is it possible to use this code ?
#include <iostream>
int main(int argc, const char * argv[]) {
int number = 0;
std::cout << "napis cifro za array
";
std::cin >> number;
[Code]...
It does work on xcode but doesn't in microsoft visual studio 2013. Where is the problem?
I am new to C. I've been trying to use C to code some statistical functions originally coded in R. I've encountered an interesting phenomenon. In the function foo1, I declared the array v1v2b using an actual value 1999000. The function runs fine when I call it in R.
Code:
void foo1(double *x, double *y, int *nsamp){
int i, j, k, oper=2, l;
double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1));
outer_pos(x, y, nsamp, &v1v2[0]);
double v1v2b[1999000]; //<-------HERE
for(i=1; i<= 1999000]; i++){
v1v2b[i-1]=1;
} }
However, in foo2, I first create an integer variable called index, and store the value 1999000 in it. I then use it to initialize the same array. When I tried calling this function in R, it either led to a stack overflow error, or completely crashed R.
Code:
void foo2(double *x, double *y, int *nsamp){
int i, j, k, oper=2, l;
double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1));
[Code] .....
I am making program that allows the user to determine how big the array size will be and then asks the user to make up numbers to fill the array. Every time run the program on Dev C++ it says "program has stopped working"
Heres My Code:
//Assignment 19 Program 2
#include <iostream>
using namespace std;
int main()
[Code].....
I am not sure why I am receiving the error message:
Error C2466: cannot allocate an array of constant size 0
When I run the code:
Code:
int s;
cout<<"Enter the size:
";
cin>>s;
int array[s];
C++ masters,
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....
How can I stomp the arr size of 50 with the value the user inputs? The function doesn't sum up the even integers from 0 to the value the user inputs. Instead it sums up exactly that many even integers.
Is there a way I can stomp the size of the array with what the user inputs so that the sum calculation never goes past the value the user inputs?
Code:
void sumIntegers () {
int arr[50];
int i = 0;
int num = 0;
int sum = 0;
printf("
I want to sum up even integers <= 50.
[Code] .....
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
View 10 Replies View RelatedSo I'm trying to make a program, Which has nothing to do with the topic. But I ran into a problem.
I need to get a char array size of 6 doing:
char myChar[6];
but the size (6) is undefined until user input.
So I need to do char myChar[var]; (Var being 6 for now).
When I do:
char myChar[6];
It works!!!
But when I do:
int val = 6;
char myChar[val];
It doesn't work.
I'm trying to build an array of a certain size, after receiving user input. The method I'm trying is
int var = 3;
int* ar = new int[var];
When doing tests I did this (and it worked) and red flags popped off in my head.
int var = 3;
int* ar = new int[var];
ar[0] = 0;
ar[1] = 1;
ar[2] = 2;
ar[3] = 3;
ar[4] = 4;
cout << ar[0] << ar[1] << ar[2] << ar[3] << ar[4] << endl;
This method is considered safe, and possibly tell me why I'm not getting stack errors when trying to overload the array?
I am trying to use an array of a size that will be determined by the user, therefore I must use a vector, right?
In class I was told that this is how I call a vector:
vector <int> x;
Is the vector called vector? Is it called x?
Can I do this?
for(int i=0;i<=10;i++)
{
cout<<x[i];
}
Some basic ways of implementing a vector? How it works or how I can do anything with it.
Dynamic memory allocation in array in c programming. I am trying to make the user to choose the size of array they want to engage in the game.
However, i have remove the global variable which contribute the error to my code previously. Now I assigned all the arr individually but not using the global variable. However, i still not get the desired board i want. i still keep getting 9x9 array board.
And i also need limit the board size only from 4 to 9. And how do i do that.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>
#include <malloc.h>
#include <ctype.h>
#include <stdbool.h>
[Code] .....
I'm a little lost with this program. The idea is to dynamically allocate an array and increase its size every time a new integer is inputted by the user. I believe it is a memory leak but as we have just started learning this I'm not sure how to recognise it. Sometimes I can input as many integers as I want other times 2 or 3 before it crashes. When I can input enough values i exit the loop and send it to the sort function and mean calculator function, all works fine there except the last number inputted becomes this huge value not hexadecimal though... As such I'm at a loss as what to look at next, so here you go:
#include <iostream>
using namespace std;
void SelectSort(int [], int);
float MeanCalc(int [], int);
float MedianCalc(int* [], int);
[Code] .....
how to insert a variable for the size of array and prompt user to insert the elements for the array?
View 13 Replies View RelatedCode:
if (IS_LEAP_YEAR(year))
const int days_per_month[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
else
const int days_per_month[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; Is it ok to declare the array in this manner or is it bad?
And i have to ask the user for a date to enter in my program. So should I use scanf or should I store the date in a string and then use sscanf. I have to check for valid input for everything like day, month, year etc. I did it as below..
Code:
int assignments;
assignments = scanf("%d / %d / %d", &month, &day, &year);
fflush(stdin);
if (assignments != 3)
{
printf("Retry: ");
}
else
error checking.
We have been assigned to create an iTunes library. Everything compiles in my other .h file but my main is not happy with my object declaration. It keeps stating "primary expression before '{'". Here is my main code:
#include<iostream>
#include<string>
#include<fstream>
#include"myTunes.h"
using namespace std;
//function protocols
void read(string);
[Code] ......
I'm writing this program that basically interprets the rottentomatoes website. I am however having a problem declaring if it is rotten or fresh according to the rating the user enters.
I'm outputting it here:
void PrintAll(const string titles[], const int ratings[], int count) {
WriteLine('=', 50);
cout << "PRINT ALL" << endl;
WriteLine('-', 50);
[Code] .....
And here is my condition:
string RatingToString(const int ratings[], int count) {
string rank;
for(int i = 0; i < count; i++) {
[Code]....
Here is the output:
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950
==================================================
MENU
1. Add Movie
2. Print All
3. Exit
--------------------------------------------------
Enter 1-3 : 1
Title : Hitch
Rating : 90
==================================================
[Code]....
My condition works when there is only one movie, but when I add more, it gives it the new movies "ROTTEN" or "FRESH" rank.
I have the following code:
struct mystruct {
char fieldA[5];
char fieldB[7];
};
void dosomething(struct mystruct* pms) {
[Code] ....
Is there any problem doing that, even for a C89/90 compiler?
I can not set the size of my array while running porgrama. Is there any way to do this in C + +?
---- code ------
#include <iostream>
#include <string>
using namespace std;
[Code].....
I have a function
Code:
int exec_program(char * arguments[])
{
...
}
I can call it like this without a problem:
Code: char * uselessvariable[] = {"/bin/echo", "Testing", NULL};exec_program(uselessvariable);
However I get an error if I try to compile it like this:
Code: exec_program({"/bin/echo", "Testing", NULL});
How, in c, I can put this array inside of the argument in one line without having to name a new variable name?
class Hallway {
private:
//---------------------------------------------------------------
// DO_04: Declare a Light array of size MAX_LIGHTS
// Hint: look through the methods below to find the name to use
// for the array
//---------------------------------------------------------------
int numLights;
int lights[MAX_LIGHTS];
[Code] .....
I keep getting the error " this.lights[i] is not a struct or class and so you cannot use '.' " on line 34.
How am I supposed to define my lights[] array? I can't modify anything except directly after each comment block.
Here are the steps to this program:
1. Declare an array that will hold 3000 numbers
2. Initialize this array by assigning a random number to each element in the array
3. Traverse the array, modifying the current contents of each element in the array so that each value now lies between -3000 and 3000 inclusive
4. Traverse the array to compute the average value of all elements
I have never worked with arrays before and am lost!
I am having following pointer variable declaration
Code: Static double (*funcs[]) (double) = { sin,cos,tan,asin,acos};
Here funcs is an array of pointers to functions which take double as input and gives double as output with static as storage type am I right.
I'm making a flash card type console application using visual studios 2013. The flash cards contain character that I can display using unicode. So far I am looking at about 200 characters across 2 unicode blocks which I don't want to hard code into my arrays. I thought of initializing my arrays using a loop. The only problem is I don't know how to add in hexadecimal. So is there a way to initialize my array without having to input 200 values my self? Also is hexadecimal addition possible without me having to write a function for it?
View 3 Replies View RelatedHow can i write a program that allows a user to enter a size of pizza and then print the price for that size.
Example: if a user enters size ''s'' then it should display the price stored under ''s''
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.