i have used single argument conversion function which gets called in below scenario.
Code:
#include<iostream>
using namespace std;
class Demo
{
[Code]....
It is giving error "test3.cpp: In function `int main()':test3.cpp:18: syntax error before numeric constant"
But it should work as Demo d=100; works
I searched the web for error: C3867... and the discussions where murky or obscure.
My code excerpt is:
#pragma once
#include <windows.h>
#include <stdlib.h>
#include <process.h>
void PutUpfrmIO(void *);
namespace WordParsor {
[Code] .....
I get the generic message:
error C3867: 'WordParsor::Form1::PutUpfrmIO': function call missing argument list; use '&WordParsor::Form1::PutUpfrmIO' to create a pointer to memberc:userskingc++wordparsorwordparsorForm1.h... and the suggestion fix generate another error.
One person suggested the gcroot<> object wrapper... but I do not know how to modify/declair the function or its argument type.
I am writing a program in which a Fucntion has to be wriiten to parse the Command Line . When I include Code for parsing in main fuction iteslf ,its run ok . But I want to make a fucntion of that code and call it from main ,than it show Segmentation error .
By using Debugging I found Some thing is mess with " -m" Parameter of Command line , But Cant Rectify it ..
Code:
int main (int argc, char *argv[]){
//get_parameter_value(argc,argv);
// buffer[packet_size+1]= char ("'");
while (argc > 1) {
if (argv[h][0] == '-')
[Code] .....
So I'm writing a data structure from scratch as part of a university assignment in c++, and I have to write an iterator for it. The problem involves comparison between constant iterators and normal iterators, and I'm going about it in this way: I wrote a constructor of normal iterator which takes a const iterator as its only parameter, hoping that the comparison operator between two normal iterators will be enough:
btree_iterator(const_btree_iterator<T>&conv):_target(conv._target),_index(conv._index),_last(conv._last){}
(and somewhere else)
template <typename T>
bool operator!=(btree_iterator<T> one,btree_iterator<T> other){
return !(other == one);
}
and I'm testing it in this way:
btree<int> bl(5);//the data structure
auto iter = bl.begin();
iter != bl.cend(); //trying to compare iterator with const iterator
but apparently this is wrong, since the compiler tells me something along the line of "no function 'operator!=' which takes ......" It seems the constructor is alright, since the following works:
btree<int>::iterator i(bl.cend());
Am I getting something fundamentally wrong about it? How is this functionality actually implemented in C++ library containers like vector?
How to pass an int that I got from user input into a function to use it. I am trying to print out the words to a string of numbers.
I got the input from user.
I got an absolute value of the input.
I then separate the string into individual digits and name them.
I can print these out.
Then I started my if statement by checking if the original input was zero, and if it is, printing zero and exiting.
Then I an trying to pass the digits into a switch function and this is where I go off the rails.
Code:
#include <iostream>
#include <string>
#include <cstdio>
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
[Code] .....
I was reading about void as function argument, but I did not fully understand it's meaning in C.
In C++
void foo(void) {}
and
void foo() {}
are the same. It means no arguments for foo function. But in C it's different. First function means the same as in C++, but second means
In C, an empty parameter list means that the number and type of the function arguments are unknown. But if it is unknown you can't use this arguments if user specifies same. Because here are no variables to store them. So doesn't result are the some? You do not get any arguments. O do I can get this arguments from some hidden variable?
For example.
void foo() {
printf("%d", var);
}
foo(5);
It is very unclear for me. Do this apply to main function too?
int main(void)
int main()
or can I use arguments given to int main() like given to int main(int argc, char* argv[])
I have two questions :
1)
#include <iostream>
using namespace std;
void func1() {
cout << "Func1" << endl;
[Code] ....
Why ptr_func1() does not work here?
IntelliSense: expression preceding parentheses of apparent call must have (pointer-to-) function type
2) How can i pass func1 to func2 as parameter?
I tried void func1(void* function), but I think I'm wrong here.
I have code for conversion of longitude and latitude and I need to reverse the function so it will work in opposite direction:
Code:
float LongitudeDeg = argv[1]; // some longitude
float LatitudeDeg = argv[2]; // some latitude
uint32_t u,v,l,n;
l=15; // l range is 2-29
[Code] .....
On start of the code we know longitude,latitude and l. And the result is u and v. And I need function when I will know the u and v, possibly l too, to calculate longitude, latitude.
Write a c++ function that takes int as an argument and doubles it.the function does not return a value.
View 5 Replies View RelatedI get an error when i try to compile this code. I tried to allocate memory in main function and that works. But why it doesn't work in function? I think that there is something wrong with function argument, but not sure.
Code:
#include <iostream>
#include <fstream>
using namespace std;
struct Word
[Code].....
I have a function
Code:
int exec_program(char * arguments[])
{
...
}
I can call it like this without a problem:
Code: char * uselessvariable[] = {"/bin/echo", "Testing", NULL};exec_program(uselessvariable);
However I get an error if I try to compile it like this:
Code: exec_program({"/bin/echo", "Testing", NULL});
How, in c, I can put this array inside of the argument in one line without having to name a new variable name?
What does collection of parameters as argument of a function in C mean? Also any place I can refer to find those parameters?
Googling gives me Parameters and Arguments But not really sure whether that is what is needed.
I was wondering if one could write a function that could accept one or the other variable type.
Ex: I have 2 arrays, int** and double**, and a function
Code: void PGMWrite(double** Matrix, int Matrix_dimension){.....}
Is there any way to change the function to
Code: void PGMWrite(int** Matrix || double** Matrix, int Matrix_dimension){.....}
And then have some sort of type identifier in the function that picks the correct section via an if loop? If so how, and how would I identify in the function if the input it type double or int?
I am using a small robotic-car that is controlled by writing C/C++ codes under Linux. I need to use a particular function from the library provided by the manufacturer. The relevant API documentation for the function is:
BASEBOARD_ERROR_KIND ZMP zrc :: :: :: Baseboard GetRS232Data (char * msg )
RS232 data acquisition.
Argument:
[Out] msg Address of the acquired data.
Returns:
BASE_OK RS232 data acquisition success
BASE_BASE_232_GETDATA_ERR RS232 data acquisition failure
I have trouble writing the relevant code in the main program that invokes this function. Here is a snippet of what I have tried:
# include "Baseboard.h"
int main () {
Baseboard _Baseboard; // Class name is Baseboard
char *msg ;
[Code] ......
The part where I am uncertain is how to handle the char pointer "msg" in the declaration, function call and referencing. According to the documentation, the char pointer "msg" is the output of the function so I presume that is is somehow dynamically allocated. Am I handling the char pointer properly in the declaration, function call and referencing parts?
Another related question I have is: I am printing out the value of the variable "dummy". I always get 0 for it. Since the variable "dummy" is an enum of type BASEBOARD_ERROR_KIND which can take on two values (first value represents success and the second failure), it is alright to get a integer value of 0 for it if the function call was successful ? (I do not have much experience with using enums so this is a enum-related question on whether we can get an integer value representing the first enum value) .
I have same type of errors in my program
#include "iostream"
#include <stdio.h>
#include <conio.h>
[Code].....
how can i pass an array as an argument to the function? in getCoin() fcn, I am supposed to pass coins array as an argument to the function. fcn prompts user to enter coin(Date, Type and Country). values entered by user are read and assigned to the coins array. I tried the code below.
//# include "Coins.h";
#include <iostream>
#include <string>
using namespace std;
[Code].....
I am trying to build a function with an array object as argument. Please see the following code:
// main.cpp
const int a = 10;
......
//function.cpp
void test_func(double x, array<double, a> &y) {
......
}
This code cannot be compiled because the "a" in parameter is not identified. I cannot neither put const int a as argument to the function.
Here I need "a" to control size of the array from the main.cpp. How can I make this work?
We just started going into classes for my C++ class. Everything looks right but the error is saying i'm missing an argument in my getspending call.
Heres the code:
for (int i; i < 0; i++) {
cout << members[i].getfirst << " "<< members[i].getlast << endl;
cout << "member ID: " << members[i].getmem << endl;
cout << "They have purchased " << members[i].getbooks << " books" << endl;
cout << "$" << members[i].getspending << endl;
}
Here's my get spending function:
double memberType::getspending() {
return spent;
}
What argument am I missing?
I made a function like follows:
void foo(const double va, const int q) {
int qaa[q];
......
return;
}
However, the compiler indicates allocator cannot allocate an array of constant size 0... how can I use the argument "q" to fix the size of array "qaa"?
Why does the following code compile and execute without any error? I mean, the function compareid should get 2 arguments so why does the compiler not complaining, is it because of the type of arguments?
Code:
#include <stdio.h>
int compareid(void* info, int value); // ansi declaration
int compareid(void* info, int value)
[Code] .....
I am trying to pass function as argument to another function. My idea is to write function that can works with any type of array, and for it to be able to compare array items I'd like to use my own compareTo function. But I need to be able to pass function to use for comparing argument.
To say it short I am trying to write my own qsort that would take compareTo as one argument just like original qsort does.
Here is my code
// test.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <windows.h>
template <class T>
int compareTo( T a,T b){
[code]....
and errors
1>d:my documentsvisual studio 2012projects est est est.cpp(29): error C2896: 'void DoSomething(T,int (__cdecl *)(T,T))' : cannot use function template 'int cmp(T,T)' as a function argument
1> d:my documentsvisual studio 2012projects est est est.cpp(8) : see declaration of 'cmp'
1>d:my documentsvisual studio 2012projects est est est.cpp(29): error C2784: 'void DoSomething(T,int (__cdecl *)(T,T))' : could not deduce template argument for 'T' from 'int [3]'
1> d:my documentsvisual studio 2012projects est est est.cpp(21) : see declaration of 'DoSomething'
I am trying to use fgets to read in a string, but keep getting a "no conversion function from std::string to char" error.
View 2 Replies View Relatedchar intToStr(int a) {
int n, i, j, sign, set;
char r[10], s[10];
if (a[0] == '-')
sign = -1;
if (sign == -1)
[Code] ....
I have doubt at the time of handling of negative numbers at the time of converting to string ....
I was trying to look up solution for this for quite a while already but found nothing. I am writing a simple console based turn based RPG game for my class project. I was trying to have a member function attack() in class of the player character, which affects the component called health of the class Enemy. both this classes are inherited from the base class Unit. I tried to pass the object of type enemy as an argument to the function attack, but the function call gives me Error: too many arguments in function call. Here's the code for classes:
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>
using namespace std;
class Unit {
protected: int power, intellect;
[Code] ....
#include <iostream>
#include <string>
std::ostream& operator<<(std::ostream& os, const std::string& str) {
os << '[';
[Code].....
In the above program, I define an operator<< function in global namespace which has exactly the same signature as the one define in <string> header : [URL] . In the main function, I call operator<< on cout and a string, after which I guess it would cause ambiguity. The result is out of my anticipation, it compiles and prints [hi]. So I guess my function is a better match because it does not require argument-dependent lookup (ADL). Moreover, even if I add using namespace std; at the beginning of the main function, the program still compiles and prints [hi].
In short, I have two question:
#1 : Why is my function a better match (therefore no ambiguity) in the two cases respectively (with and without using namespace std;)?
#2 : Does using namespace affect ADL? Is ADL still performed after applying using namespace, or is it not performed because the function is thrown into global namespace?
I have to write an example in which you use a function having as argument a pointer passed by reference in C++. Can you provide an example like this:
funz.h : void funz( int *&a );
funz.cpp : ? (1)
main.cpp:
#include "funz.h"
#include <iostream>
[Code]...
as I write in (1) and (2) ?
