C++ :: Enter Decimal Number Into Program And Required Base
Oct 12, 2013
You enter decimal number into the program and what base you want. The integer part of the decimal is being handled fine, but the decimal is not.
For example, I enter 15.6847 and base 10, which means I'm going from base 10 to base 10. It spits out 68469999999999 for the decimal part. (Do not worry about the first block of numbers. The second block seperated from the first by a space is where the decimal will appear in order.)
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
int baseConverter(int, int, int *, int *);
I had the idea to write a program that would convert a decimal integer into any base up to 36 (there are no letters after that) so I decided to give it a try.
Code: #include <stdio.h> #include <stdlib.h> char letters(int r); // prototypes function for converting 10's to A's and so on, base 11+ will work int main() {
int base; int d; //declares decimal integer int d_clone; // clones d for a loop
I got this algorithm of conversion and now I'm stuck at how to code it.
"Algorithm to Convert From any Base to Base 10 Decimal."
Let 'n' be the number of digits in the number. For example, 104 has 3 digits, so 'n'=3. Let 'b' be the base of the number. For example, 104 is decimal so 'b' = 10. Let 's' be a running total, initially 0.
For each digit in the number, working left to right do:
Subtract 1 from 'n'. Multiply the digit times b^n and add it to 's'.
When done with all the digits in the number, the decimal value should be 's' .
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
I need to create a generic function that changes from any starting base, to any final base. I have everything down, except my original function took (and takes) an int value for the number that it converts to another base. I decided to just overload the function. I am Ok with changing between every base, but am slightly off when using my new function to take in a string hex value.
The code below should output 1235 for both functions. It does for the first one, but for the second, I am currently getting 1347. Decimal to Hex works fine - It's just the overloaded function (Hex to anything else) that is slightly off.
void switchBasesFunction(stack<int> & myStack, int startBase, int finalBase, int num); void switchBasesFunction(stack<int> & myStack, int startBase, int finalBase, string s);
Write a program that prompts the user to enter an item#, the program should determine if the item is in the file and print the price of the corresponding item. If the item is not in the file an error message should be printed.
All I have so far is
string item_no=0; cout<<"Enter a item#"; getline(cin,item_no); if stream openData;
Create a program that will ask the user to enter a decimal value (1-999999) then display its corresponding binary numbers. Repeat this process until the value entered is equal to 0. Use the following Function Prototype:
void BinCodes(int value); Sample Input/Output: Enter a Decimal: 35 Binary: 100011 Enter a Decimal: 184 Binary: 10111000 Enter a Decimal: 0
I'm trying to create a program that allows the user to enter an unknown number of income and expense amounts. The program has to us see a while loop and display the income total, expense total, and total profit or loss. I've got it really close, but I'm doing the loop wrong. It counts the sentinel value (-1) towards the total, instead of just ending like it is supposed to.
#include <iostream> using namespace std; int main() { //declare variables double incomeInput; double expenseInput; double incomeTotal=0; double expenseTotal=0;
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111 Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010 Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102 Number entered is not a binary number
#include <iostream> using namespace std; int main() { int num;
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h> #include <math.h> char* ReverseString (char _result[]) { int start, end, length = strlen(_result); char swap; for (start = 0, end = length-1; start < end; start++, end--)
I have a code and am asked to modify it so that it will take as input as unsigned binary number up to 16 digits in length and convert it into its equivalent decimal number and output that decimal number.
All I know is that I use library function strlen() in <cstring> to calculate the length of the input string.
I also know I have to use something called pow(2,4);
//pow (); is found in cmath
I was told to use sum = sum >>16-l; (l is the length of />/>
#include <iostream> using namespace std; int main() {
using namespace std; void Conversion (int n); int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
