h>
#include <time.h>
#include <iostream>
using namespace std;
[Code].....
I want to avoid converting the char[] into a string as an intermediate step, since I'm trying to write some "string" parser helpers which don't allocate a bunch of different strings onto the heap. (whole point of this little project is to reduce GC pressure in applications that do alot of string parsing).
basically if I have a char[] that contains {'1','2','3'}, I'd want to to be converted into 123.
I tried messing around with the stackalloc operator in C#, but its illegal to stackalloc a string unfortunately. I also googled around for converting a char[] into a numeric value, but all the solutions convert each individual char into their ASCII code, or convert the char[] into a string as an intermediate step.
I am trying to compile the following C code in C++ with visual studio 2010:
Code:
#include <windows.h>
#include <stdio.h>
void test(FARPROC addr) {
__try {
addr();
printf("ok
[Code] ....
But I get the compilation error: main.cpp(25): error C2440: 'type cast' : cannot convert from 'char [4096]' to 'FARPROC'
How would I make this compile in C++?
How do I convert a variable of type unsigned char to string.
View 9 Replies View RelatedHow can you convert int type to const char*
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