C++ :: Function With Array Object As Argument
Jan 18, 2013
I am trying to build a function with an array object as argument. Please see the following code:
// main.cpp
const int a = 10;
......
//function.cpp
void test_func(double x, array<double, a> &y) {
......
}
This code cannot be compiled because the "a" in parameter is not identified. I cannot neither put const int a as argument to the function.
Here I need "a" to control size of the array from the main.cpp. How can I make this work?
View 9 Replies
Sep 14, 2013
I have a function
Code:
int exec_program(char * arguments[])
{
...
}
I can call it like this without a problem:
Code: char * uselessvariable[] = {"/bin/echo", "Testing", NULL};exec_program(uselessvariable);
However I get an error if I try to compile it like this:
Code: exec_program({"/bin/echo", "Testing", NULL});
How, in c, I can put this array inside of the argument in one line without having to name a new variable name?
View 2 Replies
View Related
Feb 7, 2013
The code below outputs this:
a[]= 00
a[]= 10
a[]= 10
a[]= 10
a[]= 11
a[]= 11
0.
But I was expecting this:
a[]= 00
a[]= 10
a[]= 10
a[]= 00
a[]= 01
0.
This describes how the process is running in machine:
1. Defining a[2]{0,0}; ii=0; aj=0
2. Calling function func(a,ii,aj) |func({0,0},0,0)|
3. func({0,0},0,0) defining w=0; static aa=0
4. func({0,0},0,0) if(0) returns aa=1
5. func({0,0},0,0) for j=0
6. func({0,0},0,0) for Outputing "00", because a[2]={0,0}, look (1).
7. func({0,0},0,0) for if(!0) | because a[0]=0| returns w+=func(a,ii+1,j) |func({0,0},0+1,0)| and calls func({0,0},1,0)
8. func({0,0},0,0) for if func({0,0},1,0) defining w=0
9. func({0,0},0,0) for if func({1,0},1,0) if(1) returns a[0]=1, because of static aa=1, см 4.
10. func({0,0},0,0) for if func({1,0},1,0) for j=0
11. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10", because of a[2]={1,0}, look row #9
12. func({0,0},0,0) for if func({1,0},1,0) for if(!1) |because a[0]=1|
13. func({0,0},0,0) for if func({1,0},1,0) for j=1
14. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10"
15. func({0,0},0,0) for if func({1,0},1,0) for if(!0) |because a[1]=0|
16. func({0,0},0,0) for if func({1,0},1,0) for if if(1==1) |because ii=1, func({0,0},ii,0)|
17. func({0,0},0,0) for if func({1,0},1,0) for if if return 0
18. func({0,0},0,0) for if w=0 |because func({1,0},1,0) gives 0|
19. func({0,0},0,0) for j=1
And from now, something is happening that I cannot understand:
20. func({0,0},0,0) for Outputing "10"
Why so? If func has itselfs local variables, including a[2]={0,0}.
I was expecting this:
20. func({0,0},0,0) for Outputing "00"
So a[2] array is not local variable. Why it happens?
Code:
#include <iostream>
using namespace std;
int func(bool a[],int ii,int aj) {
int w=0;
static bool aa=0;
[Code] ....
View 3 Replies
View Related
Dec 26, 2014
I am writing a program in which a Fucntion has to be wriiten to parse the Command Line . When I include Code for parsing in main fuction iteslf ,its run ok . But I want to make a fucntion of that code and call it from main ,than it show Segmentation error .
By using Debugging I found Some thing is mess with " -m" Parameter of Command line , But Cant Rectify it ..
Code:
int main (int argc, char *argv[]){
//get_parameter_value(argc,argv);
// buffer[packet_size+1]= char ("'");
while (argc > 1) {
if (argv[h][0] == '-')
[Code] .....
View 3 Replies
View Related
May 21, 2013
How to pass an int that I got from user input into a function to use it. I am trying to print out the words to a string of numbers.
I got the input from user.
I got an absolute value of the input.
I then separate the string into individual digits and name them.
I can print these out.
Then I started my if statement by checking if the original input was zero, and if it is, printing zero and exiting.
Then I an trying to pass the digits into a switch function and this is where I go off the rails.
Code:
#include <iostream>
#include <string>
#include <cstdio>
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
[Code] .....
View 7 Replies
View Related
Mar 24, 2014
I was reading about void as function argument, but I did not fully understand it's meaning in C.
In C++
void foo(void) {}
and
void foo() {}
are the same. It means no arguments for foo function. But in C it's different. First function means the same as in C++, but second means
In C, an empty parameter list means that the number and type of the function arguments are unknown. But if it is unknown you can't use this arguments if user specifies same. Because here are no variables to store them. So doesn't result are the some? You do not get any arguments. O do I can get this arguments from some hidden variable?
For example.
void foo() {
printf("%d", var);
}
foo(5);
It is very unclear for me. Do this apply to main function too?
int main(void)
int main()
or can I use arguments given to int main() like given to int main(int argc, char* argv[])
View 4 Replies
View Related
Jun 12, 2013
I was wondering if one could write a function that could accept one or the other variable type.
Ex: I have 2 arrays, int** and double**, and a function
Code: void PGMWrite(double** Matrix, int Matrix_dimension){.....}
Is there any way to change the function to
Code: void PGMWrite(int** Matrix || double** Matrix, int Matrix_dimension){.....}
And then have some sort of type identifier in the function that picks the correct section via an if loop? If so how, and how would I identify in the function if the input it type double or int?
View 4 Replies
View Related
Feb 5, 2014
I am using a small robotic-car that is controlled by writing C/C++ codes under Linux. I need to use a particular function from the library provided by the manufacturer. The relevant API documentation for the function is:
BASEBOARD_ERROR_KIND ZMP zrc :: :: :: Baseboard GetRS232Data (char * msg )
RS232 data acquisition.
Argument:
[Out] msg Address of the acquired data.
Returns:
BASE_OK RS232 data acquisition success
BASE_BASE_232_GETDATA_ERR RS232 data acquisition failure
I have trouble writing the relevant code in the main program that invokes this function. Here is a snippet of what I have tried:
# include "Baseboard.h"
int main () {
Baseboard _Baseboard; // Class name is Baseboard
char *msg ;
[Code] ......
The part where I am uncertain is how to handle the char pointer "msg" in the declaration, function call and referencing. According to the documentation, the char pointer "msg" is the output of the function so I presume that is is somehow dynamically allocated. Am I handling the char pointer properly in the declaration, function call and referencing parts?
Another related question I have is: I am printing out the value of the variable "dummy". I always get 0 for it. Since the variable "dummy" is an enum of type BASEBOARD_ERROR_KIND which can take on two values (first value represents success and the second failure), it is alright to get a integer value of 0 for it if the function call was successful ? (I do not have much experience with using enums so this is a enum-related question on whether we can get an integer value representing the first enum value) .
View 2 Replies
View Related
Jul 3, 2013
I am trying to pass function as argument to another function. My idea is to write function that can works with any type of array, and for it to be able to compare array items I'd like to use my own compareTo function. But I need to be able to pass function to use for comparing argument.
To say it short I am trying to write my own qsort that would take compareTo as one argument just like original qsort does.
Here is my code
// test.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <windows.h>
template <class T>
int compareTo( T a,T b){
[code]....
and errors
1>d:my documentsvisual studio 2012projects est est est.cpp(29): error C2896: 'void DoSomething(T,int (__cdecl *)(T,T))' : cannot use function template 'int cmp(T,T)' as a function argument
1> d:my documentsvisual studio 2012projects est est est.cpp(8) : see declaration of 'cmp'
1>d:my documentsvisual studio 2012projects est est est.cpp(29): error C2784: 'void DoSomething(T,int (__cdecl *)(T,T))' : could not deduce template argument for 'T' from 'int [3]'
1> d:my documentsvisual studio 2012projects est est est.cpp(21) : see declaration of 'DoSomething'
View 2 Replies
View Related
Apr 20, 2013
I was trying to look up solution for this for quite a while already but found nothing. I am writing a simple console based turn based RPG game for my class project. I was trying to have a member function attack() in class of the player character, which affects the component called health of the class Enemy. both this classes are inherited from the base class Unit. I tried to pass the object of type enemy as an argument to the function attack, but the function call gives me Error: too many arguments in function call. Here's the code for classes:
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>
using namespace std;
class Unit {
protected: int power, intellect;
[Code] ....
View 5 Replies
View Related
Aug 8, 2014
#include <iostream>
#include <string>
std::ostream& operator<<(std::ostream& os, const std::string& str) {
os << '[';
[Code].....
In the above program, I define an operator<< function in global namespace which has exactly the same signature as the one define in <string> header : [URL] . In the main function, I call operator<< on cout and a string, after which I guess it would cause ambiguity. The result is out of my anticipation, it compiles and prints [hi]. So I guess my function is a better match because it does not require argument-dependent lookup (ADL). Moreover, even if I add using namespace std; at the beginning of the main function, the program still compiles and prints [hi].
In short, I have two question:
#1 : Why is my function a better match (therefore no ambiguity) in the two cases respectively (with and without using namespace std;)?
#2 : Does using namespace affect ADL? Is ADL still performed after applying using namespace, or is it not performed because the function is thrown into global namespace?
View 3 Replies
View Related
Jun 20, 2013
When we use a function template, we use a function template like a regular function, for example,
Code:
template<class T>
void foo(T t1, T t2)
{
}
foo(1,3);
Based on the arguments passed to foo, the compiler can deduct the type T. But on the other hand, when we use a class template, we always need to specify the type, for example,
Code:
template<class T>
struct sum {
static void foo(T t1, T t2)
{
}
};
sum<int>::foo(1,3);
Here we can't call sum::foo(1,3), otherwise we get compiler errors. My question is why the compiler can't deduct the type based on the arguments passed to foo? In addition, if we call function template foo like this,
Code:
foo(1, '3');
Then we get compiler errors. We need to specify the type like foo<int>(1.'3'). Since '3' can be always treated as integer, why we need to specify the type here?
View 7 Replies
View Related
