A sequence point in a C program is defined as "Any point in a program's execution at which it is gauranteed that all side effects of previous evaluations will have been performed and no side effects from subsequent evaluations have yet been performed."
What is a side effect?
I usually use codeblocks until my professor gave me a project in which it was mandatory to use turbo c++ so how can I create the timer effect in turbo???
E.g. if i want to print 1 2 3 4.... in a gap of 2 seconds how will I do it in turbo c++?
I have this code:
tgaManager.fileWriter.put((unsigned char)min(blue*255.0f,255.0f)).put((unsigned char)min(green*255.0f, 255.0f)).put((unsigned char)min(red*255.0f, 255.0f));
that should pass the value decided by the min function to an ofstream object, filewriter, that call the put method to print chars in a tga image file. When I open the file, all I see it is a huge black screen. You may be thinking that the values of blue,green and red are all zero but it is not the case.
With this code:
if (x==50 && y==50) {
cout << "Min BGR: " << endl;
cout << min (blue*255.0f,255.0f) << ' ' << min (green*255.0f,255.0f) << ' ' << min (red*255.0f,255.0f) << ' ' << x << ' ' << y << endl;
I get: Min BGR: 9.54167 29.9188 47.8701 50 50
The brief is to write a program that implements a musically-interesting or musically-useful audio effect/process in C without external libraries other than those prescribed (PortMedia/PortMIDI/PortSMF/PortAudio, Libsndfile).
View 6 Replies View Related// this program gives random number output
#include <iostream>
#include <cstdlib>// contains function protype for rand
#include <iomanip>// for setw
using namespace std;
[code]....
what is the effect on output of program of different numbers input to the int data type named seed*/
I have one code that use MPI broadcast and I want to change it into Asynchronous Point to Point communication. I am newbie in Parallel programming. Looking for implementation of one simple same program in broadcast and P2P ?
View 6 Replies View RelatedOn a right angled triangle, if the user inputs only ONE side length (not the hypotenuse) and only ONE angle, what code is required to work out the hypotenuse? I know how to work out the final side and the remaining angle once I have this.
View 4 Replies View RelatedI know this question must have been asked before, but the problem that I am facing is that I am using a library PoDoFo to parse PDF files. It seems that it is only compatible with C++.
Now I want the application to be web-based. That is, the user uploads a PDF file on the server, the server parses it and the parsed content is then sent back to the user.
Is such a thing possible with C++, or maybe any good work-arounds? Or should I look at server-side scripting languages like PHP and their respective libraries?
How do you add a value to the beginning of a string instead of the end?
This is for an assignment and I have to convert the user input (always assuming its a valid decimal number) to binary and store it in a string. I've got up to dividing by two to get the remainder ...
I am working on a 2D side scroller game. Where a ball is moving continuously towards right . I used a camera to follow the ball as soon as ball reaches the center of screen. I created a horizontal line to look like the surface on which the ball is rolling.
line runs from x=0 to x=800 (i.e screen width)
NOTE: (0,0) coordinate is at top left corner of display.
Problem: My display is 800 x 400 . Camera follows the ball, but soon the ball crosses x=800 and starts moving in black background. I want that line surface to stay there instead of going out of bound.
Additionally! I generated obstacles from x=800 which also move out of bound along with my line.
What should be done here? This is just my first c++ game project, so i might be skipping things that can solve the issue.
[Update] these screenshots manage to show, what the real problem is: [URL]
#include<conio.h>
#include<alloc.h>
#include<string.h>
struct node
[Code]....
I want to calculate the total some of delay pf receiving Side Packet . Code is as Follow ..
What is weird that even if i invoke a sleep of 2 sec ,than its show delay always zero. Delay will be in microsec ..Is there any problem with logic or anything else..
Code:
do
{#pragma omp parallel private(nthreads, tid) {
/* Obtain thread number */
tid = omp_get_thread_num();
if (tid == 0) {
nthreads = omp_get_num_threads();
[Code]...
[URL]
According to my project instructions, I have to make a "validation on the delete button, that before a record can be deleted it will check to see if the count of "In-Progress" orders for that product is 0. If it is greater than zero, it should not allow this record to be deleted."
So far I have on the code behind page:
protected void btnDeleteProduct_Click(object sender, EventArgs e)
{
DataView dv = (DataView)SqlOrders.Select(DataSourceSelectArguments.Empty);
[Coe].....
The professor said I have to: "As for getting the count, check your notes and book, specifically looking at SQL and the Aggregate functions. There is a function we talked about in class called "Count(OrderID)" and set the where clause to check for the productID.
Right after I close FIFO on the producer side, the app on the consumer side gets into an endless loop. select() returns that FIFO is ready to read. Below is the excerpt from the consumer code. The FIFO is opened "blocking" on both ends.
Code:
FifoClass fifo_r = FifoClass("/tmp/FIFO_READ");
int fdr = fifo_r.OpenR();// this->fd = open(name.c_str(), O_RDONLY , 0);
for(int i=0; ;i++) {
FD_ZERO(&rset);
FD_SET(fdr, &rset);
[Code] .....
I have a question concerning the CDialogBar (:CControlBar).
I have a MDI application with a dockable toolbox (CDialogBar).
The user is able/allowed to move the DialogBar and to dock it at the right or left side When I dock at the left side, the content of my mdi-application (so all other open windows) are moved right (so the dockable bar moves the windows).
If i dock at the right side, nothing changes.
How can I change the behaviour of the bar, that the windows inside the application keep the same position when I dock left ?
(Problem is, that my windows are aligned on the right side of the application). When I dock the bar on the left, the windows are getting moved in the not visible area.)
Been trying to configure the GridView to display ony 4 rows of data at a time. I thought it wasn't working because I forgot to set AllowPaging to True, but after I did that, I just get the error of
The data source does not support server-side data paging.
Source Error:
Line 66: titlesGridView.DataBind(); // displays query results
Here is my Books.aspx.cs code:
// Fig. 29.11: Books.aspx.cs
// Code-behind file for the password-protected Books page.
using System;
using System.Data.Entity;
using System.Linq;
namespace Bug2Bug.ProtectedContent {
public partial class Books : System.Web.UI.Page {
[Code] ....
Am I missing anything or doing something wrong thats not causing it to page & only display 4 titles at a time?
unsigned char x1, x2, x3;
size_t ix = 0;
size_t count;
std::string Input = "EFEF9E9475C8C2D938C204EAE058F2B3";
[code]....
when debug and have a watch on out i get incomplete sequence,
Code:
int main()
{
int n;
int* fib;
printf("
Fibonacci test 1: enter an integer
");
scanf("%d",&n);
fib = fibonacci(n);
printf("fib(%d) = ", n);
for(int i = 0; i < n; ++i){
printf("%d ", fib[i]);
}
What should I do/write for the fibonnaci function Code: int fibonnaci(int size)
I made a fibonacci series with label above it now how to put the label after the first layer because as you can see in the screenshot the label is continuous.
View 2 Replies View RelatedWhy is it that in the STL it is standard to indicate a sequence of elements in a container by a begin iterator that points to the first element and an end iterator that points to one past the last element?
View 2 Replies View RelatedMy assignment is to write a program that reads in a number from the user and then generates the hailstone sequence from that point. I'm not sure if I should use an if statement or string loop. The beginning of an attempt
#include <iostream>
#include <vector>
#include <string>
using namespace std;
vector<string> Numbers;
/// if n is equal to 1 the sequence has ended
/// if n is even divide the number by 2
/// if n is odd, multiply by 3 and add 1 to new number
[Code] ....
I have to write a program to find the nth number of the Ulam numbers.
It's a bit complicated to explain what an Ulam number is but Wolfram explains it very well here: [URL]
I have to find the nth Ulam number but I don't know what I have to do to get that. My program gives me all the Ulam numbers from a range of 0 to n.
What I want the program to do is tell me that the 49th Ulam number is 243.
/*
C++ Program to find nth Ulam Number
*/
#include <stdio.h>
#include <iostream>
#include <vector>
using namespace std;
int main() {
int num = 0;
vector<int> v;
[code]....
I made a program that prints out arithmetic sequence.. but problem is that,
when I enter a(first term) =5, d(differnce)=2.4 and n=3 the program prints out only first two terms not three.. for all the other numbers it works correctly..
I am trying to write a program that checks whether the number is in sequence(as in if the numbers are in order it is a sequence). Ex: If the numbers are {1,2,3,6,7,8,9,10,11,13,15,17,20,21}, then, the underlined parts are a sequence. Now i want to find
1) the no of sequence in the array(in the above it is 3 )
2) the longest sequence (7to 11 which is 5).
Q) How to do nested loops?
Q) How to do Array?
Q) How to do Fibonacci sequence?
The next code is right. I mean it works. It gives the sequence of fibonaci numbers ...
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int fibo(int pos) {
if(!pos)return 0;
if(pos==1)return 1;
[Code] .....
But.... when I change the lines:
Code:
int r1=fibo(pos1);
int r2=fibo(pos2);
int r=r1+r2;
For the lines:
Code:
int r=fibo(pos1)+fibo(pos2);
It doesn't work right. Apparently it should work the same.