STRING s1 = “FOOBAR”
Here STRING is a user defined class. how to assign a constant char array "FOOBAR" to string object? Copy constructor need to be same class type as parameter. and overloading assignment operator also need to be same class type. I think 'friend' can let pass another type of object rather than STRING to do operation on overloaded '=' operator. How could it be done if it is possible at all?
Assign value of pow(2,800) to char array or string ....
View 1 Replies View Related#include <iostream>
using namespace std;
struct box{
[Code].....
C++Dev.cpp:23: error: incompatible types in assignment of ‘const char [15]’ to ‘char [40]’
Can you take a look why I am getting compile error.
Code:
// clang++ main.cpp -g -std=c++11 -o main
#include <iostream>
class QuoteClass {
public:
QuoteClass() = default;
QuoteClass(std::string param) {symbol = param;}
std::string get_symbol() {return symbol;}
[Code] ....
I am getting a compilation error from the code below. It is when i am naming a variable with my user defined type.
#include<iostream>
#include<cstring>
#include<cstdlib>
using namespace std;
class person {
[Code] .....
C:Dev-CppTRIAL.PASS.!!!.cpp In function `int main()':
66 C:Dev-CppTRIAL.PASS.!!!.cpp expected primary-expression before "p"
66 C:Dev-CppTRIAL.PASS.!!!.cpp expected `;' before "p"
74 C:Dev-CppTRIAL.PASS.!!!.cpp `p' undeclared (first use this function)
(Each undeclared identifier is reported only once for each function it appears in.)
83 C:Dev-CppTRIAL.PASS.!!!.cpp `X' undeclared (first use this function)
typedef tr1::unordered_map <string, pin *> pin_cmp;
pin_cmp _pin_cmp;
_Pins[_num_pins] = new pin (pin_id, _num_pins, s, n, d);
_pin_cmp[_Pins[_num_pins]->get_name ()] = _Pins[_num_pins]; //performance profiling
What actually the code doing?
_pin_cmp[_Pins[_num_pins]->get_name ()] = _Pins[_num_pins]; //performance profiling
I am not familiar with unordered_map which still can use with array[].I am confuse unordered_map just need key and value why will have array[]?
I can assign values to pointer character array like this...
Code:
char *array[4]={"abc","xyz","dgf","sdt"} ;
but the case is i don't know how to assign strings through key board ???? with using gets ,getchar or other suitable function
Write a program using user-defined function which is passed a string and that function should cycle the string.(Do not use any string related functions). E.g.
If the string is : Chetna then it should print as Chetna, hetnaC, etnaCh, tnaChe,naChet, aChetn
Ans.
#include <iostream>
using namespace std;
char swamp(char a[], int x) {
for(int k=0; k<=x; k++) {
char l= a[x]; a[x]= a[0]; char p=a[x-1]; a[x-1]=l;
for(int i=1; i<x-2; i++) {
[Code]...
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....
How do I convert just the number from position 4 to 15 from this char array and convert to int and save to variable
char numbers[]="54155444546546545643246543241465432165456";
the real char got 1000 digits this is just example how do i convert chars from numbers[4] to numbers[15] and save them as one number ? in this case i will get int x = 5444546546545643 as u can see char numbers as a example above
We had to write a "selling program for computers, laptops and tablets", which I did but for the extra credit, we have to have those three points in the application and I have tried but how to do the "extra credit" part, which I really need.
1.) A loop to prompt the user if they would like to place another order
2.) At least one user-defined function
3.) An enumerated data type, array or struct (structure)
I did one of these three, it's a "DO WHILE" loop asking users if they want to make another order, it's right at the beginning of the code.
Code:
#include <iostream>
#include <string>
#include <iomanip>
#include <fstream>
using namespace std;
double desktop();//function prototype
double laptop();
double tablet();
[Code] ....
im tasked with creating a linear search script using functions on a 10 element array. the elements are to be supplied by the user as is the search target.
I understand how to create the array and gather that information from the user as well as howto set a variable for "target", this is what im calling it. Those two parts are simple enough.
I am not fully understanding the calling of an array in a function as a pointer. i semi understand the use of a pointer and howto call a normal pointer in a function. i also understand that an array is nothing more then a "special" pointer with a set of consecutive address blocks for the size of the array.
My first user defined function is simple enough
Code:
ReadArray(int A[], int size){
int i;
printf("Please enter %d integer numbers separated by spaces:
", size);
for (i = 0; i < size; i++)
scanf("%d", &A[i]);
}
Sso nothing out of the ordinary there. that should be a standard for loop and use of scanf, sadly prof has not covered ssanf or any of the other options so i am stuck using scanf for now. maybe someday down the line in a other program or after this course ill get the chance to learn about better options for gathering data from the user.
I am confused as to my next function:
Code:
void SearchArray(int A[], int target, int size);
I've not written any code here yet as im not sure if i should call the A[], or *A for the first type of the function?
If i call *A do i then use something like this for my search:
Code:
for (*A = 0; *A < size; *A++)
if (*A < target) or use A[] insteadA?
Code:
for (i = 0; i < size; i++)
if (A[i] = target)
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
I'm completely new to pointers and have a homework assignment due where I'm supposed to create a user defined dynamic array for player scores. The only errors I'm experiencing is a C2109: subscript requires pointer type and only on the lines that use the int *score; variable (57, 62, 64, 69, 71, and 82). I've already tried adding = nullptr to the variable and that didn't work.
#include<iostream>
#include<string>
#include<iomanip>
using namespace std;
void players(string[], int[], int);
void average(int[], int);
[Code] ....
I'm trying to "tokenize" a string using std::string functions, but I stored the text in a char array. When I try to convert it to a string, the string has the first character right but the rest is garbage.
// Get value from ListBox.
char selectedValue[256];
memset(selectedValue, NULL, 256);
SendMessage(GetDlgItem(hWnd, IDC_LB_CURRENTSCRIPT), LB_GETTEXT, selectedIndex, (LPARAM)selectedValue);
// Convert to string.
string val(selectedValue);
[Code] ....
So I'm trying to make a program, Which has nothing to do with the topic. But I ran into a problem.
I need to get a char array size of 6 doing:
char myChar[6];
but the size (6) is undefined until user input.
So I need to do char myChar[var]; (Var being 6 for now).
When I do:
char myChar[6];
It works!!!
But when I do:
int val = 6;
char myChar[val];
It doesn't work.
I am a newbie to C++ and VS ++. I have created a windows form application by dragging and dropping button, label..etc. i wish label text to be appeared as return value from a function. The function returns ' const char* '.how this returned string pointer can be used to display label text.?
View 9 Replies View RelatedI have some code:
char cHomeTeamFaceOffsPercentageWon[100];
memcpy(cHomeTeamFaceOffsPercentageWon,cSqlHomeTeamFaceOffsPercentageWon,100);
After this, for example, cHomeTeamFaceOffsPercentageWon is, "29%".
Then, I use
std::string szwPercentageWon = std::string(cHomeTeamFaceOffsPercentageWon);
szwPercentageWon is then, "2". Shouldn't this convert correctly, to "29%" as well.
Or is there something I'm missing? Maybe the termination character, or something.
#include<iostream>
using namespace std;
#include<set>
class person{
int age;
[Code] ....
When I executed the above code it displays
Age is 37
Age is 25
Here I have defined operator< so that set can identify the order of person objects. I am clueless how set could identify that
person p[3]={person(25),person(37),person(25)};
I have provided one duplicated object with age 25
I havent overloaded == operator also,then how it could identify?
what is a built in function and user defined is cause i cant seriously find a decent example about it in the net
View 4 Replies View RelatedIn this program, I have to ask the user for an employee, then the program will check to see if the file for that employee exist, if it doesnt then it will automatically create the file.
ReadNew function reads the file....check to see if it exist
CreateNew function creates a new file.
In my code I have no problem with the first part of reading file.. and my createnew function works in other programs where I am asking for input of file name to create the file name. However in this code I cannot figure how to automatically pass the input filename from the ReadNew function to the CreateNew function. I can't ask the user to enter the name a second time, so I have to pass the input filename into both functions. Here is my code.
Code:
//Create a file, append to it, and read it.
#include <iostream>
#include <fstream>
#include <string.h>
#include <stdio.h>
using namespace std;
char filename[256];
string n;
string filelist;
void CreateNew(ofstream & FileNew);
[Code]...
Currently I have:
Code:
char my_array[4] = { '1', '2', '3', '4' };
how do I convert the above to a string of: "1234"
.I have this string that I need to convert into a 2d char array like this:
String str= "A,E,B,I,M,Y#N,R,C,A,T,S";
I know how to use delimiter and split string and I know how to convert but only from string to char[].I need something like this:
Input: String str= "A,E,B,I,M,Y#N,R,C,A,T,S";
Output: [A] [E] [B] [I] [M] [Y][N] [R] [C] [A] [T] [S]
I have a text file with state names, and state abbreviations, thusly:
ALASKA
AK
ARKANSAS
AR
..and so on.
I have to load the abbreviations ONLY from the file into an array of char[ - (already done and tested).
I have to get a 2 char abbreviation as a string,then test it against the state array to make sure it is a valid abbreviation. As it stands, my test is never finding an invalid abbreviation..
Here is where I get the input:
void getState() {
char state[10];
getString("Please enter the state as a 2 char abbreviation:",state,10);
printf("State Entered:%s", state);
validState(state);
[Code] ....
How do I convert a string of unknown length to a char array? I am reading strings from a file and checking if the string is a Palindrome or not. I think my palindrome function is correct, but do I do something like char [] array = string.length(); ??
#include <iostream>
#include <fstream>
#include <string>
#include <cctype>
[Code].....
I'm new in the C programming language, so I tried to create a program that reverses a string. This is my code:
/* Reverse string */
#include <stdio.h>
#include <string.h>
int main() {
char s[8]="Welcome";
[Code] ....
The output of the program is "@".