In GCC v4.6, I am encountering a strange problem. If I try to get a character input and a int input like this:
Code:
int main()
{
int a;
char b;
scanf("%d",&a);
scanf("%c",&b);
}
the compiled program asks for input only one time. On the other hand, if I do the char scanf earlier like this:
Code:
int main()
{
int a;
char b;
scanf("%c",&b);
scanf("%d",&a);
}
it asks for input twice.
I have to make a program for school to evalute poker hand.I am not asking about the logic of the program,I am asking because I have to take the input from the console,five lines which can be the cards 2,3,4..10 and the problem is with J,Q,K,A ,because I dont know how to tell scanf to expect integer or char ? If I type J,Q,K,A the program crash ,
View 1 Replies View RelatedI would just like to know what does
while( (c =getchar())!='
' && c !=EOF );
do ? and how it do it?
I have see it in a example to clear the input buffer for next input through scanf but does not know its working clearly.
it is used in this example :
Code:
#include<stdio.h>
struct linklist {
char value[20];
struct linklist *next;
};
struct linklist *head,*curr;
[Code] .....
I'm doing a code to calculate the final grade of students. This is a work for college, and I need to keep this structure.
My problem is that last scanf, it is ignored when I compile the code. It "works" if I try to scan a string, float or int.
Code:
#include <stdio.h>
#include <stdlib.h>
void nfinal(float NOTA1,float NOTA2,float NOTA3,char MEDIA){
int NOTA;
if(MEDIA=='A'){
NOTA=(NOTA1+NOTA2+NOTA3)/3;
[Code]....
Code:
#include <stdio.h>
int main(){
unsigned char x, y=10;
scanf ("%c", &x);
[Code] ....
If I take out scanf and assign x a value then it works, but if I enter, for example, 10 into scanf it comes up as 234 rather than 100.
How to store the value in this case.. The topic is called "limited summation".. The following is the guideline for this problem:
Write a program in a folder called "sum" with a source file of main.cpp that does the following:
•prompt a user to enter a maximum number of entries, make the prompt "max # entries"
•prompt a user to enter a threshold sum, make the prompt "threshold"
•using error checking logic, let a user enter base-10 signed numbers until at least one of the following conditions is true:
or the maximum number of entries is reached
or the sum of entered numbers has reached (>=) the threshold
•print the sum of all the entries, just the number and a linefeed at the end of the line
Error checking means entries that are not numbers are detected and ignored. You are to use printf and scanf in this assignment (no cin or cout).
I tried to scanf the input by the user into the function but it does not read my input. Read on one of the thread, it said that to scanf a input into a double, need to use %1f instead to %d (which normally used. I tried changing it to %1f and it still did not work.
Code:
#include <stdio.h>
#include <math.h>
/* function main begins program execution */
int main( void )
{
double amount; /* amount on deposit */
[Code] ....
so i'm using scanf() this way
Code:
int i;
while (scanf("%i", &i))
printf("%i ", i);
printf("
done
");
i tried several combination of Ctrl+D and "Enter", it's not terminating, Ctrl+C just "cancels" the whole thing without printing "done", i'm running this on linux installed on a PC
So running the following code
Code:
#include <stdio.h>
int main(void) {
char c;
int i=1;
while (scanf("%c", &c)==1)
printf("loop sequence %i: %c(%i)
[Code] ......
Done it seems a "carriage return" serves two purposes here, one is to signal the program to read in the character typed in before the "carriage return", another serves as a second character typed, how can i do this cleanly, that is without having to use a "carriage return" as the second character to signal "I've typed in the first character already".
The issue that I'm having is that when I run this part of the code it seems to enter the if statement and set it to 0 when comparing the array to the input.
What I want it to do is to search the array for the grade, set it to zero, and then exit the loop in case there are any repeat grades. It always sets the first number to 0 and then exits.
//Below is the prototyping for the array
int grades[14] = {60,50,50,20,75,90,0,0,0,0,0,0,0,0};
//There is some code between here, but it is probably not relevant so I didn't post it.
printf("Enter the grade that you want to remove. Press Enter after each input.");
printf("Enter 0 to exit: ");
[Code] ....
I didn't mean to leave the "prototyping" part in the code. I was initially going to put the function prototypes in there, but decided it wasn't necessary for the question.
I'm extremely rusty at C but is this the best way to store an input string into a char*?
Code:
int length = 100; //initial size Code: char * name = malloc(length * sizeof(char)); //allocate mem for 100 chars
int count = 0; //to keep track of how many chars have been used
char c; // to store the current char
while((c = getchar()) != '
'){ //keep reading until a newline
if(count >= length)
name = realloc(name, (length += 10) * sizeof(char)); //add room for 10 more chars
name[count++] = c
}
Is this a good way and what could be better?
Basically I'm having trouble reading more than one character.I want the user to input character traits(ie, w, a), if two traits are entered they get the job.
But I cannot get my program to read more than one character input.
This is what I have so far...
#include <iostream>
using namespace std;
int main(){
char input;
int count = 0;
[Code] .....
I am writing a program that asks the user for their gender. I know that atoi converts arrays into integers, but I need the input from the user in the form of F or M into a char, and return it to the main function to be displayed at the end of the program.
string Employee::getgender(char gen)
{
cout << "Please enter your Gender: " << endl;
//atoi function would go here, what for char?
getline(cin,gen)
return gen;
}
I'm trying to write a program that takes input from the user (thats a char) and outputs it to the monitor in hex form.The program is meant to continuously take input from the user then output to the monitor in hex form until an EOF is detected this triggers the program to close.The following code does this except that I get a lower case 'a' at the end of each output.I think the 'a' has to do with the enter key and if that is the case how can i tell the program to ignore this input from the user.
Example: input from user: ABC output to monitor: 41 42 43 a
Code:
#include <stdio.h>
int main(void) {
char myChar;
while(EOF != (myChar = getchar())) {
printf("%x ",myChar);
}
system("pause");
return 0;
}
I've been experimenting with char arrays and getting user input through different methods.
int main() {
char userInput[21];
/*I understand that over here, a maximum of 20 letters can be input, and only letters before a space will be stored in userInput*/
std::cin >> userInput;
std::cout << userInput << std::endl;
[Code] ....
As I was testing, whenever I would input a single word for userInput (for example "hi"), the program would work as expected: it would output "hi" and I'd be able to input a sentence of sorts for userInput2 (for example "hello world") and have it outputted.
But if I were to input more than one word for user Input (for example "hi how are you"), the program would output "hi" as expected, but it wouldn't let me input anything for userInput2 and would just output the rest of the first input; in this case, "how are you" would be outputted and the program would end. I am not aware of the logic error at play.
So my question was:
Write a program to read in a sequence of characters one by one. Print out the characters in reverse. You should use a char[]. (Remember single quotes are used for char)
For example:
Please enter characters one by one: (Enter 0 to exit)
h
e
l
l
o
0
You entered: hello.
The reverse of that is olleh.
and this is currently my code
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <ctime>
#include <cmath>
using namespace std;
int main() {
char entry[20];
[code]....
im just not sure how to set that value and still make the for loops work
I want to take string input into a char array.
What is the functionality for the above problem.
So I'm trying to make a program, Which has nothing to do with the topic. But I ran into a problem.
I need to get a char array size of 6 doing:
char myChar[6];
but the size (6) is undefined until user input.
So I need to do char myChar[var]; (Var being 6 for now).
When I do:
char myChar[6];
It works!!!
But when I do:
int val = 6;
char myChar[val];
It doesn't work.
#include<windows.h>
#include<conio.h>
void gotoxy(int x,int y);
void gets_ex(char*, int max_chars);
int main(int argc, char *argv[]) {
char urname[16], surname[16], fullname[32];
start:
system("COLOR 1c");
[Code]...
What I'm trying to do is have the user input a hex number this number will then be converted to a char and displayed to the monitor this will continue until an EOF is encountered.I have the opposite of this code done which converts a char to a hex number. The problem I'm running into is how do i get a hex number from the user I used getchar() for the char2hex program. Is there any similar function for hex numbers?
this is the code for the char2hex program
#include <stdio.h>
int main(void) {
char myChar;
int counter = 0;
while(EOF != (myChar = getchar())) {
if (myChar == '')
[Code] .....
This is what i want to the program to do except it would do this continuously
#include<stdio.h>
int main() {
char myChar;
printf("Enter any hex number: ");
scanf("%x",&myChar);
printf("Equivalent Char is: %c",myChar);
system("pause");
return 0;
}
Code:
#include<stdio.h>
#include<windows.h>
int nr, i, array_new[10],n=0;
main(){
printf ("Insert number: ");
scanf ("%d", &nr);
[Code]...
I need put value from scanf into array. How make this: array_new[nr]?
When I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] .....
But when I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] ....
Why does the compiler say that there is an else without a previous if ??? ... Does this mean that I cannot use "scanf" in an if/else statement?
I want the user to be able to enter a command then a character, like for example: push r....I want the command to be stored in the array command, and the character to be stored in the variable c.
Now I wonder what the best way to get rid of the space is, using scanf or getchar (see below for code, only thing that I changed between the 2 versions is the statement before the comment "get rid of space")? Or maybe it doesnt matter?
Code:
include <stdio.h>
#define MAX 200
void push(char c); // Puts a new element last in queue
char pop(void); // Gets the first element in queue
static char s[MAX];
}
[code]....
How can i upgrade my program I want to input a octal and binary number and convert them in base 2, 8, 10, 16..
how can I write the scanf with the right parameter in it??
Code:
scanf ("%x",&i); Code: #include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int main() {
int i;
char buffer [33];
[Code] .....
I am trying to write a terminal-like chat application in Linux. I would like to use a FIFO queue to print out the messages in terminal. The queue would be populated from 2 sources- stdin and messages sent from the other user over TCP. I have meet an obstacle that I cannot handle...
Lets say I would like to take user input using fgets and put it into a buffer. Then queue it if the buffer is not empty or print if it is. The problem is that when I use fgets or scanf, my input is instantly printed to the terminal..If i do:
Code:
fgets(message, 100, stdin); printf
("%s", message The string under message is printed twice :|. Is there a way to prevent this?
I wanted to input some numbers with scanf function, i can enter some numbers and if I input -1 to the scanf, the input must end. And the scanf function has limited input, the max that I can input is 40 numbers.example if enter 1 2 4 6 5 4 -1 the scanf function will ended and the result will be appear.I wanted to know how the scanf function is like that would be best for this problem, Code: scanf("%d", &n); the result if I input those number will be like
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