I made a function like follows:
void foo(const double va, const int q) {
int qaa[q];
......
return;
}
However, the compiler indicates allocator cannot allocate an array of constant size 0... how can I use the argument "q" to fix the size of array "qaa"?
I have a function
Code:
int exec_program(char * arguments[])
{
...
}
I can call it like this without a problem:
Code: char * uselessvariable[] = {"/bin/echo", "Testing", NULL};exec_program(uselessvariable);
However I get an error if I try to compile it like this:
Code: exec_program({"/bin/echo", "Testing", NULL});
How, in c, I can put this array inside of the argument in one line without having to name a new variable name?
how can i pass an array as an argument to the function? in getCoin() fcn, I am supposed to pass coins array as an argument to the function. fcn prompts user to enter coin(Date, Type and Country). values entered by user are read and assigned to the coins array. I tried the code below.
//# include "Coins.h";
#include <iostream>
#include <string>
using namespace std;
[Code].....
I am trying to build a function with an array object as argument. Please see the following code:
// main.cpp
const int a = 10;
......
//function.cpp
void test_func(double x, array<double, a> &y) {
......
}
This code cannot be compiled because the "a" in parameter is not identified. I cannot neither put const int a as argument to the function.
Here I need "a" to control size of the array from the main.cpp. How can I make this work?
// This program should get to grades and calculate the average.
#include <iostream>
#include <iomanip>
using namespace std;
void getGrades(double[], const int&);
void getTotalAver(double[], double&, const int&);
[Code] .....
When I compile it. I got a linker error.Undefined reference to the functions.I have problems passing data by reference.
The code below outputs this:
a[]= 00
a[]= 10
a[]= 10
a[]= 10
a[]= 11
a[]= 11
0.
But I was expecting this:
a[]= 00
a[]= 10
a[]= 10
a[]= 00
a[]= 01
0.
This describes how the process is running in machine:
1. Defining a[2]{0,0}; ii=0; aj=0
2. Calling function func(a,ii,aj) |func({0,0},0,0)|
3. func({0,0},0,0) defining w=0; static aa=0
4. func({0,0},0,0) if(0) returns aa=1
5. func({0,0},0,0) for j=0
6. func({0,0},0,0) for Outputing "00", because a[2]={0,0}, look (1).
7. func({0,0},0,0) for if(!0) | because a[0]=0| returns w+=func(a,ii+1,j) |func({0,0},0+1,0)| and calls func({0,0},1,0)
8. func({0,0},0,0) for if func({0,0},1,0) defining w=0
9. func({0,0},0,0) for if func({1,0},1,0) if(1) returns a[0]=1, because of static aa=1, см 4.
10. func({0,0},0,0) for if func({1,0},1,0) for j=0
11. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10", because of a[2]={1,0}, look row #9
12. func({0,0},0,0) for if func({1,0},1,0) for if(!1) |because a[0]=1|
13. func({0,0},0,0) for if func({1,0},1,0) for j=1
14. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10"
15. func({0,0},0,0) for if func({1,0},1,0) for if(!0) |because a[1]=0|
16. func({0,0},0,0) for if func({1,0},1,0) for if if(1==1) |because ii=1, func({0,0},ii,0)|
17. func({0,0},0,0) for if func({1,0},1,0) for if if return 0
18. func({0,0},0,0) for if w=0 |because func({1,0},1,0) gives 0|
19. func({0,0},0,0) for j=1
And from now, something is happening that I cannot understand:
20. func({0,0},0,0) for Outputing "10"
Why so? If func has itselfs local variables, including a[2]={0,0}.
I was expecting this:
20. func({0,0},0,0) for Outputing "00"
So a[2] array is not local variable. Why it happens?
Code:
#include <iostream>
using namespace std;
int func(bool a[],int ii,int aj) {
int w=0;
static bool aa=0;
[Code] ....
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
to return the array i shall make a pointer function thats ok.. but how do I get the size return if i dont know the size?
if I need to make AXB=C and output C my new array doesnt have a size..
How to find the size of an array in called function? When we pass the array a argument to function definition we will be having base address of array, so my understanding is that we will not get the size of an array? but is there any hacking for this to find size of array other than passing as size an argument to this called function?
View 3 Replies View RelatedWrite a function that accepts an array of integers and its size as arguments. The function should create a new array that is one element larger than the argument array. The first element of the new array should be set to 0. Element 0 of the argument array should be copied to element 1 of the new array, element 1 of the argument array should be copied to element 2 of the new array, and so forth.
The function should return a pointer to the new array. Use ONLY pointer parameters instead of arrays in both functions; use pointers (not subscripts) to move through elements of both arrays. Before calling the function, display your original array. When the function call is completed, display the new array.
Here is what i got so far:
#include <iostream>
using namespace std;
int *shifted (int * , int);
const int SIZE = 10;
int main () {
int array_size [30];
[Code] ....
I am having trouble getting the stars to output correctly in the printStars function. the final output should look something like this:
#include <iostream>
using namespace std;
int readArray(int input[], int size);
void printArray(int input[], int count);
void printStars(int input[], int size);
[Code] ...
I'm working on a piece of code written long time ago. Without getting in the details or too much context here, there is a function that declares an array of char of a size of 350,000 elements, in order to fill it (using a pointer) with the list of all running processes on the machine (using "ps -ejf" on a Linux box).
The size of the char array has been changed from 40,000 to 350,000 sometime along the years, probably because of a lack of space required.
What kind on data structure / storage would you use to store the running processes in order to eventually search for a value in it?
I searched the web for error: C3867... and the discussions where murky or obscure.
My code excerpt is:
#pragma once
#include <windows.h>
#include <stdlib.h>
#include <process.h>
void PutUpfrmIO(void *);
namespace WordParsor {
[Code] .....
I get the generic message:
error C3867: 'WordParsor::Form1::PutUpfrmIO': function call missing argument list; use '&WordParsor::Form1::PutUpfrmIO' to create a pointer to memberc:userskingc++wordparsorwordparsorForm1.h... and the suggestion fix generate another error.
One person suggested the gcroot<> object wrapper... but I do not know how to modify/declair the function or its argument type.
I am writing a program in which a Fucntion has to be wriiten to parse the Command Line . When I include Code for parsing in main fuction iteslf ,its run ok . But I want to make a fucntion of that code and call it from main ,than it show Segmentation error .
By using Debugging I found Some thing is mess with " -m" Parameter of Command line , But Cant Rectify it ..
Code:
int main (int argc, char *argv[]){
//get_parameter_value(argc,argv);
// buffer[packet_size+1]= char ("'");
while (argc > 1) {
if (argv[h][0] == '-')
[Code] .....
How to pass an int that I got from user input into a function to use it. I am trying to print out the words to a string of numbers.
I got the input from user.
I got an absolute value of the input.
I then separate the string into individual digits and name them.
I can print these out.
Then I started my if statement by checking if the original input was zero, and if it is, printing zero and exiting.
Then I an trying to pass the digits into a switch function and this is where I go off the rails.
Code:
#include <iostream>
#include <string>
#include <cstdio>
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
[Code] .....
I was reading about void as function argument, but I did not fully understand it's meaning in C.
In C++
void foo(void) {}
and
void foo() {}
are the same. It means no arguments for foo function. But in C it's different. First function means the same as in C++, but second means
In C, an empty parameter list means that the number and type of the function arguments are unknown. But if it is unknown you can't use this arguments if user specifies same. Because here are no variables to store them. So doesn't result are the some? You do not get any arguments. O do I can get this arguments from some hidden variable?
For example.
void foo() {
printf("%d", var);
}
foo(5);
It is very unclear for me. Do this apply to main function too?
int main(void)
int main()
or can I use arguments given to int main() like given to int main(int argc, char* argv[])
I have two questions :
1)
#include <iostream>
using namespace std;
void func1() {
cout << "Func1" << endl;
[Code] ....
Why ptr_func1() does not work here?
IntelliSense: expression preceding parentheses of apparent call must have (pointer-to-) function type
2) How can i pass func1 to func2 as parameter?
I tried void func1(void* function), but I think I'm wrong here.
i have used single argument conversion function which gets called in below scenario.
Code:
#include<iostream>
using namespace std;
class Demo
{
[Code]....
It is giving error "test3.cpp: In function `int main()':test3.cpp:18: syntax error before numeric constant"
But it should work as Demo d=100; works
Write a c++ function that takes int as an argument and doubles it.the function does not return a value.
View 5 Replies View RelatedI get an error when i try to compile this code. I tried to allocate memory in main function and that works. But why it doesn't work in function? I think that there is something wrong with function argument, but not sure.
Code:
#include <iostream>
#include <fstream>
using namespace std;
struct Word
[Code].....
What does collection of parameters as argument of a function in C mean? Also any place I can refer to find those parameters?
Googling gives me Parameters and Arguments But not really sure whether that is what is needed.
I was wondering if one could write a function that could accept one or the other variable type.
Ex: I have 2 arrays, int** and double**, and a function
Code: void PGMWrite(double** Matrix, int Matrix_dimension){.....}
Is there any way to change the function to
Code: void PGMWrite(int** Matrix || double** Matrix, int Matrix_dimension){.....}
And then have some sort of type identifier in the function that picks the correct section via an if loop? If so how, and how would I identify in the function if the input it type double or int?
I am using a small robotic-car that is controlled by writing C/C++ codes under Linux. I need to use a particular function from the library provided by the manufacturer. The relevant API documentation for the function is:
BASEBOARD_ERROR_KIND ZMP zrc :: :: :: Baseboard GetRS232Data (char * msg )
RS232 data acquisition.
Argument:
[Out] msg Address of the acquired data.
Returns:
BASE_OK RS232 data acquisition success
BASE_BASE_232_GETDATA_ERR RS232 data acquisition failure
I have trouble writing the relevant code in the main program that invokes this function. Here is a snippet of what I have tried:
# include "Baseboard.h"
int main () {
Baseboard _Baseboard; // Class name is Baseboard
char *msg ;
[Code] ......
The part where I am uncertain is how to handle the char pointer "msg" in the declaration, function call and referencing. According to the documentation, the char pointer "msg" is the output of the function so I presume that is is somehow dynamically allocated. Am I handling the char pointer properly in the declaration, function call and referencing parts?
Another related question I have is: I am printing out the value of the variable "dummy". I always get 0 for it. Since the variable "dummy" is an enum of type BASEBOARD_ERROR_KIND which can take on two values (first value represents success and the second failure), it is alright to get a integer value of 0 for it if the function call was successful ? (I do not have much experience with using enums so this is a enum-related question on whether we can get an integer value representing the first enum value) .
I have same type of errors in my program
#include "iostream"
#include <stdio.h>
#include <conio.h>
[Code].....
We just started going into classes for my C++ class. Everything looks right but the error is saying i'm missing an argument in my getspending call.
Heres the code:
for (int i; i < 0; i++) {
cout << members[i].getfirst << " "<< members[i].getlast << endl;
cout << "member ID: " << members[i].getmem << endl;
cout << "They have purchased " << members[i].getbooks << " books" << endl;
cout << "$" << members[i].getspending << endl;
}
Here's my get spending function:
double memberType::getspending() {
return spent;
}
What argument am I missing?
Why does the following code compile and execute without any error? I mean, the function compareid should get 2 arguments so why does the compiler not complaining, is it because of the type of arguments?
Code:
#include <stdio.h>
int compareid(void* info, int value); // ansi declaration
int compareid(void* info, int value)
[Code] .....