Code:
#include<stdio.h>
#include<windows.h>
int nr, i, array_new[10],n=0;
main(){
printf ("Insert number: ");
scanf ("%d", &nr);
[Code]...
I need put value from scanf into array. How make this: array_new[nr]?
I don't know how many numbers will be the input only that its going to be up to 10000. EOF should be active. I tried it like this:
Code:
int i = 0;
int del[10000]
while (scanf("%d",del[i])!=EOF)
{
i++;
}
But it seems the value of i doesn't increment, could you provide some tips on how to scanf the inputs into an array if I don't know how many numbers will I have?
I'm trying to make a character array, and be able to custom fill it by using the scanf() function to ask the user for each character spot in the array.
Code:
#include <stdio.h>
int main() {
int i;
char character_array[11];
char *charpointer;
charpointer = character_array;
[Code] .....
And this is the output i get when i run it:
Code:
root@kali-Tulips:~# ./myown
what letter would you like in the [0] spot of the array? :
a
what letter would you like in the [1] spot of the array? :
what letter would you like in the [2] spot of the array? :
b
what letter would you like in the [3] spot of the array? :
what letter would you like in the [4] spot of the array? :
[Code] .....
Obviously I'm trying to grasp C programming and am very new. I don't understand why this isn't working, and i think its more than my lack of knowledge of C syntax. I believe the correct memory is allocated but when examined with gdb i don't find what i expect....
The issue that I'm having is that when I run this part of the code it seems to enter the if statement and set it to 0 when comparing the array to the input.
What I want it to do is to search the array for the grade, set it to zero, and then exit the loop in case there are any repeat grades. It always sets the first number to 0 and then exits.
//Below is the prototyping for the array
int grades[14] = {60,50,50,20,75,90,0,0,0,0,0,0,0,0};
//There is some code between here, but it is probably not relevant so I didn't post it.
printf("Enter the grade that you want to remove. Press Enter after each input.");
printf("Enter 0 to exit: ");
[Code] ....
I didn't mean to leave the "prototyping" part in the code. I was initially going to put the function prototypes in there, but decided it wasn't necessary for the question.
When I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] .....
But when I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] ....
Why does the compiler say that there is an else without a previous if ??? ... Does this mean that I cannot use "scanf" in an if/else statement?
I have to make a program for school to evalute poker hand.I am not asking about the logic of the program,I am asking because I have to take the input from the console,five lines which can be the cards 2,3,4..10 and the problem is with J,Q,K,A ,because I dont know how to tell scanf to expect integer or char ? If I type J,Q,K,A the program crash ,
View 1 Replies View RelatedI want the user to be able to enter a command then a character, like for example: push r....I want the command to be stored in the array command, and the character to be stored in the variable c.
Now I wonder what the best way to get rid of the space is, using scanf or getchar (see below for code, only thing that I changed between the 2 versions is the statement before the comment "get rid of space")? Or maybe it doesnt matter?
Code:
include <stdio.h>
#define MAX 200
void push(char c); // Puts a new element last in queue
char pop(void); // Gets the first element in queue
static char s[MAX];
}
[code]....
In GCC v4.6, I am encountering a strange problem. If I try to get a character input and a int input like this:
Code:
int main()
{
int a;
char b;
scanf("%d",&a);
scanf("%c",&b);
}
the compiled program asks for input only one time. On the other hand, if I do the char scanf earlier like this:
Code:
int main()
{
int a;
char b;
scanf("%c",&b);
scanf("%d",&a);
}
it asks for input twice.
How can i upgrade my program I want to input a octal and binary number and convert them in base 2, 8, 10, 16..
how can I write the scanf with the right parameter in it??
Code:
scanf ("%x",&i); Code: #include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int main() {
int i;
char buffer [33];
[Code] .....
I am trying to write a terminal-like chat application in Linux. I would like to use a FIFO queue to print out the messages in terminal. The queue would be populated from 2 sources- stdin and messages sent from the other user over TCP. I have meet an obstacle that I cannot handle...
Lets say I would like to take user input using fgets and put it into a buffer. Then queue it if the buffer is not empty or print if it is. The problem is that when I use fgets or scanf, my input is instantly printed to the terminal..If i do:
Code:
fgets(message, 100, stdin); printf
("%s", message The string under message is printed twice :|. Is there a way to prevent this?
I wanted to input some numbers with scanf function, i can enter some numbers and if I input -1 to the scanf, the input must end. And the scanf function has limited input, the max that I can input is 40 numbers.example if enter 1 2 4 6 5 4 -1 the scanf function will ended and the result will be appear.I wanted to know how the scanf function is like that would be best for this problem, Code: scanf("%d", &n); the result if I input those number will be like
|
||
||||
||||||
|||||
||||
when i run it , it skips scanf and not allowing user to enter input.tried adding getchar(), fflush but nothing worked for me.
//file name : sort_array_of_structure.c
Code:
/*Write a program to accept records of the different states using array of structures. The structure should contain char state, population, literacy rate, and income. Display the state whose literacy rate is highest and whose income is highest.*/
#include <stdio.h>
#define M 50
struct state
{
char name[50];
long int population;
float literacyRate;
float income;
}
[code]....
I have created a prompt which prompts the user for an integer and I have set up a loop to check for if it is an integer or not. My "bug" is that a user can enter an "integer" and "space" and "enter" and it does not give any error and assumes that "All is FINE!". I have gotten the value from the ascii table of 'SPACE' and put it as a check in my parameter of while, but it does not work.
Here is my code:
int x, y, boolean, i;
char buff[256];
printf("Enter the first integer value: ");
scanf("%s", buff);
i = 0;
boolean = 0; //initializing our boolean var that will eventually decide if we have an error or not
[code]....
I am writing a program and am asking the user to enter a number between 1-12.
If they do not, they will be promoted over and over again to enter a number between 1-12.
However, if the user enters a letter or anything else scanf seems to stop working and then my loop goes out of control.
How to store the value in this case.. The topic is called "limited summation".. The following is the guideline for this problem:
Write a program in a folder called "sum" with a source file of main.cpp that does the following:
•prompt a user to enter a maximum number of entries, make the prompt "max # entries"
•prompt a user to enter a threshold sum, make the prompt "threshold"
•using error checking logic, let a user enter base-10 signed numbers until at least one of the following conditions is true:
or the maximum number of entries is reached
or the sum of entered numbers has reached (>=) the threshold
•print the sum of all the entries, just the number and a linefeed at the end of the line
Error checking means entries that are not numbers are detected and ignored. You are to use printf and scanf in this assignment (no cin or cout).
I tried to scanf the input by the user into the function but it does not read my input. Read on one of the thread, it said that to scanf a input into a double, need to use %1f instead to %d (which normally used. I tried changing it to %1f and it still did not work.
Code:
#include <stdio.h>
#include <math.h>
/* function main begins program execution */
int main( void )
{
double amount; /* amount on deposit */
[Code] ....
I'm doing a code to calculate the final grade of students. This is a work for college, and I need to keep this structure.
My problem is that last scanf, it is ignored when I compile the code. It "works" if I try to scan a string, float or int.
Code:
#include <stdio.h>
#include <stdlib.h>
void nfinal(float NOTA1,float NOTA2,float NOTA3,char MEDIA){
int NOTA;
if(MEDIA=='A'){
NOTA=(NOTA1+NOTA2+NOTA3)/3;
[Code]....
The problem that I want to make an array " vertextDegree [nbColours] " with " nbColours " elements in it ,but the "nbColours" unknown and I have to get it get it from a file .
Code:
int nbEdges,nbVetices, nbColours ;
typedef struct st_graphVertex {
int index;
int colour;
int val ;
int vertexDegree[nbColours]; // it won't work because nbColours unknown
// here and I want get it from file in the main
struct st_graphVertex *next;
t_edgeList *out;
}t_grapheVertex;
Somehow only str2 is successfully scanned and str1 is not printed
Code:
printf("
Please enter two times in this way xx.xx xx.xx now ");
scanf("%s%s", str1, str2);
printf("
%s - %s:
", str1, str2)); result : - str2:
I'm trying to make a very simple reaction game where a random number flickers on the screen for a fraction of a second and the user has to then enter the number before another comes on the screen after a random amount of time. However I dont know how i would make it so that the user cannot enter anything after a certain amount of time has passed, below is my code?
Also FYI, clock_start is at 5100 because by the time the program actually gets to scanning in the first number the time is at an absolute minimum of 5050 milliseconds however obviously this is an impossible number to reach due to processing, my machine clocks in at 5080.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
int main(void){
[Code]...
I have created a program using a switch statement that uses scanf() to accept a users input. The input variable is defined as an integer and scanf() is also looking for an integer.
One computer I run the program and it will return a value of 0 for all non-numerical inputs such as 'z', and the output thinks the value 0 was input into scanf(). On another computer when I input 'z', the compiler stores this as 198864884, and my program executes correctly giving an error.
so i'm using scanf() this way
Code:
int i;
while (scanf("%i", &i))
printf("%i ", i);
printf("
done
");
i tried several combination of Ctrl+D and "Enter", it's not terminating, Ctrl+C just "cancels" the whole thing without printing "done", i'm running this on linux installed on a PC
I'm using scanf() function to read numbers in my cpp program and, for example, if i want to read a string that is a complete name i could use
scanf("%[^]", x);
or if i want to read only vogals i could use
scanf("%[aeiou]", x);
Is it possible to read only positive numbers or only negatives numbers using scanf() and how to do it?
Below given is the code, which allocates memory for a structure dynamically and stores value in its member. The problem is in the last scanf statement which reads 'ch'. The code will be in infinite loop as it doesnt executes the last scanf statement. The solution for this is (i use this) to add one more similar scanf statement for 'ch' in the very next line. If i do so, it executes the statement, reads 'ch' and then continues.
I want to know why it behaves like that..
struct student{
int usn;
};
int main(){
char ch;
struct student *s;
s=(struct student *)malloc(sizeof(struct student));
[Code] ....
Code:
#include <stdio.h>
int main(){
unsigned char x, y=10;
scanf ("%c", &x);
[Code] ....
If I take out scanf and assign x a value then it works, but if I enter, for example, 10 into scanf it comes up as 234 rather than 100.
I just started learning programming. I tried using this but the loop is not working ....
Code:
#include<stdio.h>
#include<ctype.h>
#define PI 3.1416
void main(void) {
char choice;
float r, area;
[Code] ....
However when i removed this portion below, and replacing it with choice='Y';, the loop works just fine although my intention is to continue the loop only when 'y' is entered.
Code:
printf("Continue? Y/N:");
fflush(stdin);
scanf_s("%c", &choice);
choice = toupper(choice);
I think that I'm using the code wrongly but i'm not sure where the mistake lies in
