i need to code a function that converts an array of 64 bits into a hexadecimal value, the one is tested gives me correct value except for the last hexadecimal letter.
Code:
#include <iostream>
#include <stdio.h>
#include <conio.h>
#include <fstream>
#include <cstdlib>
#include <string>
typedef unsigned __int64 Ebyte;
#define length 64
[Code] .....
Code:
#include<stdio.h>#define MAX 1000
int main(){
char binaryNumber[MAX],hexaDecimal[MAX];
long int i=0;
printf("Enter any hexadecimal number: ");
scanf("%s",hexaDecimal);
[Code]...
So this is my current code, is there anyway I can reduce the size and use a main function to ask for input and a call function to do all the conversion and return it? I am confused for the past few days trying to figure it out and finally ended up here. Anyway can I write it as a something like this
Code:
int main()
{
//ask for user input hexadecimal into here and call a let's say hex2binary() function
}
int hex2binary(...)
{
//an array with dynamic memory, malloc? and convert it and return values
}
I don't really need the full code, just a simple instruction on how and where to start.
I have an array:
Code: int array1[]={0,1,1,0}
I need to convert the entire array to Hexadecimal.
My first thoughts to the approach was to convert the array to a string then strcmp but i cant seem to find how to convert an array to a string either.
How to convert the array to hexadecimal directly? or, How to convert the array to a string to be strcmp'ed?
#include <iostream>
#include <iomanip>
#include <string>
#include <sstream>
[Code]...
1)What should be the best variable for adding two 6-digit hexadecimal,such as 0034AD,0057EA? I would like to use array of character but it seems hard to handle.
I'm trying to convert 4 hex register into floating point value using IEEE 754 floating point format. My device will reply 4 register value. The problem is that it always reply for example 0x10 as 10 when i use getc() hence using char variable to store it is not ideal.
Code:
union {
char c[4];
float f;
} conv;
How to search in C or C++ a hexadecimal patterns within a binary file.
For example:
String1:
Code: 0x44 0x65 0x07
Then, once found, extract those 3 bytes and the next 11 bytes (14 bytes in total).
Finally, from those 14 bytes, print without spaces "bytes 1 to 6", "bytes 6 to 12", and byte "13 to 14".
Then I would like to print last 2 bytes (13 to 14) joined in decimal format.
The output without any conversion would be:
Code:
446507c90688 888000800005 0015
4465072ec918 059173495269 002C
44650700cc01 01811bc90b00 00AB
But the output converting to decimal the last 2 bytes would be:
Code:
446507c90688 888000800005 21
4465072ec918 059173495269 44
44650700cc01 01811bc90b00 171
The sample file is attached, and looks like this:
Code:
06 00 00 80 00 00 00 80 09 3c c9 06 88 88 80 00
80 00 44 65 07 c9 06 88 88 80 00 80 00 05 00 15
37 06 01 00 00 01 00 65 00 00 00 02 00 00 02 00
18 00 00 00 03 00 00 03 00 17 00 00 00 04 00 00
[Code] .....
The program is supposed to convert a two digit hexadecimal number to its binary representation. My code runs without any problems but I do not know how to limit the user's input to two digits only. For example the person can input "1ABC" and the program will give the binary representation and I need it to only accept two digit only like for example "1A".
#include<stdio.h>
#define MAX 1000
int main(){
char binaryNumber[MAX],hexaDecimal[MAX];
long int i=0;
printf("Enter a two digit hexadecimal number: ");
[Code] ....
Write a program in c++ to accept a number and convert this number into binary or hexa decimal or octal number according to the user choice using the concept of array.
View 6 Replies View Relatedprivate void button1_Click(object sender, EventArgs e) {
if (openFileDialog1.ShowDialog() == DialogResult.OK) {
TxtPath.Text = openFileDialog1.FileName;
} string connString = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source="+TxtPath.Text+"";
DataSet ds = new DataSet();
[Code] .....
How do I convert ifstream to binary and display the binary at the end. I have a file that when it contains numbers it can do it but when reading strings it has trouble. It acts as if there is no binary in the file.
View 17 Replies View RelatedI had an exercise to convert from decimal to binary with base 2, it was simple simple i did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
[Code] .....
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ......
The code should convert binary numbers to decimal but it doesn't..
Code:
#include <stdio.h>
#include <math.h>
#include <string.h>
int main()
{
[Code] ....
I had an exercise that required me to convert a number to binary (base 2) which as simple enough.
Code:
#include <iostream>#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ....
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
Code:
#include <stdio.h>
#include <stdlib.h>
#define MAX_LEN 20
void translate_dec_bin(char s[]){
char st[sizeof(unsigned)*20] = { 0 };
}
[code]....
Platform : c++, compiler: GNU gcc
I am new to programming and have written the code for the following program.
PROGRAM: Input 2 arrays => arrays 1 and 2 from the user each containing 5 elements. Sum is another array which is sum of elements of array 1 and array 2. Convert each of the elements of the sum array into binary. Count number of 1's in each binary element and output it to another array "arr".
Example: arr1 = {1,2,3,4,5}
arr2 = {6,7,8,9,10}
sum = {7,9,11,13,15}
binary of 7 [111], 9[1001], 11[1011], 13[1101], 15[1111]
No of 1's in 7 [3], 9 [2], 11 [3], 13 [3], 15 [4]
arr array will be {3, 2, 3, 3, 4}
I am not getting the desired output. My code is:-
include <iostream>
using namespace std;
int main() {
int array1[5];
[code].....
What is the difference between the two functions below? I created the function in the top and my friend created the function in the bottom. I just want to know why the function with the while loop prints the binary numbers backwards. And the recursive function prints the binary numbers correctly.
void findBinary(int num) {
int remainder = 0;
while ( num > 0) {
remainder = num % 2;
cout << remainder;
num = num / 2;
[Code] .....
So if I have an array how do I convert it to a balance binary tree?
View 1 Replies View RelatedI'm trying to write a program that takes input from the user (thats a char) and outputs it to the monitor in hex form.The program is meant to continuously take input from the user then output to the monitor in hex form until an EOF is detected this triggers the program to close.The following code does this except that I get a lower case 'a' at the end of each output.
example:
input from user: ABC
output to monitor: 41 42 43 a
#include <stdio.h>
int main(void) {
char myChar;
[Code]....
I want to convert a decimal number to binary and store it in a string so that I can use that binary output for later computation. Here is what I did
Code:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void main()
[Code] ....
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){
char* binNum = decToBin(25);
int i = 0;
while(binNum != NULL){
[Code].....
The problem is that I want to write a C++ program that converts an ordinary text file into binary and then reads that binary file and converts it to text file so that this text file equals to first text file. I have wrote this code for it.
int main() {
string name1 = "first", name2 = "sec", name3 = "third";
int j = 0, k = 0;
ifstream ifs(name1.c_str()); // Here I want to read from the ordinary text file (name1).
[Code] .....
Now what the ofs.write(as_bytes(j), sizeof(int)); or ifs.read(as_bytes(k), sizeof(int)); exactly mean?
In practice, the file name1 contains digit 5 and its size is 1 byte. The name2 contains some character/sign like [] and its size is 4 bytes and name3 contains digit 0 and its size is 1 byte, why? I before have created the name1 file in ordinary text file mode.
My machine is Windows 7 32-bit. My compiler is MVS 2012.
How to convert an ordinary text file into binary and how to convert that binary file back to a text file so that the first text file equals with the last text file?
View 8 Replies View RelatedI am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3
10110101
11111111
10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
I am attempting to write a program that converts binary to base10, and vice versa.
But in the function for converting Base10 to Binary, just as it reaches the line of code
int* binary = new int [a];
it skips straight to the int main()
All I'm attempting to do with that line of code is initialize the variable "a" into the elements of the array "binary".
[URL] ....
I am having an issue with my sort function. This is one part of the Hash table program. The main issue is that I am trying to sort the pointer table after all of the values have been entered. The ptr_sort function is not a class function and so I am therefore unable to use the class variables psize and pTable. Is there another way I should be trying this? it is a Vector should I use the sort() function from the vector class in STL?
#include "/home/onyuksel/courses/340/progs/13f/p9/util9.h"
#include "/home/onyuksel/courses/340/progs/13f/p9/hTable.h"
#ifndef H_TABLE1
#define H_TABLE1
void ptr_sort ( );
[Code] ....
If a user enters a string of boolean algebra it will ouput the table.
I have input parsing, cycling through the combinations, and outputing working. However once i parse the input I am not sure what to do with it. I have thought of having it write the parsed input to a new file as a function and then use that function, but that seems bad.
How to dynamically create the function, how to implement it.
BTW This is a console function, if that changes anything.