C++ :: Convert Each Of Elements Of Sum Array Into Binary
Nov 9, 2014
Platform : c++, compiler: GNU gcc
I am new to programming and have written the code for the following program.
PROGRAM: Input 2 arrays => arrays 1 and 2 from the user each containing 5 elements. Sum is another array which is sum of elements of array 1 and array 2. Convert each of the elements of the sum array into binary. Count number of 1's in each binary element and output it to another array "arr".
Example: arr1 = {1,2,3,4,5}
arr2 = {6,7,8,9,10}
sum = {7,9,11,13,15}
binary of 7 [111], 9[1001], 11[1011], 13[1101], 15[1111]
No of 1's in 7 [3], 9 [2], 11 [3], 13 [3], 15 [4]
arr array will be {3, 2, 3, 3, 4}
I am not getting the desired output. My code is:-
include <iostream>
using namespace std;
int main() {
int array1[5];
[code].....
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Feb 4, 2014
I'm just learning and C. Here is a code snippit from a program that will compile. It's function is to validate credit card numbers. I have an error I can't find though. the last print statement shows the conversion in reverse string (as integers). Here is the code:
int main (void)
{
char cn[17];
char *cardtype;
int n0,n1,n2,n3,n4,n5,n6,n7,n8,n9,n10,n11,n12,n13,n14, n15;
int s1,s2,s3,s4,s5,s6,s7,s8;
int oddsum;
int sum;
int total;
int validate;
}
[code]....
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[Code] .....
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So if I have an array how do I convert it to a balance binary tree?
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Mar 3, 2013
I am attempting to write a program that converts binary to base10, and vice versa.
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[URL] ....
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Dec 7, 2014
I had an exercise to convert from decimal to binary with base 2, it was simple simple i did the following:
Code:
#include <iostream>
#include <iomanip>
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void Conversion (int n);
[Code] .....
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ......
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Mar 27, 2013
The code should convert binary numbers to decimal but it doesn't..
Code:
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#include <math.h>
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int main()
{
[Code] ....
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I had an exercise that required me to convert a number to binary (base 2) which as simple enough.
Code:
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using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ....
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Code:
#include <iostream>
#include <stdio.h>
#include <conio.h>
#include <fstream>
#include <cstdlib>
#include <string>
typedef unsigned __int64 Ebyte;
#define length 64
[Code] .....
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Nov 15, 2013
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
Code:
#include <stdio.h>
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#define MAX_LEN 20
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char st[sizeof(unsigned)*20] = { 0 };
}
[code]....
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Jul 11, 2014
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[Code] .....
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Apr 16, 2014
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Code:
#include<stdio.h>
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void main()
[Code] ....
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Code:
#include<stdio.h>#define MAX 1000
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scanf("%s",hexaDecimal);
[Code]...
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Code:
int main()
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}
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//an array with dynamic memory, malloc? and convert it and return values
}
I don't really need the full code, just a simple instruction on how and where to start.
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[Code] .....
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My machine is Windows 7 32-bit. My compiler is MVS 2012.
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------------- My Subroutine ----------------------------------------------------------------------
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[Code] ....
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Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111
Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010
Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102
Number entered is not a binary number
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int main()
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int num;
[code]....
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This is what I have.
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