C++ :: No Operator Found Which Takes A Right-hand Operand Of Type Double
May 17, 2014
while (getline(inStream, line))
{
while (inStream >> Student.getId() >> Student.FNAME >> Student.MINIT >> Student.LNAME >> Student.GENDER >> Student.UNITS >> Student.getGpa())
{
while (Student.getId() != id)
{
outStream << line << endl;
}
}
}
This is what I have right now. It shouldn't be a problem, but for some reason I am getting an error trying to >> Student.getGpa()
Error1error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'double' (or there is no acceptable conversion)c:location1301Project 5
I will post more code if needed, but... I just don't know. I have a TON of code so I would rather not if I don't have to.
I get Error this error. Did I miss something or is that some kind of bug?
Code: error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'const std::string' (or there is no acceptable conversion)301
Code: 2IntelliSense: no operator "<<" matches these operands operand types are: std::ostream << const std::string307
I see that the function itself does not return anything but calls another function. The main difficulty I have is with the "dev->dev->" operator, where dev, I expect is a pointer to a structure.
Code: #include <stdio.h> #include <stdlib.h> int main() {
[Code].....
he problem is that when I print out the three sums at the end of the program I dont get any decimal points but just zeros like something.00 instead of something.50 etc
Can you use data type double or float for an array? ie
double n[]; or float a; float m[a];
My code wont accept me changing the data type..will on accept int data type. I get the following error when I try to change the array to double or float..
3310E:C++vector.cpp[Error] invalid types 'double [1000][double]' for array subscript
I am wondering why return type for an assignment operator cant be a void or int? Cant I write assignment operator for student class like this as we do nothing with returned value?
Student { char name[20]; int marks; public: student(char*name,int marks)
The following code compiles and runs fine till it reaches line 16 and gets a sigsev violation which I'm not sure about as to why. I have no problem passing the object of type node** into the constructor of base and storing it into the double pointer node** copy;; but when I call the function void pass(node** temp) it crashes.
#include <iostream> class base; class node { private: node** data; public:
I need to write a function that will merge the content of two sorted arrays of type double values. The function should not assume that both its input parameter arrays are the same length.
Here is my program so far - I know there is alot of errors and mistakes:
I cannot get my function overloading the input operator for rational type objects to work.
lab9.cpp: In function ‘std::istream& operator>>(std::istream&, const rational&)’: lab9.cpp:186:20: error: invalid initialization of reference of type ‘std::istream& {aka std::basic_istream<char>&}’ from expression of type ‘rational’ return (inputFrac);
lab9.h
#include <iostream> using namespace std; class rational { public: rational(); rational(int a, int b);
Write a program that scores a blackjack hand. In blackjack, a player receives from two to five cards. The cards 2 through 10 are scored as 2 through 10 points each. The face cards - jack, queen, and king are scored as 10 points. The goal is to come as close to a score of 21 as possible without going over 21. Hence, any score over 21 is called "busted". The ace can count as either 1 or 11, whichever is better for the user. For example, and ace and a 10 can be scored as either 11 or 21. Since 21 is a better score, this hand is scored as 21. An ace and two 8s can be scored as either 17 or 27. Since 27 is a "busted" score, this hand is scored as 17.
The user is asked how many cards she or he has, and the user responds with one of the integers 2,3,4, or 5. The user is then asked for the card values. Card values are 2 through 10, jack, queen, king, and ace. A good way to hande input is to use the type char so that the card input 2, for example, is read as the character '2', rather than as the number 2. Input the values 2 through 9 as the characters '2' through '9'. Input the values 10, jack, queen, king, and ace as the characters 't', 'j', 'q', 'k', and 'a'. (Of course, the user does not type in the single quotes.) Be sure to allow upper - as well as lowercase letters as input.
After reading in the values, the program should convert them from character values to numeric card scores, taking special care for aces. The output is either a number between 2 and 21 (inclusive) or the word Busted. Use fucntions, multiway branches, switch statements or nested if-else statements. Your program should include a loop that lets the user repeat the calculation until they are done doing so.
The code runs properly for the first card but then it asks if the user wishes to repest the program. I need to claculate the value of all cards before it asks for that. Here is my code:
#include <iostream> using namespace std; int main() {
I am creating a right hand maze solution, and it actually works for the most part, but it gets stuck at the sixth spot and will not proceed any further. I cannot seem to find my error even though I know it's probably a small one in my code, here is what I have at the moment:
How do you add a value to the beginning of a string instead of the end?
This is for an assignment and I have to convert the user input (always assuming its a valid decimal number) to binary and store it in a string. I've got up to dividing by two to get the remainder ...
I almost finished a program but am stuck on sorting the hand im dealing with qsort. sorting by the face values and if they have the same faces im suppose to follow this suit order to determine which one is greater (Clubs, Diamond, Hearts, and Spades) how would i adjust my comparator function to do this for me ?
I am having problems compiling this program. line 29 causes the error "left operand must be l-value".
// chap5proj.cpp : Defines the entry point for the console application. // # include <stdafx.h> # include <iostream> using namespace std; int main() { double mph, time, disPerHour, milesTrav;
I am getting this error when compiling my program with quincy:
Error: I value required as left operand of assignment
The program is meant to calculate how much parking costs based on the amount of hours in a park and what type of vehicle it is. the error is coming from my function definitions which i have just started to add in.
Code: float calcCarCost (char vehicletype, int time, float car) { if ((time > MINTIME) && (time <= 3)) calcCarCost =( CAR * time ); }
The error is on line 72 which is: calcCarCost =( Car * time);
I should probably point out CAR is already defined as a constant with a numerical value given and time is previously asked to be input in when the program runs.
The issue arises with case 3 where it tells produces an error when I attempt to compile and says "lvalue required for left operand of assignment error". How to fix this so that I can properly run the program.
