Visual C++ :: Being Argument Array Not Copied When Calling Function

The code below outputs this:
a[]= 00
a[]= 10
a[]= 10
a[]= 10
a[]= 11
a[]= 11
0.

But I was expecting this:
a[]= 00
a[]= 10
a[]= 10
a[]= 00
a[]= 01
0.

This describes how the process is running in machine:
1. Defining a[2]{0,0}; ii=0; aj=0
2. Calling function func(a,ii,aj) |func({0,0},0,0)|
3. func({0,0},0,0) defining w=0; static aa=0
4. func({0,0},0,0) if(0) returns aa=1
5. func({0,0},0,0) for j=0
6. func({0,0},0,0) for Outputing "00", because a[2]={0,0}, look (1).
7. func({0,0},0,0) for if(!0) | because a[0]=0| returns w+=func(a,ii+1,j) |func({0,0},0+1,0)| and calls func({0,0},1,0)
8. func({0,0},0,0) for if func({0,0},1,0) defining w=0
9. func({0,0},0,0) for if func({1,0},1,0) if(1) returns a[0]=1, because of static aa=1, см 4.
10. func({0,0},0,0) for if func({1,0},1,0) for j=0
11. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10", because of a[2]={1,0}, look row #9
12. func({0,0},0,0) for if func({1,0},1,0) for if(!1) |because a[0]=1|
13. func({0,0},0,0) for if func({1,0},1,0) for j=1
14. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10"
15. func({0,0},0,0) for if func({1,0},1,0) for if(!0) |because a[1]=0|
16. func({0,0},0,0) for if func({1,0},1,0) for if if(1==1) |because ii=1, func({0,0},ii,0)|
17. func({0,0},0,0) for if func({1,0},1,0) for if if return 0
18. func({0,0},0,0) for if w=0 |because func({1,0},1,0) gives 0|
19. func({0,0},0,0) for j=1

And from now, something is happening that I cannot understand:
20. func({0,0},0,0) for Outputing "10"

Why so? If func has itselfs local variables, including a[2]={0,0}.

I was expecting this:
20. func({0,0},0,0) for Outputing "00"

So a[2] array is not local variable. Why it happens?

Code:
#include <iostream>
using namespace std;
int func(bool a[],int ii,int aj) {
int w=0;
static bool aa=0;

[Code] ....