I'm trying to copy one element value in an array to other array(Line no: 19) in the following program.
There is some problem due to which it is displaying ZERO.
Need to fix the Problem in this function member.
int tdms (int m, float* x,float* y,float* z, float* w, float* u,float tt,float ddt ){
for(int k=1; k<=2;k++) {
cout<<"
Time step: "<<ddt*k<<"
[Code] .....
The code below outputs this:
a[]= 00
a[]= 10
a[]= 10
a[]= 10
a[]= 11
a[]= 11
0.
But I was expecting this:
a[]= 00
a[]= 10
a[]= 10
a[]= 00
a[]= 01
0.
This describes how the process is running in machine:
1. Defining a[2]{0,0}; ii=0; aj=0
2. Calling function func(a,ii,aj) |func({0,0},0,0)|
3. func({0,0},0,0) defining w=0; static aa=0
4. func({0,0},0,0) if(0) returns aa=1
5. func({0,0},0,0) for j=0
6. func({0,0},0,0) for Outputing "00", because a[2]={0,0}, look (1).
7. func({0,0},0,0) for if(!0) | because a[0]=0| returns w+=func(a,ii+1,j) |func({0,0},0+1,0)| and calls func({0,0},1,0)
8. func({0,0},0,0) for if func({0,0},1,0) defining w=0
9. func({0,0},0,0) for if func({1,0},1,0) if(1) returns a[0]=1, because of static aa=1, см 4.
10. func({0,0},0,0) for if func({1,0},1,0) for j=0
11. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10", because of a[2]={1,0}, look row #9
12. func({0,0},0,0) for if func({1,0},1,0) for if(!1) |because a[0]=1|
13. func({0,0},0,0) for if func({1,0},1,0) for j=1
14. func({0,0},0,0) for if func({1,0},1,0) for Outputing "10"
15. func({0,0},0,0) for if func({1,0},1,0) for if(!0) |because a[1]=0|
16. func({0,0},0,0) for if func({1,0},1,0) for if if(1==1) |because ii=1, func({0,0},ii,0)|
17. func({0,0},0,0) for if func({1,0},1,0) for if if return 0
18. func({0,0},0,0) for if w=0 |because func({1,0},1,0) gives 0|
19. func({0,0},0,0) for j=1
And from now, something is happening that I cannot understand:
20. func({0,0},0,0) for Outputing "10"
Why so? If func has itselfs local variables, including a[2]={0,0}.
I was expecting this:
20. func({0,0},0,0) for Outputing "00"
So a[2] array is not local variable. Why it happens?
Code:
#include <iostream>
using namespace std;
int func(bool a[],int ii,int aj) {
int w=0;
static bool aa=0;
[Code] ....
I recently downloaded the ' code:blocks ' file. After I tried some code the compiler stated there was an error with
' #include<iostream> '.
Since I'm not a C++ programmer, right now, I'm confused. This was copied directly from the e-book I downloaded. After I uninstalled this program, I re downloaded it and now it comes up with a new error while opening Code-blocks.
This new error states ' Can't find compiler executable in your configured search path's for GNU GCC compiler '
I'm trying to copy a file into another file and copy the number of characters copied but my while loop doesn't even enter into a loop indicating the file is already at the EOF file character. I've confirmed this by placing the printf() statement inside the while loop, which doesn't print anything and by keeping it out of the while loop and changing the chars_copied to something like 9, it prints 9 for number of chars_copied. I don't understand why the file is already at the EOF character, I've tried this with a few more files, it's the same result.
Code:
#include <stdio.h>
int main(void){
FILE *input_file, *output_file;
int c, chars_copied=0;
if((input_file=fopen("C:workmarks.txt", "r"))==NULL)
perror("input file open failed");
[Code] ....
I have this code for a computer project... (store management) but the character strings are not copied on text file..
#include<iostream.h>
#include<conio.h>
#include<fstream.h>
class Store {
public:
char *item_name[5];
store()
[Code] .....
Now when i run the program, it gives a error :::
ERROR
address 0x0
How can i write these strings to the text file?
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) {
if (cards[0]) {
hideFirstCard=true;
cards[0] = '**';
} for(int a = 0; a <= numCards; a++) {
cout >> showCard(cards[a]);
} }
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
Write a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
View 6 Replies View RelatedThe program should store a character array in reverse order then display the reversed array. I have also included in the code that will display the actual characters into the array as it loops through. So I know the characters are being stored, but why doesn't it display the entire string when I call it?
Code:
#include<stdio.h>
int main(){
char str[50];
char rev[50];
printf("Enter Desired Text: ");
scanf ("%[^
[Code] ....
Is it just my compiler?
I wrote this simplified version of a program i am writing that parses data in UDP packets. In the process of doing so i pretty much answered all my questions and fix all the problems i was having.
decodeSystemMap function will be in loop, and will proccess packets that have mostly the same data, only a few items will be added or changed or deleted.
whats the best way to check if there are any new, deleted, or removed items in the packet and only modify those?
Is there anything unsafe / dangrous about the way the code is now?
Code:
/* * File: main.c
* Author: david
*
* Created on May 23, 2013, 11:57 AM
*/
#include <stdio.h>
#include <stdlib.h>
[Code] ....
im trying to read in 1 array and get 2 as outputs from 3 different functions.my read array is easy enough were im getting confused is how to read that array, separate it and take out only the parts i want and place them into a 2nd, then again a 3rd array.i have the following so far:
Code:
#include<stdlib.h>#include<stdio.h>
#include<unistd.h>
#define SIZE 10
}
[code]....
this compiles without a complaint, but when i go to run it no longer responds after taking the 10th element (well 9th if counting from 0).I think i have the if correct for the even odd section, but when i try to populate B or C array with the output of that if statement from A is were i think things are dying...
#include <iostream>
#include<fstream>
int decryption(int);
int multiply(int,int[][2]);
using namespace std;
main(){
int n;
ifstream inFile;
inFile.open ("out.txt");
[Code] .....
I was trying to store numbers read from a text file into 2D array but I am getting the error above.here is where the error occurs:
line 33: cout<<m[i][j]<<" ";
Assume you want to use a loop to process an array of characters starting from the beginning of the array. You want the loop to stop when you read the null terminator character from the array. Fill in the loop test condition that will make this work correctly.
index = 0;
ch = array[index];
while ( _____________________________)
{
// process the character
index++;
ch = array[index];
}
I know to read a strings into array and tables.. what is they are mixed up?? strings are just names ( 3 characters) and there are bunch of table.. the max size was set to 60
ex. text file
JES
DAN
JEN
.
.
.
01010101
10010101
RAM
JET
01010010
10100101
.... and so on
should i use a while loop?
I have a multidimensional array that runs parallel with a string array
Lincoln 120 300 400
Parks 100 500 250
Shakespeare 0 30 50
Ghandi 250 100 40
Ashe 300 50 175
Rodriguez 87 118 320
Curie 284 0 112
I need to sort this and I know how to do it. But I need to sort it again with the highest value in the first row and keep all information in that row paired with the name . So
Lincoln 120 300 400
Parks 100 500 250
Parks 100 500 250
Lincoln 120 300 400
I need so swap this whole rows. I'm using dynamic array. So my question is Do I have to do a bunch of temps to move them? Or is there a way to move the whole int array row as a single unit?
But it can the other way around
Code:
static_Array= dynamic_Array;
dynamic_Array = static_Array;
The second statement works and i'm able to print out both arrays with equal values but with the first
[code] static_Array = dynamic_Array;I get incompatible types in assignment of 'int*' to 'int [7]' is the error I get [/code]
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code:
#include<stdio.h>
void display(int array[],int size) {
int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
Trying to get code to look like
Row 1: ^^^
Row 2: ^^^
Row 3: ^^^
const int siz = 3;
for (int t=0; t<siz;t++) {
cout << "Row" << t+1 << ":";
cout << endl;
[Code] ....
Also was wondering if i wanted to separately ask the user to choose a location to add a char who would i do that ?
( im thinking * cin << arry[][]; ? not sure but ask for them separately
array []1
array []2
= array [][]
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
1 0 0 0 0 0
1 2 0 0 0 0
1 2 3 0 0 0
1 2 3 4 0 0
1 2 3 4 5 0
1 2 3 4 5 6
"
I'm having trouble converting this binary search with an int array to use a string array..
Code:
#include <iostream>
#include <string>
using namespace std;
// Function prototype
int binarySearch(string [], int);
[Code] .....
I'm trying extremely hard to understand pointers and I have the basic concept down.. I feel as though my knowledge of dynamically allocated pointers and pointers in general is not enough to understand the logic behind what I'm trying to do. The problem is that the donations array must be able to accept any number of donations. I've made it do just that, but there is also an array of pointers which must each point to the same element in the donations array. The program works if I assign int *arrPtr[100] for example, but it does not work if I try to dynamically allocate it to accept the same number of elements for donations entered by the user. Here it's the snippet
#include <iostream>
using namespace std;
//Function Prototypes
[Code]....
Objective: Write a function with the given signature that will take a sorted array of integers and return the array compacted. That is, given an array containing: 1, 2, 6, 8, 8, 8, 9, 10, 10, when the function returns, the contents of the array should be: 1, 2, 6, 8, 9, 10.
Restrictions:
Cannot use Distinct method
Signature:
public static int[] CompactArray(int[] input)
My program takes the values from one array and searches for their index position in another array (linear search algorithm). This is an example of the issue im having(its not part of the actual code below)
a[]={1,2,3,4,5,6}
Arr[]={1,2,2,3,4,5}
If it finds 1 in arr, it returns 0, which is fine but if it finds 2 in arr it return 1 and 1 instead of 1 and 2.
for (int q=0; q=size2;q++) {
int rs=secfunc(array1;size1;array2[q])
if(rs>=0) {
cout<<rs << "";
[Code] .....
I have the following code which attempts to assign a u_int8 array of 256 to an unsigned char[256]:
Code:
unsigned char testData[256]=pSample->data;
I get the compilation error:
error C2440: 'initializing' : cannot convert from 'const uint8_t [256]' to 'unsigned char [256]'
What is the safe way to cast or convert here?
Example :
Code:
struct x {
int v[4];
};
const x test = { 0, 1, 2, 3 };
Why can I do this? How does the compiler know to write to this in the proper way? I get that v would be contiguous. Does that have something to do with it?