how can i pass an array as an argument to the function? in getCoin() fcn, I am supposed to pass coins array as an argument to the function. fcn prompts user to enter coin(Date, Type and Country). values entered by user are read and assigned to the coins array. I tried the code below.
//# include "Coins.h"; #include <iostream> #include <string> using namespace std;
void foo(const double va, const int q) { int qaa[q]; ...... return; }
However, the compiler indicates allocator cannot allocate an array of constant size 0... how can I use the argument "q" to fix the size of array "qaa"?
But I was expecting this: a[]= 00 a[]= 10 a[]= 10 a[]= 00 a[]= 01 0.
This describes how the process is running in machine: 1. Defining a[2]{0,0}; ii=0; aj=0 2. Calling function func(a,ii,aj) |func({0,0},0,0)| 3. func({0,0},0,0) defining w=0; static aa=0 4. func({0,0},0,0) if(0) returns aa=1 5. func({0,0},0,0) for j=0 6. func({0,0},0,0) for Outputing "00", because a[2]={0,0}, look (1). 7. func({0,0},0,0) for if(!0) | because a[0]=0| returns w+=func(a,ii+1,j) |func({0,0},0+1,0)| and calls func({0,0},1,0) 8. func({0,0},0,0) for if func({0,0},1,0) defining w=0 9. func({0,0},0,0) for if func({1,0},1,0) if(1) returns a[0]=1, because of static aa=1, см 4. 10. func({0,0},0,0) for if func({1,0},1,0) for j=0 11. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10", because of a[2]={1,0}, look row #9 12. func({0,0},0,0) for if func({1,0},1,0) for if(!1) |because a[0]=1| 13. func({0,0},0,0) for if func({1,0},1,0) for j=1 14. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10" 15. func({0,0},0,0) for if func({1,0},1,0) for if(!0) |because a[1]=0| 16. func({0,0},0,0) for if func({1,0},1,0) for if if(1==1) |because ii=1, func({0,0},ii,0)| 17. func({0,0},0,0) for if func({1,0},1,0) for if if return 0 18. func({0,0},0,0) for if w=0 |because func({1,0},1,0) gives 0| 19. func({0,0},0,0) for j=1
And from now, something is happening that I cannot understand: 20. func({0,0},0,0) for Outputing "10"
Why so? If func has itselfs local variables, including a[2]={0,0}.
I was expecting this: 20. func({0,0},0,0) for Outputing "00"
So a[2] array is not local variable. Why it happens?
Code: #include <iostream> using namespace std; int func(bool a[],int ii,int aj) { int w=0; static bool aa=0;
I am a bit confused about how specific one must be with arguments when declaring a function. I'll show you two functions from the book I'm using to learn C to show you what I mean.
Example 1 (greatest common denominator function):
Code: void gcd (int u, int v) { int temp; printf ( "
[Code] ....
So in that function, there are exactly two arguments, because that's how many arguments the algorithm to find the gcd takes. No problem there, makes sense to me. Then further in the chapter on functions I run into this,
Example 2 (square root function):
Code: float absoluteValue (float x) { if ( x < 0 ) x = -x; return x;
[Code] ....
In this second example, we have a square root function that is preceded by an absolute value function. The absolute value function has the one argument, "float x", however when this function is called within the square root function, the arguments "guess * guess * -x" are passed to it. I'm confused how this absolute value function is working with all of that inside it, when it was originally declared with just "x." The only possibility I can think of is that this expression is treated as a single unit, but I'm not sure.
This is a c program that is failing to compile. The error occurs in the calcLabs() function. The error called out is (btw, I'm using VS 2010): Error4error C2143: syntax error : missing ';' before 'type'
I don't understand why the compiler is not letting me declare variables in the calcLabs() function!
I'm just wondering, why you have to set the length of the inner arrays declaring a function. In which moment does the code needs to be sure about the length of the inner arrays accessing an cell?
I came up with this question realizing the elements of the outer array beeing pointers to the first value of each inner array. Therefore I can access e.g. the first first element of the second inner array like this:
**(arr + 1) ...regardless of the length of any array to my mind.
error C3867: 'WordParsor::Form1::PutUpfrmIO': function call missing argument list; use '&WordParsor::Form1::PutUpfrmIO' to create a pointer to memberc:userskingc++wordparsorwordparsorForm1.h... and the suggestion fix generate another error.
One person suggested the gcroot<> object wrapper... but I do not know how to modify/declair the function or its argument type.
if (IS_LEAP_YEAR(year)) const int days_per_month[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; else const int days_per_month[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; Is it ok to declare the array in this manner or is it bad?
And i have to ask the user for a date to enter in my program. So should I use scanf or should I store the date in a string and then use sscanf. I have to check for valid input for everything like day, month, year etc. I did it as below..
We have been assigned to create an iTunes library. Everything compiles in my other .h file but my main is not happy with my object declaration. It keeps stating "primary expression before '{'". Here is my main code:
I'm writing this program that basically interprets the rottentomatoes website. I am however having a problem declaring if it is rotten or fresh according to the rating the user enters.
I'm outputting it here:
void PrintAll(const string titles[], const int ratings[], int count) { WriteLine('=', 50); cout << "PRINT ALL" << endl; WriteLine('-', 50);
[Code] .....
And here is my condition:
string RatingToString(const int ratings[], int count) { string rank; for(int i = 0; i < count; i++) {
[Code]....
Here is the output:
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950 ================================================== MENU 1. Add Movie 2. Print All 3. Exit -------------------------------------------------- Enter 1-3 : 1 Title : Hitch Rating : 90 ==================================================
[Code]....
My condition works when there is only one movie, but when I add more, it gives it the new movies "ROTTEN" or "FRESH" rank.
class Hallway { private: //--------------------------------------------------------------- // DO_04: Declare a Light array of size MAX_LIGHTS // Hint: look through the methods below to find the name to use // for the array //---------------------------------------------------------------
int numLights; int lights[MAX_LIGHTS];
[Code] .....
I keep getting the error " this.lights[i] is not a struct or class and so you cannot use '.' " on line 34.
How am I supposed to define my lights[] array? I can't modify anything except directly after each comment block.
I am writing a program in which a Fucntion has to be wriiten to parse the Command Line . When I include Code for parsing in main fuction iteslf ,its run ok . But I want to make a fucntion of that code and call it from main ,than it show Segmentation error .
By using Debugging I found Some thing is mess with " -m" Parameter of Command line , But Cant Rectify it ..
Code: int main (int argc, char *argv[]){ //get_parameter_value(argc,argv); // buffer[packet_size+1]= char ("'"); while (argc > 1) { if (argv[h][0] == '-')
1. Declare an array that will hold 3000 numbers 2. Initialize this array by assigning a random number to each element in the array 3. Traverse the array, modifying the current contents of each element in the array so that each value now lies between -3000 and 3000 inclusive 4. Traverse the array to compute the average value of all elements
I have never worked with arrays before and am lost!
I am new to C. I've been trying to use C to code some statistical functions originally coded in R. I've encountered an interesting phenomenon. In the function foo1, I declared the array v1v2b using an actual value 1999000. The function runs fine when I call it in R.
Code: void foo1(double *x, double *y, int *nsamp){ int i, j, k, oper=2, l; double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1)); outer_pos(x, y, nsamp, &v1v2[0]); double v1v2b[1999000]; //<-------HERE for(i=1; i<= 1999000]; i++){ v1v2b[i-1]=1; } }
However, in foo2, I first create an integer variable called index, and store the value 1999000 in it. I then use it to initialize the same array. When I tried calling this function in R, it either led to a stack overflow error, or completely crashed R.
Code: void foo2(double *x, double *y, int *nsamp){ int i, j, k, oper=2, l; double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1));
so in declaring a display function prototype only that displays a student test scores in the format (student name tab number of scores tab test scores )
is this right?
#ifndef STUDENTTESTSCORES_H #define STUDENTTESTSCORES_H #include <string> using namespace std; class StudentTestScores{ private:
[Code]...
and also how do we call the display function if it is in a class from the header file onto the main cpp file.
How to pass an int that I got from user input into a function to use it. I am trying to print out the words to a string of numbers.
I got the input from user. I got an absolute value of the input. I then separate the string into individual digits and name them. I can print these out. Then I started my if statement by checking if the original input was zero, and if it is, printing zero and exiting. Then I an trying to pass the digits into a switch function and this is where I go off the rails.
I was reading about void as function argument, but I did not fully understand it's meaning in C.
In C++ void foo(void) {} and void foo() {}
are the same. It means no arguments for foo function. But in C it's different. First function means the same as in C++, but second means
In C, an empty parameter list means that the number and type of the function arguments are unknown. But if it is unknown you can't use this arguments if user specifies same. Because here are no variables to store them. So doesn't result are the some? You do not get any arguments. O do I can get this arguments from some hidden variable?
For example.
void foo() { printf("%d", var); } foo(5);
It is very unclear for me. Do this apply to main function too?
int main(void) int main()
or can I use arguments given to int main() like given to int main(int argc, char* argv[])
