How do you add a value to the beginning of a string instead of the end?
This is for an assignment and I have to convert the user input (always assuming its a valid decimal number) to binary and store it in a string. I've got up to dividing by two to get the remainder ...
#include<conio.h>
#include<alloc.h>
#include<string.h>
struct node
[Code]....
I have a question concerning the CDialogBar (:CControlBar).
I have a MDI application with a dockable toolbox (CDialogBar).
The user is able/allowed to move the DialogBar and to dock it at the right or left side When I dock at the left side, the content of my mdi-application (so all other open windows) are moved right (so the dockable bar moves the windows).
If i dock at the right side, nothing changes.
How can I change the behaviour of the bar, that the windows inside the application keep the same position when I dock left ?
(Problem is, that my windows are aligned on the right side of the application). When I dock the bar on the left, the windows are getting moved in the not visible area.)
Write a program that scores a blackjack hand. In blackjack, a player receives from two to five cards. The cards 2 through 10 are scored as 2 through 10 points each. The face cards - jack, queen, and king are scored as 10 points. The goal is to come as close to a score of 21 as possible without going over 21. Hence, any score over 21 is called "busted". The ace can count as either 1 or 11, whichever is better for the user. For example, and ace and a 10 can be scored as either 11 or 21. Since 21 is a better score, this hand is scored as 21. An ace and two 8s can be scored as either 17 or 27. Since 27 is a "busted" score, this hand is scored as 17.
The user is asked how many cards she or he has, and the user responds with one of the integers 2,3,4, or 5. The user is then asked for the card values. Card values are 2 through 10, jack, queen, king, and ace. A good way to hande input is to use the type char so that the card input 2, for example, is read as the character '2', rather than as the number 2. Input the values 2 through 9 as the characters '2' through '9'. Input the values 10, jack, queen, king, and ace as the characters 't', 'j', 'q', 'k', and 'a'. (Of course, the user does not type in the single quotes.) Be sure to allow upper - as well as lowercase letters as input.
After reading in the values, the program should convert them from character values to numeric card scores, taking special care for aces. The output is either a number between 2 and 21 (inclusive) or the word Busted. Use fucntions, multiway branches, switch statements or nested if-else statements. Your program should include a loop that lets the user repeat the calculation until they are done doing so.
The code runs properly for the first card but then it asks if the user wishes to repest the program. I need to claculate the value of all cards before it asks for that. Here is my code:
#include <iostream>
using namespace std;
int main()
{
[Code].....
I am creating a right hand maze solution, and it actually works for the most part, but it gets stuck at the sixth spot and will not proceed any further. I cannot seem to find my error even though I know it's probably a small one in my code, here is what I have at the moment:
#include "stdafx.h"
#include <iostream>
#include <Windows.h>
[Code].....
I almost finished a program but am stuck on sorting the hand im dealing with qsort. sorting by the face values and if they have the same faces im suppose to follow this suit order to determine which one is greater (Clubs, Diamond, Hearts, and Spades) how would i adjust my comparator function to do this for me ?
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define DECK_SIZE 52
struct card {
const char *face;
const char *suit;
[code]....
I get Error this error. Did I miss something or is that some kind of bug?
Code:
error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'const std::string' (or there is no acceptable conversion)301
Code:
2IntelliSense: no operator "<<" matches these operands
operand types are: std::ostream << const std::string307
Code:
#include <iostream>
#include <fstream>
using namespace std;
const string Alphabet1 = "abcdefgijklmnopqrstuvwxyz";
[Code] .....
while (getline(inStream, line))
{
while (inStream >> Student.getId() >> Student.FNAME >> Student.MINIT >> Student.LNAME >> Student.GENDER >> Student.UNITS >> Student.getGpa())
{
while (Student.getId() != id)
{
outStream << line << endl;
}
}
}
This is what I have right now. It shouldn't be a problem, but for some reason I am getting an error trying to >> Student.getGpa()
Error1error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'double' (or there is no acceptable conversion)c:location1301Project 5
I will post more code if needed, but... I just don't know. I have a TON of code so I would rather not if I don't have to.
On a right angled triangle, if the user inputs only ONE side length (not the hypotenuse) and only ONE angle, what code is required to work out the hypotenuse? I know how to work out the final side and the remaining angle once I have this.
View 4 Replies View RelatedI know this question must have been asked before, but the problem that I am facing is that I am using a library PoDoFo to parse PDF files. It seems that it is only compatible with C++.
Now I want the application to be web-based. That is, the user uploads a PDF file on the server, the server parses it and the parsed content is then sent back to the user.
Is such a thing possible with C++, or maybe any good work-arounds? Or should I look at server-side scripting languages like PHP and their respective libraries?
A sequence point in a C program is defined as "Any point in a program's execution at which it is gauranteed that all side effects of previous evaluations will have been performed and no side effects from subsequent evaluations have yet been performed."
What is a side effect?
I am working on a 2D side scroller game. Where a ball is moving continuously towards right . I used a camera to follow the ball as soon as ball reaches the center of screen. I created a horizontal line to look like the surface on which the ball is rolling.
line runs from x=0 to x=800 (i.e screen width)
NOTE: (0,0) coordinate is at top left corner of display.
Problem: My display is 800 x 400 . Camera follows the ball, but soon the ball crosses x=800 and starts moving in black background. I want that line surface to stay there instead of going out of bound.
Additionally! I generated obstacles from x=800 which also move out of bound along with my line.
What should be done here? This is just my first c++ game project, so i might be skipping things that can solve the issue.
[Update] these screenshots manage to show, what the real problem is: [URL]
Assuming that we have the string :
Code:
***HELLO&SIR. & and * is the delimiters.
My question is how strtok will work in the beginning?
According to this to determine the beginning and the end of a token, the function first scans from the starting location for the first character not contained in delimiters (which becomes the beginning of the token). And then scans starting from this beginning of the token for the first character contained in delimiters, which becomes the end of the token. The scan also stops if the terminating null character is found.
This end of the token is automatically replaced by a null-character, and the beginning of the token is returned by the function. strtok will replace the first * with '' and the next call will start from the second * puts '' there and again the same with the third * ?
I want to calculate the total some of delay pf receiving Side Packet . Code is as Follow ..
What is weird that even if i invoke a sleep of 2 sec ,than its show delay always zero. Delay will be in microsec ..Is there any problem with logic or anything else..
Code:
do
{#pragma omp parallel private(nthreads, tid) {
/* Obtain thread number */
tid = omp_get_thread_num();
if (tid == 0) {
nthreads = omp_get_num_threads();
[Code]...
[URL]
According to my project instructions, I have to make a "validation on the delete button, that before a record can be deleted it will check to see if the count of "In-Progress" orders for that product is 0. If it is greater than zero, it should not allow this record to be deleted."
So far I have on the code behind page:
protected void btnDeleteProduct_Click(object sender, EventArgs e)
{
DataView dv = (DataView)SqlOrders.Select(DataSourceSelectArguments.Empty);
[Coe].....
The professor said I have to: "As for getting the count, check your notes and book, specifically looking at SQL and the Aggregate functions. There is a function we talked about in class called "Count(OrderID)" and set the where clause to check for the productID.
Right after I close FIFO on the producer side, the app on the consumer side gets into an endless loop. select() returns that FIFO is ready to read. Below is the excerpt from the consumer code. The FIFO is opened "blocking" on both ends.
Code:
FifoClass fifo_r = FifoClass("/tmp/FIFO_READ");
int fdr = fifo_r.OpenR();// this->fd = open(name.c_str(), O_RDONLY , 0);
for(int i=0; ;i++) {
FD_ZERO(&rset);
FD_SET(fdr, &rset);
[Code] .....
I am writing another program and I cannot find for the life of me how to loop the program back to the start of a function.
Code:
#include <stdio.h>
#include <stdlib.h>
int main(void) {
int choice;
char band1, band2, band3, band4;
printf ("This program calculates the resistor value based on the colours of the wire.
(enter the integer near the command)
");
printf ("What would you like to do?
[Code].....
This is my current iteration of the program. Obviously, I haven't finished writing the case 1 of the first switch, but for the other ones. I thought that return main would cause the program to loop back to the beginning after executing the case, but I see that it is not the case (pun not intended). Anyways, what would I have to insert to cause the program to loop again (other than for case 3)? And another question, why is it that in scanf in the first case, the program only accepts two characters before finishing?
I've been struggling with linked list for a few days. I've tried performing a few operations. Here is my code. the add_begin() function doesn't seem to work.
#include<iostream>
using namespace std;
struct node {
int data;
node *next;
[Code] .....
I'm writing a program that converts hex to letters and writes the letters to a file.To write I'm currently using ofstream("output.txt" ios::app)But the issue with this is, is that everytime I run the program, it appends and doesn't write from the beginning of the text file.So what I want to know is, how do I clear the contents of a text file, before writing to it?
View 1 Replies View RelatedI was asked by my teacher to create while loop for this, iv have completely for gotten how and all the tutorial that i have found show basic lopping.
#include <iostream>
#include <iomanip>
using namespace std;
void checkAnswers(char[], char[], int, int);
int main(int argc, const char * argv[]) {
int choice = 0;
const int num_question=20;
const int min_correct=15;
char answers[num_question] ={
[Code] ....
I'm trying to learn structure type in C. In this trying, the code must take 9 value from user but it takes 6 values then returned. I scrutinized but I can't find my error.
#include <stdio.h>
typedef struct books {
char name;
float price;
int pages;
} book;
[code].....
My program had a requirement to ignore an input beginning with a # sign. The input is entered by user from keyboard. I wanted to know how to use cin.ignore to achieve this.
#include <iostream>
#include <algorithm>
#include <string>
#include <iomanip>
#include <limits>
#include <stdio.h>
using namespace std;
[Code] ....
The output:
Enter the string
# Comment
This is the # comment string.
Answer:
This is the string.
So I'm making my first program w/ C++ and its a game guessing game. I've learned how to use booleans, chars, strings, if/else, loops, and input. Anything past that I dont know. I've gotten my game to work properly except for the fact that when you guess incorrectly, the program closes. I want the program to go to the beginning of the program again so the user can restart. So far i've gotten the loop to beginning thing to work but not well. It'll only repeat twice before closing again and it'll say the user got the wrong answer even if it was correct. Here's my code
#include <iostream>
#include <string>
#include <random>
#include<ctime>
using namespace std;
int game(){
string playerName;
int guess;
[Code] ....
How do I write a ROM BIOS routine which accepts a row number from the user and place the cursor to the beginning of the row number which the user gave?
View 2 Replies View RelatedI am currently having problems creating a loop that will allow my user to choose to return to the beginning of the program or quit.
#include <iostream>
using namespace std;
int main() {
int j;
do {float a;
cout << "+----Welcome to Basic Operations----+
| Select Your Operation |
[Code] .....
I have not yet finished designing the interface for a couple of the operations, but right now i am hung up on trying to return to the beginning. I believe it is because the j was defined inside do and isn't carried out of the do statement for while.
I encounter this from a library:
( *(reg8 *)(pinPC) |= CY_PINS_PC_DATAOUT)
From my understand the cast (reg8 *) applies to the result of the bitwise OR. But what is the left most asterisk doing?Is it just dereferencing the casted pointer?