So I'm trying to make a program, Which has nothing to do with the topic. But I ran into a problem.
I need to get a char array size of 6 doing:
char myChar[6];
but the size (6) is undefined until user input.
So I need to do char myChar[var]; (Var being 6 for now).
When I do:
char myChar[6];
It works!!!
But when I do:
int val = 6;
char myChar[val];
It doesn't work.
I am making program that allows the user to determine how big the array size will be and then asks the user to make up numbers to fill the array. Every time run the program on Dev C++ it says "program has stopped working"
Heres My Code:
//Assignment 19 Program 2
#include <iostream>
using namespace std;
int main()
[Code].....
I'm trying to build an array of a certain size, after receiving user input. The method I'm trying is
int var = 3;
int* ar = new int[var];
When doing tests I did this (and it worked) and red flags popped off in my head.
int var = 3;
int* ar = new int[var];
ar[0] = 0;
ar[1] = 1;
ar[2] = 2;
ar[3] = 3;
ar[4] = 4;
cout << ar[0] << ar[1] << ar[2] << ar[3] << ar[4] << endl;
This method is considered safe, and possibly tell me why I'm not getting stack errors when trying to overload the array?
I need to make a program that will let the user input values and it will only stop accepting once the user has inputted a negative number then it will display its mode and frequency.
The problem is I can't find a way to let the user input values freely without asking first for the no. of values he will enter.
#include<stdio.h>
int main() {
int i,j,k=1,p,a[20],b[20],n,cnt=1,big;
clrscr();
printf("Enter the number of elements:
[Code] .....
How can i write a program that allows a user to enter a size of pizza and then print the price for that size.
Example: if a user enters size ''s'' then it should display the price stored under ''s''
I'm trying to write a program that takes input from the user (thats a char) and outputs it to the monitor in hex form.The program is meant to continuously take input from the user then output to the monitor in hex form until an EOF is detected this triggers the program to close.The following code does this except that I get a lower case 'a' at the end of each output.I think the 'a' has to do with the enter key and if that is the case how can i tell the program to ignore this input from the user.
Example: input from user: ABC output to monitor: 41 42 43 a
Code:
#include <stdio.h>
int main(void) {
char myChar;
while(EOF != (myChar = getchar())) {
printf("%x ",myChar);
}
system("pause");
return 0;
}
I've been experimenting with char arrays and getting user input through different methods.
int main() {
char userInput[21];
/*I understand that over here, a maximum of 20 letters can be input, and only letters before a space will be stored in userInput*/
std::cin >> userInput;
std::cout << userInput << std::endl;
[Code] ....
As I was testing, whenever I would input a single word for userInput (for example "hi"), the program would work as expected: it would output "hi" and I'd be able to input a sentence of sorts for userInput2 (for example "hello world") and have it outputted.
But if I were to input more than one word for user Input (for example "hi how are you"), the program would output "hi" as expected, but it wouldn't let me input anything for userInput2 and would just output the rest of the first input; in this case, "how are you" would be outputted and the program would end. I am not aware of the logic error at play.
I have function that looks like this myfoo(char* Name) Now i want to compare this name to another one . But the another name is a pointer . This my code :
bool Tribe::RemoveSurvavior(char *H_Name) {
const char *p;
p=SurpointArr[i]->GetSurvivor_Name();
}
I need to compare if p is same as H_Name.
Mine is do it with for on each element but when i use sizeof it gives me size of char and not real size of the name.
I want to save the char[8][8] // fixed size 2 dimension array
to a vector
such as
vector<?????> temp;
is there anyway to approach this?
I've been in a strange problem. Im in need to have a dynamic character size, but that increases the outputsize of my program by almost 50kb. (while the program was 11kb previously).
Example:
Char One[7000]; (11kb output)
int Z = 7000;
Char Two[Z];
I'm working on a piece of code written long time ago. Without getting in the details or too much context here, there is a function that declares an array of char of a size of 350,000 elements, in order to fill it (using a pointer) with the list of all running processes on the machine (using "ps -ejf" on a Linux box).
The size of the char array has been changed from 40,000 to 350,000 sometime along the years, probably because of a lack of space required.
What kind on data structure / storage would you use to store the running processes in order to eventually search for a value in it?
I am not sure why I am receiving the error message:
Error C2466: cannot allocate an array of constant size 0
When I run the code:
Code:
int s;
cout<<"Enter the size:
";
cin>>s;
int array[s];
C++ masters,
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....
is it possible to use this code ?
#include <iostream>
int main(int argc, const char * argv[]) {
int number = 0;
std::cout << "napis cifro za array
";
std::cin >> number;
[Code]...
It does work on xcode but doesn't in microsoft visual studio 2013. Where is the problem?
How can I stomp the arr size of 50 with the value the user inputs? The function doesn't sum up the even integers from 0 to the value the user inputs. Instead it sums up exactly that many even integers.
Is there a way I can stomp the size of the array with what the user inputs so that the sum calculation never goes past the value the user inputs?
Code:
void sumIntegers () {
int arr[50];
int i = 0;
int num = 0;
int sum = 0;
printf("
I want to sum up even integers <= 50.
[Code] .....
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
View 10 Replies View RelatedI am trying to use an array of a size that will be determined by the user, therefore I must use a vector, right?
In class I was told that this is how I call a vector:
vector <int> x;
Is the vector called vector? Is it called x?
Can I do this?
for(int i=0;i<=10;i++)
{
cout<<x[i];
}
Some basic ways of implementing a vector? How it works or how I can do anything with it.
Dynamic memory allocation in array in c programming. I am trying to make the user to choose the size of array they want to engage in the game.
However, i have remove the global variable which contribute the error to my code previously. Now I assigned all the arr individually but not using the global variable. However, i still not get the desired board i want. i still keep getting 9x9 array board.
And i also need limit the board size only from 4 to 9. And how do i do that.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>
#include <malloc.h>
#include <ctype.h>
#include <stdbool.h>
[Code] .....
I'm now working on a class to handle matrices and matrix operations. I dynamically allocate a two dimensional array with its size as an input. My problem is that i need to resize the matrix structure (to fit to the size of a product of two matrices or to adjust the size after deleting a row or column for example). I make the resizing by deleting the allocated 2d array after saving its first element address to another pointer to pointer, after saving the useful data in an other array, then i use new[] operator to create a new 2d array using the same address of the old deleted array.
void My_matrix ::delete_row(int a) {
int i,j;
int buffer_row_index = -1; //note that our work is zero based, as we acess the private member of an object of the same class we are working on and we access to the array as it is (zero based) so if this variable is -1, it will be 0 when it enters for the first time and saves the data in the right position.
My_matrix buffer(number_of_rows-1,number_of_columns);
[Code] ....
I do this in a way that i think is unsafe. This code is sometimes unstable and gives an unhandled exception whose reason is unknown. I need to know whether this way is good enough or if there any other better ways.
I'm a little lost with this program. The idea is to dynamically allocate an array and increase its size every time a new integer is inputted by the user. I believe it is a memory leak but as we have just started learning this I'm not sure how to recognise it. Sometimes I can input as many integers as I want other times 2 or 3 before it crashes. When I can input enough values i exit the loop and send it to the sort function and mean calculator function, all works fine there except the last number inputted becomes this huge value not hexadecimal though... As such I'm at a loss as what to look at next, so here you go:
#include <iostream>
using namespace std;
void SelectSort(int [], int);
float MeanCalc(int [], int);
float MedianCalc(int* [], int);
[Code] .....
So my question was:
Write a program to read in a sequence of characters one by one. Print out the characters in reverse. You should use a char[]. (Remember single quotes are used for char)
For example:
Please enter characters one by one: (Enter 0 to exit)
h
e
l
l
o
0
You entered: hello.
The reverse of that is olleh.
and this is currently my code
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <ctime>
#include <cmath>
using namespace std;
int main() {
char entry[20];
[code]....
im just not sure how to set that value and still make the for loops work
I want to take string input into a char array.
What is the functionality for the above problem.
STRING s1 = “FOOBAR”
Here STRING is a user defined class. how to assign a constant char array "FOOBAR" to string object? Copy constructor need to be same class type as parameter. and overloading assignment operator also need to be same class type. I think 'friend' can let pass another type of object rather than STRING to do operation on overloaded '=' operator. How could it be done if it is possible at all?
I have written a program and i had to pass an array into a function and now i have a variable for the subscript of the array and i was the user to input data, specificlly a string, more specifically first and last name without having to create two arrays, i have to do this with other things in the program as well, here is part of the program:
int addFunc(const int totNum, string city[],string state[],string street[],string name[],
int addNum[],int zip[],int telNum[],double bal[],int dateLp[], int addCount, int accNum, int usNum)//function will add a new account {
int countAf = 1;
if (usNum < 20)
[Code] ....
it should be able to take firstname space lastname
My parameters are that the users input has to be from 1 to 9 and the same number can't be entered twice. How do i modify this code to make sure that the user did those things or an error message should appear that their input is invalid.
#include <iostream>
using namespace std;
int main() {
int square[3][3];
[Code] ......
Say you the user inputs x number of names and then is to put in x amount of values for each name. How would you display these values in a 2d array and be able to add the values for each row which will represent each name?
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