C++ :: Operand Types Are Incompatible
Oct 14, 2013#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main() {
double temp, result;
char type;
[Code] .....
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C :: Error - Incompatible Types In Assignment
Oct 11, 2013I am working on a double linked list and inside of my function to insert a node, I am getting an error of "Incompatible types in assignment". Here is my function code. Line 55 is where I am receiving the error.
Code:
45 struct lnode *ins_llist(char data[], struct llist *ll){
46 struct lnode *p, *q;
47
48 q = malloc(sizeof(struct lnode));
49 if ( q == NULL )
[Code]....
C :: Errors For Incompatible Types In Return
Oct 23, 2013I am writing a program in C. The following is an extract from my code:
Code:
enum coin_types{
FIVE_CENTS=5,
TEN_CENTS=10,
TWENTY_CENTS=20,
FIFTY_CENTS=50,
ONE_DOLLAR=100,
TWO_DOLLARS=200
[Code] .....
I'm getting the following errors:
For: new = new_coins_data_line(line);
"Incompatible types in assignment"
For: return newdata;
"Incompatible types in return"
There seem to be problems with my variables and perhaps it is related to the type 'struct coin' which has an enumerated type within it.
C :: Convert Characters From Array Into ASCII Integers - Incompatible Types Error
Nov 22, 2013The code is supposed to convert characters from an array into their respective ascii integers, and append a 0 if the number is less than 3 digits long. It then supposed to put it all together into one string.
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
char file[] = "This is a test";
char *ptr = file;
int length = strlen(file);
int i, numbers[length];
[Code] .....
C :: Parameter Names Without Types And Conflicting Types In Fgets
Jan 22, 2014I have this
Code:
#include<stdio.h>
#include<ctype.h>
#include<string.h>
int check_up(char string[]);
int check_low(char string[]);
void to_up(char string[]);
void to_low(char string[]);
[Code] .....
When I compile this I have the following problems: warning: data definition has no type or storage class [enabled by default] in 'to_up(word)'conflicting types in 'to_up' function and to_low function warning: data definition has no type or storage class [enabled by default] into_up function error: unknown type name "word" in line 'printf("All uppercase %s. ", word):;'warning: parameter names (without types) in function declaration [enabled by default] in 'to_up(word)'and 'to_low(word)' 'note: previous declaration of "to_up" was here in function declaration of to_up function
C/C++ :: Reverse Polish Notation Not Doing Second Operand
Sep 24, 2014been working on this code til my eyes bled, can not get second operand to work, if i enter 1 2 3 + - it will only return 5 from the addition operand.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
[Code].....
C/C++ :: Compiler Error / Left Operand Must Be L-value
Oct 15, 2014I am having problems compiling this program. line 29 causes the error "left operand must be l-value".
// chap5proj.cpp : Defines the entry point for the console application.
//
# include <stdafx.h>
# include <iostream>
using namespace std;
int main() {
double mph, time, disPerHour, milesTrav;
[code]....
C :: Error - I Value Required As Left Operand Of Assignment
Apr 21, 2013I am getting this error when compiling my program with quincy:
Error: I value required as left operand of assignment
The program is meant to calculate how much parking costs based on the amount of hours in a park and what type of vehicle it is. the error is coming from my function definitions which i have just started to add in.
Code:
float calcCarCost (char vehicletype, int time, float car)
{
if ((time > MINTIME) && (time <= 3))
calcCarCost =( CAR * time );
}
The error is on line 72 which is:
calcCarCost =( Car * time);
I should probably point out CAR is already defined as a constant with a numerical value given and time is previously asked to be input in when the program runs.
C :: Lvalue Required For Left Operand Of Assignment Error
Oct 18, 2013The issue arises with case 3 where it tells produces an error when I attempt to compile and says "lvalue required for left operand of assignment error". How to fix this so that I can properly run the program.
View 5 Replies View RelatedC++ :: Error - LValue Required As Left Operand Of Assignment
Jan 1, 2014I get the following error:
pointers_array.c: In function ‘readlines’:
pointers_array.c:42:37: error: lvalue required as left operand of assignment
I know what the error is saying but what it is giving it with this code:
/* readlines: read input lines */
int readlines(char *lineptr[], int maxlines) {
int len, nlines;
char *p, line[MAXLEN];
nlines = 0;
[Code] ....
C++ :: VS 2013 - No Operator Found Which Takes A Right-hand Operand
Dec 3, 2014I get Error this error. Did I miss something or is that some kind of bug?
Code:
error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'const std::string' (or there is no acceptable conversion)301
Code:
2IntelliSense: no operator "<<" matches these operands
operand types are: std::ostream << const std::string307
Code:
#include <iostream>
#include <fstream>
using namespace std;
const string Alphabet1 = "abcdefgijklmnopqrstuvwxyz";
[Code] .....
C++ :: No Operator Found Which Takes A Right-hand Operand Of Type Double
May 17, 2014while (getline(inStream, line))
{
while (inStream >> Student.getId() >> Student.FNAME >> Student.MINIT >> Student.LNAME >> Student.GENDER >> Student.UNITS >> Student.getGpa())
{
while (Student.getId() != id)
{
outStream << line << endl;
}
}
}
This is what I have right now. It shouldn't be a problem, but for some reason I am getting an error trying to >> Student.getGpa()
Error1error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'double' (or there is no acceptable conversion)c:location1301Project 5
I will post more code if needed, but... I just don't know. I have a TON of code so I would rather not if I don't have to.
C++ :: Socket Program - Lvalue Required As Left Operand Of Assignment
Feb 5, 2013I got above error in my program. My program is socket program. I am using ubuntu 11.10.
#include <netdb.h>
#include <netinet/in.h>
#include <string.h>
#include <cstdlib>
#include <iostream>
#include <stdio.h>
#define PORT 4547
/*int parseARGS(char **args, char *line) {
[Code] ....
C :: Incompatible Integer To Pointer Conversation
Nov 28, 2013I am getting error"incompatible integer to pointer conversation..." and don't know how to fix this. In my code, user inters line like this (3+3*(55-52)) I need to separate number from the line so I can do other operation.here is my code
Code:
#include <stdio.h>
#include <stdlib.h>
#include<string.h>
int main(){
[Code]....
C/C++ :: Return From Incompatible Pointer Type
Jul 13, 2014/*
* symboltable.c
*/
#include "symboltable.h"
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "include/utlist.h"
[Code] ....
C++ :: Vector Iterators Incompatible In Debug Mode
Jul 11, 2013I get this error when i try to run this code for an inventory in debug mode in VS. But for some reason it works just fine in release mode.
void Push_Back_Item(Item *item){
for(int y = 0; y < InvSizeY; y ++)
for(int x = 0; x < InvSizeX; x ++){
auto Iter = ItemList.find(std::make_pair(x,y));
if(Iter != ItemList.end()){
item->SetDead(); // ERROR
}
}
}
This isnt the full code though but it still gives me the same error.
The only thing "item->SetDead()" does is to set a bool to true.
This is the map i get the iterator from
std::map<std::pair<int,int>,Item*> ItemList;
This have been bugging me for quite some time now.
C/C++ :: Warning / Assignment From Incompatible Pointer Type
Apr 17, 2014I'm working on a program and everything works except for the follow function:
void swapHex(int x, int byte1, int byte2) {
unsigned char *b1, *b2, tmpc;
printf("%d in hex is %x
", x, x);
printf("swapping byte %d with byte %d
", byte1, byte2);
[Code] ....
I get the following errors when compiling:
In function "swapHex":
warning: assignment from incompatible pointer type
warning: assignment from incompatible pointer type
C/C++ :: Error - Initialization From Incompatible Pointer Type
Apr 8, 2012Below is my code snippet.I'm getting "Error:initialization from incompatible pointer type" error on line 'int *q = status;'.
Obviously, I'm missing something but has no clue...:(
void findwalls(int *p,int y,int x){
int status[y_count][x_count][4];
int *q = status;
for(int i = 0;i < (y_count * x_count * 4);i++)
*(q + i) = *(p + i);
C :: Function To Read A Text File - Incompatible Pointer Type
Nov 3, 2014So for a project, my professor sent out two pages of code containing functions to read a text file (since we do not know how to write this on our own yet). I've got the code working on Orwell IDE and it gives me 2 warnings saying
"Passing argument 1 of 'readFromFile' from incompatible pointer type"
"Passing argument 2 of 'option2Print' makes integer from pointer without a cast"
The Orwell IDE seems to just bypass these warnings and compiles the code correctly. However, when I transferred my files over to my desktop using BloodShed (what the professor uses), instead of getting a warning I get an error and the code won't compile.
I assume it will not compile on his computer either since he uses the BloodShed IDE.
I don't know how to put the code directly into the text neatly, so a attached a .zip file with my code. The "storms.txt" file is also included. (the file that will be read).
C++ :: Generic Linked List Compilation Errors / Incompatible Pointer Type
May 19, 2014I am trying to write a generic linked list in c, but for some reason i keep getting errors saying "incompatible pointer type. This is the code and erros:
#ifndef SLIST_H
#define SLIST_H
#include <stdlib.h>
typedef struct {
void *data;
slist_elem *next;
[code]....
C :: Passing Argument Of Incompatible Pointer Type - Warning In Function Call In Main
Jun 4, 2013Code:
#include <stdio.h>
#include <stdlib.h>
int size_b_row1;
int size_b_col1;
[Code].....
C++ :: Passing Arguments From Incompatible Pointer Type - Warning In Function Call Transpose In Main Routine
Jun 4, 2013#include <stdio.h>
#include <stdlib.h>
int size_b_row1;
int size_b_col1;
int main(void) {
double C[4][4] = {{1,3,5,2},{7,6,2,2},{1,2,7,3},{2,3,5,3}};
double TC[4][4];
transpose(C, TC);
[Code] ......
C++ :: Using New On Primitive Data Types
Dec 12, 2014int* count;
count = new int(1); // what???
Is this on the heap?? do i have to delete it now?
So is 'new' on a primitive data type just a way for me to allocate primitive data types (int, char, etc.) on the heap instead of the stack?
And, out of curiosity, can you do that in Java?
C++ :: How To Convert Data Types
Jan 9, 2015How to convert these data types? i have an array of bytes in unsigned char[] array, and need to convert to const void* pointer.
View 3 Replies View RelatedC++ :: Object That Contains 2 Types Of Data
May 24, 2014How do you create an object (like in the title) something more simple than a struct? I wanna know that cuz I'm writing a function that could return a boolean and an integer at the same time.
View 2 Replies View RelatedC# :: Working With Different Types And Casting?
Jan 3, 2015double a = 1.0 + 1 + 1.0f; //everynumber will be added up as a double even the last one which is a float. All 3 numbers will turn into 3.0 as a double.
int x = (int)(7 + 3.0 / 4.0 * 2); //the variable will do the math bracket first. then the va type will still be an int because int was never changed.
Console.WriteLine((1 + 1) / 2 * 3); // 1 + 1 will be done first then 1 / 2 then * by 3
Console.WriteLine(x);
Console.ReadKey();
I THINK THATS ALL WRONG ^ =/ like the comments
double a = 1.0 + 1 + 1.0f;
In this equation, everything is using addition, so we start working left to right. 1.0 + 1 is the first step. These two representations of 1 aren't the same type though. In fact, none of the three are.
The first is a double, the second is an int, and the last is a float.
So in order to do 1.0 + 1, we need to convert one type to another. Since the double type is "wider" than the int type, we'll move things up to the double type. We'll convert the int version to a double, and to 1 + 1 using double types, resulting in 2.0 as a double.
Next we do the other addition. This has the same problem, though, because we'll be adding our result from the first step (a 2 as a double) to a float. So again, the float gets converted up to a double and we do the addition using doubles.
We now have a value of 3 that is the double type, which we can simply store in our a variable without any conversions at all, since our value is already a double type.