I have a fascination with Roman numerals and would like to create a C program that converts Roman numeral inputs to normal numbers.
I want to keep everything simple and only use the C library for the coding.
I am writing a program that converts arabic numbers into roman numerals.
Quote Write a program that asks the user to enter a number within the range of 1 through 10. Use a switch statement to display the Roman numeral version of that number.
Input Validation: Do not accept a number less than 1 or greater than 10.
Prompts And Output Labels. Use the following prompt for input: "Enter a number (1 - 10): ". The output of the program should be of the form "The Roman numeral version of A is R" where A is the Arabic numeral entered (1,2,3,...) and R is the all-capitals form of a Roman numeral, such as VII.
Here is the problem:"Write a program that converts a number entered in Roman numerals to a positive integer. Your program should consist of a class, say, romanType. An object of type romanType should do the following:
a. Store the number as a positive integer.
b. Convert and store the number as a positive integer.
c. Print the number as a Roman numeral or positive integer as requested by the user.
The integer values of the Roman numerals are:
M 1000
D 500
C 100
L 50
X 10
V 5
I 1
d. Test your program using the following Roman numerals: MCXIV, CCCLIX, MDCLXVI."I'm doing the best I can to understand the concept of the class. Here is what I have (which is not much thus far, and nowhere near correct I'm sure).
#include<iostream>
#include<iomanip>
using namespace std;
class romanType {
public:
void getRoman();
[code]....
This program compiles, but has a bunch of logical errors. I know my problem is somewhere in the while loop that I have, but I can't figure out where. Here are some of the issues I am experiencing:
1. At the beginning of the program it asks you to enter a number, and when you do it does nothing while proceeding to the while loop where I have it asking the same question
Code:
"Please enter a number between 1 and 20 (Enter 0 to stop)
";
cin >> num;
cout << endl;
I want to be able to eliminate that first statement but if I only run this in the loop without the above statement the program will display nothing on the screen and proceeds to stop.
2. This code runs fine, except that if you make a mistake, it will prompt you to enter a valid number, however; it ignores your first response if the number you enter is valid and asks you to enter a valid number anyway. Once you enter it a second time, it will accept it and the program will continue on.
Code:
while(num != SENTINEL) {
cout << "Please enter a number between 1 and 20 (Enter 0 to stop) ";
cin >> num;
cout << endl;
Also if you type in 0 on your first response, it will prompt you that it is not a valid number and ask you to try again, instead of stopping the program like it is supposed to do. On your second response the program will accept your 0 and stop the program correctly.
//Write a program that displays the roman numeral equivalent of any decimal number between 1 and 20 that the user enters. The roman numerals should be stored in an array of strings and the decimal number that the user enters should be used to locate the array element holding the roman numeral equivalent. The program should have a loop that allows the user to continue entering numbers until an end sentinel of 0 is entered.
Input validation: Do not accept scores less than 0 or greater than 20
#include <iostream>
#include <string>
using namespace std;
int main() {
// Declare constants and variables
const int romanNum = 21; // Size of the elements in the array
[Code] ....
So I am trying to write a program that converts roman numerals into decimal numbers. I so far have come up with:
Code:
#include <stdio.h>
#include <ctype.h> // importing the tolowerfunction
//variables
int decimal, total;
char numeral[];
[Code] .....
But each time I compile it, it times out as if it were hitting an infinite loop. I have a feeling that I am not passing an individual character to the roman_to_decimal function but am unsure why.
how to convert integers -> Roman Numerals using both if & switch statement.
View 3 Replies View Related#include "stdio.h"
#include <stdarg.h>
#include <math.h>
// Main Function
int main(void){
int number;
printf(" Please enter a number from 1-10? ");
scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
I've Been working on a program that acts as a form of Roman numeral calculator, I input Roman Numeral Characters, and the program (is suppose to) output the corresponding digits. *Not allowed to use for loops or arrays.
Input:
MCCXXVI
LXVIIII
+
Output:
The First number is 1226
The second number is 69
Arithmetic operation is +
the sum of 1226 and 69 is MCCLXXXXV (1295)
However, when I run the program:
input:
MCCXXVI
LXVIIII
+
Output:
The first number is 77
The second number is 76
Arithmetic Operation is +
The sum of 77 and 76 is (infinite loop of I's) (153)
I noticed that when I input MCCXXVI, it only takes the first character (I thought cin.get() was suppose to stop this?), and returns the ASCII decimal value of that, instead of the integer value that I assigned to each letter. Why i get an infinite loop, and how to fix it.
#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
using namespace std;
const int I_Value = 1;
const int V_Value = 5;
[Code] ....
About exercise 7 of chapter 10 of PPP (page 372): changing the calculator to gives us the result of the roman numerals, like XXI + CIV = CXXV.
At *first* time there are two solutions for solving it in my mind.
First is, giving each roman number to a function like the one existing in exercise 6 and then get their integer numbers and then calculate them by the calculator of chapter 7 and finally make a function to convert the result to roman mode. (simpler)
Second is to change the calculator from chapter 7 to calculate roman numbers inside itself and gives the result again in roman mode. (harder)
As an important step of ‘solving the problems’/’programming’, how can I make decision to choose a solution for solving a problem.
Write a function that generates 1000 normally distributed (Gaussian Probability Distribution) random numbers. Range should be between -3 and +3. Numbers should be double floating point.
There's more to it than that, but I've got it from there.
Program that reads in a normal text file and converts it into mobile phone text. that is if the word is 3 characters or less then ther is no changes to the word and if the word is four or more letters then remove all the vowels from the word except for vowels that are capitals.
View 5 Replies View RelatedWrite a function which takes two parameter of integer type and both parameters are positive integer. These number should be provided by the user of your program. The first parameter is lower than the second parameter. You function should be able to calculate the sum of the square of each of the numbers between the two inputs and should display that. Please write a main function to display the working of your function. Call the function at least three times by using some loop in the main function.
This is what I came up with but it is not correct:
#include <iostream>
using namespace std;
void sumsquares(int number1, int number2) {
int sum = 0;
for(int i = number1; i<number2; i++)
sum =sum+ i*i;
cout<<"The Result is: "<<sum<<endl;
[Code] .....
How to calculate the values between numbers that a user types in.
Write a function which takes two parameter of integer type and both parameters are positive integer. These number should be provided by the user of your program. The first parameter is lower than the second parameter. You function should be able to calculate the sum of the square of each of the numbers between the two inputs and should display that. Please write a main function to display the working of your function. Call the function at least three times by using some loop in the main function.
Write a program that computes a running sum of inputs from the user, terminating when the user gives an input value of 0
Using a while loop - no problem. Its only when I try to code it with a for loop that the program doesn't terminate with a 0 input. It terminates with a -1 input!!
while loop
#include <iostream>
using namespace std;
int main() {
float input=1;
float sum = 0;
[Code] ....
How to convert numbers into words using ragged dynamic arrays? this is my solution:
int main()
{
char *Units[]={"ZERO", "ONE", "TWO", "THREE","FOUR","FIVE", "SIX","SEVEN", "EIGHT", "NINE"};
char *teens []={"TEN", "ELEVEN", "TWELVE","THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN" };
char *hundreds []= {"HUNDRED"};
char *tens []={ "ZERO", "TEN", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"};
char *currency []={"Dollars"};
[code]....
I'm trying to get two numbers longer than long long int and add them together and multiply. I'm not sure how to convert the numbers to a string.
#ifndef BIG_INTEGER_H
#define BIG_INTEGER_H
#include "BigIntegerException.h"
class BigInteger {
private:
int biginteger[500];
int bigintegertwo[500];
[Code] .....
Write a c++program that asks the user to enter positive integer numbers without points between 0 and 999. Then check the amount and print in words. You need to use dynamic ragged arrays..
This is my solution but I'm not sure if this is the right way for dynamic ragged array???:
int main()
{
char *Units[]={"ZERO", "ONE", "TWO", "THREE","FOUR","FIVE", "SIX","SEVEN", "EIGHT", "NINE"};
char *teens []={"TEN", "ELEVEN", "TWELVE","THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN" };
char *hundreds []= {"HUNDRED"};
char *tens []={ "ZERO", "TEN", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"};
[Code].....
I'm working on a program and I need to convert big numbers to radix 64. I would like to shorter them whit conversion that's why I choosed base 64. I have two problems:
1. The conversion works only for not so big numbers. Untill about 2^32. I would like to convert bigger numbers. Is there any solution? (I thought on GMP/MPIR library, but I can't managed it.)
2. The conversion back to decimal base doesn't works, because I use 'strtoul()' which doesn't support bigger bases like 36.
Is there any good method for that?
The code should convert binary numbers to decimal but it doesn't..
Code:
#include <stdio.h>
#include <math.h>
#include <string.h>
int main()
{
[Code] ....
i want to convert in loop for example this
char number[]="54465465445646848640";
and in loop convert these element to int one by one.
Here`s the text:
You have to expect the following input : an arbitrary amount of lines, each line consists of 5 int32 numbers. The full input will be terminated by an EOF.
E.g.:
1 2 3 4 5
6 7 8 9 0
...
You`re then supposed to convert the numbers to integers and do some calculations. I would know how to parse a single line of 5 numbers via scanf(). That`s easy, and that`s exactly what they did in class.
But how do i go about splitting the lines? What about the EOF? Even if could hack something together, by using errno or something, it would be way beyond what they are doing atm. The input is received via user input, ie stdin.
Basically i am really close (i think) and the numbers im getting when i run it are weird like for instance i should get back a one if i enter in I or i but instead im getting like 178976087.
MAIN:
#include "stdafx.h"
#include "iostream"
#include <iomanip>
#include "romanType.h"
using namespace std;
int main() {
romanType r;
[Code] .....
I am supposed to convert a string made of many numbers between every number spaces are between, to an integer variable for every number..
How am I supposed to get over this problem?
Example: String: " 322 52 231"
Having problem with my code. i keep getting an error towards the bottom of the code. i need the user to enter a word. and with that word convert it to numbers. once i have convert it if it is bigger than 20 i have to add the two digits together and get print out the array that response to it.
example" ALEX
A=1
L=12
E=5
X=23
1+12+5+23= 41 //since its bigger than 20 you add 4 and 1 together so it will be 5. after that you print the 5th element of array
#include <iomanip>
#include <iostream>
#include <string>
using namespace std;
int main()
{
string name;
[Code]...
I have been playing around with .txt and .dat files lately. I only manage to load the files, but I don't seem to be able to load files using a variable.
Also modifying the data after it is imported is also currently problematic. I know how to go about the process without the need to import anything, but whenever I import the data I am having trouble modifying/ editing the ".txt" or ".dat" data.
Below is my current code:
#include <iostream>
#include <fstream>
#include <string>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
ifstream file;
ofstream result;
char in_file_name[8], out_file_name[8];
[Code] ....
Program to convert a date entered into roman numerals. I can only use one output prompt to get the date, so that makes it more difficult. Here is what i have, but how to go about the rest of it.
#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;
int array_date[20];
char I; // one
[Code] .....