I've been in a strange problem. Im in need to have a dynamic character size, but that increases the outputsize of my program by almost 50kb. (while the program was 11kb previously).
Example:
Char One[7000]; (11kb output)
int Z = 7000;
Char Two[Z];
My sample.h is
#include <string>
namespace xxx
{
class abc
[Code]....
My Question is when i compile this code in Linux platform Using g++ compiler My sample.o's Size is 1Kb.. But when the same code is compiled in Windows platform using VC++ Compiler , My sample.o's size is 42Kb..to reduce the size in windows... Is there any proble with '#include <string>' in Windows platform.
I remember in C++, when a dynamic array is allocated, the size of this array is stored right before the array in memory. Therefore compiler knows exactly how long, when this array is deleted.
Do all compilers store the size this way? Is it a safe method to get the size of a dynamic array?
Here is a example code, it works fine on Visual Studio 2012.
#include <iostream>
using namespace std;
class dummy {
public:
dummy() {
cout<<"dummy created"<<endl;
[Code]...
arrays with dynamic sizes. That being said, I'm working with a simple code which seems to work just fine, my only concern is that once I display the 'char array', not only displays the user's inputs but some extra data, symbols and what not.
why, if to my understanding the first user's input already sets the size of the array
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
View 10 Replies View RelatedI'm now working on a class to handle matrices and matrix operations. I dynamically allocate a two dimensional array with its size as an input. My problem is that i need to resize the matrix structure (to fit to the size of a product of two matrices or to adjust the size after deleting a row or column for example). I make the resizing by deleting the allocated 2d array after saving its first element address to another pointer to pointer, after saving the useful data in an other array, then i use new[] operator to create a new 2d array using the same address of the old deleted array.
void My_matrix ::delete_row(int a) {
int i,j;
int buffer_row_index = -1; //note that our work is zero based, as we acess the private member of an object of the same class we are working on and we access to the array as it is (zero based) so if this variable is -1, it will be 0 when it enters for the first time and saves the data in the right position.
My_matrix buffer(number_of_rows-1,number_of_columns);
[Code] ....
I do this in a way that i think is unsafe. This code is sometimes unstable and gives an unhandled exception whose reason is unknown. I need to know whether this way is good enough or if there any other better ways.
Dynamic memory allocation in array in c programming. I am trying to make the user to choose the size of array they want to engage in the game.
However, i have remove the global variable which contribute the error to my code previously. Now I assigned all the arr individually but not using the global variable. However, i still not get the desired board i want. i still keep getting 9x9 array board.
And i also need limit the board size only from 4 to 9. And how do i do that.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>
#include <malloc.h>
#include <ctype.h>
#include <stdbool.h>
[Code] .....
I'm a little lost with this program. The idea is to dynamically allocate an array and increase its size every time a new integer is inputted by the user. I believe it is a memory leak but as we have just started learning this I'm not sure how to recognise it. Sometimes I can input as many integers as I want other times 2 or 3 before it crashes. When I can input enough values i exit the loop and send it to the sort function and mean calculator function, all works fine there except the last number inputted becomes this huge value not hexadecimal though... As such I'm at a loss as what to look at next, so here you go:
#include <iostream>
using namespace std;
void SelectSort(int [], int);
float MeanCalc(int [], int);
float MedianCalc(int* [], int);
[Code] .....
I'm writing a class that has two constructors. However, I can't get them to work quite right. One constructor has a parameter of an int (with a default value of 0) and the other has a parameter of a C-style string.
First of all, are these function prototypes correct for the constructors?
MyInt(int n = 0);// first constructor, int param, default value 0
MyInt(const char * c);// second constructor, c-style string param
Both constructors work fine in some cases but don't work in all cases. Here are some potential calls to these functions that are supposed to work:
// These two work fine
MyInt x(12345),
y("9876543210123456789"),
// The array assignment doesn't work when the value is negative
// I'm not allowing negative numbers, but I want to create the object and assign the array to 0
r1(-1000),
[Code] .....
Here's the private data from the class (from the header file):
private:
int currentSize,
maxSize;
char* digits;// Pointer to an array of digits
// Increase the size of digits array by 5
void Grow ();
I have function that looks like this myfoo(char* Name) Now i want to compare this name to another one . But the another name is a pointer . This my code :
bool Tribe::RemoveSurvavior(char *H_Name) {
const char *p;
p=SurpointArr[i]->GetSurvivor_Name();
}
I need to compare if p is same as H_Name.
Mine is do it with for on each element but when i use sizeof it gives me size of char and not real size of the name.
So I'm trying to make a program, Which has nothing to do with the topic. But I ran into a problem.
I need to get a char array size of 6 doing:
char myChar[6];
but the size (6) is undefined until user input.
So I need to do char myChar[var]; (Var being 6 for now).
When I do:
char myChar[6];
It works!!!
But when I do:
int val = 6;
char myChar[val];
It doesn't work.
I want to save the char[8][8] // fixed size 2 dimension array
to a vector
such as
vector<?????> temp;
is there anyway to approach this?
General Purpose: Delete all "white spaces" in text file, until the read-in char is _not_ a whitespace (mark as start of text file).
Problem: Cannot seem to shift char's over properly. (I think my problem is the inner loop - however other code may lead to this problem - I do not know)
Code:
#include <fstream>
#include <iostream>
using namespace std;
bool trimWhiteSpace(fstream &file, char * charMemoryBlock) {
if (!file.is_open()) {
[Code] ....
I'm working on a piece of code written long time ago. Without getting in the details or too much context here, there is a function that declares an array of char of a size of 350,000 elements, in order to fill it (using a pointer) with the list of all running processes on the machine (using "ps -ejf" on a Linux box).
The size of the char array has been changed from 40,000 to 350,000 sometime along the years, probably because of a lack of space required.
What kind on data structure / storage would you use to store the running processes in order to eventually search for a value in it?
Code:
#include main() { char why[64]; why =255,255,255,255,255,255,255,255;
while (why > 4); printf("why is equal to" ,why); why = why-2;
return 0;
}
It tells me incompatible data type.
I have data that is coming into my buffer via popen (process data, not a file). Every seven records is a new set [0-6]. I am trying to 'print out the array line/element value' and 'change the value of element [2] to 0', but my loop appears to be looping through every character and not just every line?
code:
char* Data(){
char buff[BUFSIZ];
FILE *fp = popen("php order.php 155", "r");
std::string::size_type sz;
while(fgets(buff, sizeof buff, fp) != NULL)
}
[code]....
So my question was:
Write a program to read in a sequence of characters one by one. Print out the characters in reverse. You should use a char[]. (Remember single quotes are used for char)
For example:
Please enter characters one by one: (Enter 0 to exit)
h
e
l
l
o
0
You entered: hello.
The reverse of that is olleh.
and this is currently my code
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <ctime>
#include <cmath>
using namespace std;
int main() {
char entry[20];
[code]....
im just not sure how to set that value and still make the for loops work
I have data that is coming into my buffer via popen (process data, not a file). Every seven records is a new set [0-6]. I am trying to 'print out the array line/element value' and 'change the value of element [2] to 0', but my loop appears to be looping through every character and not just every line?
Code:
char* Data(){
char buff[BUFSIZ];
FILE *fp = popen("php order.php 155", "r");
std::string::size_type sz;
while(fgets(buff, sizeof buff, fp) != NULL) {
const char * cstr2 = buff;
for(int i = 0; i < 6; ++i){
[code]...
expected output:
199729173
2014-11-16 10:09:34
Found String!
198397652
2014-11-14 15:10:10
Found String!
198397685
2014-11-14 15:10:13
Found String!
198398295
2014-11-14 15:11:14
Found String!
raw inbound data [URL]
My purpose is to fill a matrix with random numbers. As you can see in the code, I defined a matrix called sim_matrix (which should be filled), but the dimensions of such matrix is given by the parameters that we introduce in the constructor. Because we don't know the size of such matrix until we give these parameters through the constructor. I'd like to know how to declare such matrix, or how to modify the size,...
The header of my file MonteCarlo.h is:
/* MonteCarlo.h */
#ifndef MONTECARLO_H_
#define MONTECARLO_H_
using namespace std;
class MonteCarlo {
public:
MonteCarlo(int n_paths, int n_simulations);
[Code] ......
I am designing an application in which I need to deal with many different variables in which different sequences of bits are stored. I have very strict memory requirements so I decided to use the boost::dynamic_bitset data type which works very well in my scenario as I need to dynamically allocate/deallocate/resize the variables.
The only problem is that I am not able to change the size of the blocks in which the dynamic_bitsets are stored.
I mean, even if I specify the blocks should be "unsigned char", I always obtain 32 bytes allocation by sizeof function, even if the variable is empty.
I just wrote the following simple program:
Code:
#include <stdio.h>
#include <math.h>
int main(void) {
float fx, x;
[Code] ....
The output increases x by 0.1 as expected until x=1.5. After that x becomes 1.600001 and not 1.6 as expected.
I'm writing a program in which I have to use a matrix to represent a file in code. because it's a file, the size of the matrix is undefined, and therefore the matrix has to be dynamic. I found out that my compiler doesn't like dynamic multidimensional arrays, so I was thinking of this matrix as a dynamic (monodimensional) array of other dynamic (monodimensional) arrays. My program (and thus this example) uses unsigned chars.
unsigned char variable=something;
unsigned char**matrix=new unsigned char*[lenghtOfMainArray];
for(int rowNumber=0;rowNumber<lenghtOfArray;rowNumber++)
{
[Code].....
Why is the size of an empty class 1? Why is the class still one when I add a char member to the class?//using turbo c++ 3.0, yes I know I'm using a very old c++ compiler and software
View 3 Replies View RelatedI tried running the code below and i got an unexpected output
Code:
#include<stdio.h>
void main() {
char a='A';
while(a)
[Code] ....
The code is supossed to give an infinite loop but instead it terminates with a=0...I tried running it with some casting like this
Code:
#include<stdio.h>
void main(){
char a='A';
while((int)a)
[Code] ....
But the output was the same as before.why the code has this unexpected behaviour???
I'm trying to write a program that takes input from the user (thats a char) and outputs it to the monitor in hex form.The program is meant to continuously take input from the user then output to the monitor in hex form until an EOF is detected this triggers the program to close.The following code does this except that I get a lower case 'a' at the end of each output.I think the 'a' has to do with the enter key and if that is the case how can i tell the program to ignore this input from the user.
Example: input from user: ABC output to monitor: 41 42 43 a
Code:
#include <stdio.h>
int main(void) {
char myChar;
while(EOF != (myChar = getchar())) {
printf("%x ",myChar);
}
system("pause");
return 0;
}
I've made a code to check whether or not a save file has been created correctly, but for some reason it always returns this line: readdata[qa]=='1' as true. in which qa is the counter I use in a for loop and readdata is a character array consisting of 50 characters that are either 0, 1 or 2.
this is the entire code:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
[Code]....
at first is also went wrong at line 22 and also returned that as true, but then I added brackets and it worked.
