I am not sure why I am receiving the error message:
Error C2466: cannot allocate an array of constant size 0
When I run the code:
Code:
int s;
cout<<"Enter the size:
";
cin>>s;
int array[s];
C++ masters,
I am making program that allows the user to determine how big the array size will be and then asks the user to make up numbers to fill the array. Every time run the program on Dev C++ it says "program has stopped working"
Heres My Code:
//Assignment 19 Program 2
#include <iostream>
using namespace std;
int main()
[Code].....
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....
is it possible to use this code ?
#include <iostream>
int main(int argc, const char * argv[]) {
int number = 0;
std::cout << "napis cifro za array
";
std::cin >> number;
[Code]...
It does work on xcode but doesn't in microsoft visual studio 2013. Where is the problem?
How can I stomp the arr size of 50 with the value the user inputs? The function doesn't sum up the even integers from 0 to the value the user inputs. Instead it sums up exactly that many even integers.
Is there a way I can stomp the size of the array with what the user inputs so that the sum calculation never goes past the value the user inputs?
Code:
void sumIntegers () {
int arr[50];
int i = 0;
int num = 0;
int sum = 0;
printf("
I want to sum up even integers <= 50.
[Code] .....
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
View 10 Replies View RelatedSo I'm trying to make a program, Which has nothing to do with the topic. But I ran into a problem.
I need to get a char array size of 6 doing:
char myChar[6];
but the size (6) is undefined until user input.
So I need to do char myChar[var]; (Var being 6 for now).
When I do:
char myChar[6];
It works!!!
But when I do:
int val = 6;
char myChar[val];
It doesn't work.
I'm trying to build an array of a certain size, after receiving user input. The method I'm trying is
int var = 3;
int* ar = new int[var];
When doing tests I did this (and it worked) and red flags popped off in my head.
int var = 3;
int* ar = new int[var];
ar[0] = 0;
ar[1] = 1;
ar[2] = 2;
ar[3] = 3;
ar[4] = 4;
cout << ar[0] << ar[1] << ar[2] << ar[3] << ar[4] << endl;
This method is considered safe, and possibly tell me why I'm not getting stack errors when trying to overload the array?
I am trying to use an array of a size that will be determined by the user, therefore I must use a vector, right?
In class I was told that this is how I call a vector:
vector <int> x;
Is the vector called vector? Is it called x?
Can I do this?
for(int i=0;i<=10;i++)
{
cout<<x[i];
}
Some basic ways of implementing a vector? How it works or how I can do anything with it.
Dynamic memory allocation in array in c programming. I am trying to make the user to choose the size of array they want to engage in the game.
However, i have remove the global variable which contribute the error to my code previously. Now I assigned all the arr individually but not using the global variable. However, i still not get the desired board i want. i still keep getting 9x9 array board.
And i also need limit the board size only from 4 to 9. And how do i do that.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>
#include <malloc.h>
#include <ctype.h>
#include <stdbool.h>
[Code] .....
I'm a little lost with this program. The idea is to dynamically allocate an array and increase its size every time a new integer is inputted by the user. I believe it is a memory leak but as we have just started learning this I'm not sure how to recognise it. Sometimes I can input as many integers as I want other times 2 or 3 before it crashes. When I can input enough values i exit the loop and send it to the sort function and mean calculator function, all works fine there except the last number inputted becomes this huge value not hexadecimal though... As such I'm at a loss as what to look at next, so here you go:
#include <iostream>
using namespace std;
void SelectSort(int [], int);
float MeanCalc(int [], int);
float MedianCalc(int* [], int);
[Code] .....
how to insert a variable for the size of array and prompt user to insert the elements for the array?
View 13 Replies View RelatedHow can i write a program that allows a user to enter a size of pizza and then print the price for that size.
Example: if a user enters size ''s'' then it should display the price stored under ''s''
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
I'm trying to put all of the words in a text document into an array but this text document is 2,138 kb, and when my program is crashing when I try to put it into an string array. Could the file be too big to put into the array?
View 2 Replies View RelatedHere is what I've tried:
int numbers[] = {8, 2, 0, 4, 100, 5};
for(int i = 0; i < sizeof(numbers); i++){
cout << numbers[i] << endl;
}
However the results in the console is: 8 2 0 4 ,What am I doing wrong? Am I using the wrong built in function or something? I googled this and one of the links that came up stated to just do something like
arrayName.size()
but that didnt work for me either...
[URL]
Also, I know that I just enter the size of the list manually, in this case make i < 6 but I still want to know if there is a built in function or something.
I am trying to sort an array of size 10. If I was given:
Code: int List[Size] = {29, 11,12,10,3,26,13,15,19,2};
I need the program to sort all the odd integers and put the even integers to the back of the array. Like so:
Index: 0 1 2 3 4 5 6 7 8 9
Value:29 11 3 13 15 19 12 10 26 2
And it returns the number of even integers in the List. In this case it returns 4. All I am given to start with is
Code:
int evensToRead(int* const List, const int Size){
//body
}
I remember in C++, when a dynamic array is allocated, the size of this array is stored right before the array in memory. Therefore compiler knows exactly how long, when this array is deleted.
Do all compilers store the size this way? Is it a safe method to get the size of a dynamic array?
Here is a example code, it works fine on Visual Studio 2012.
#include <iostream>
using namespace std;
class dummy {
public:
dummy() {
cout<<"dummy created"<<endl;
[Code]...
arrays with dynamic sizes. That being said, I'm working with a simple code which seems to work just fine, my only concern is that once I display the 'char array', not only displays the user's inputs but some extra data, symbols and what not.
why, if to my understanding the first user's input already sets the size of the array
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
char A[]={}; this is the array in c++ of unknown size, now I want to enter some alphabets via loop and want to be the no. of elements i entered the size of the array. .
View 8 Replies View Relatedhow declaring this: { {1, 2}, {1, 2, 3} } Both outer and inner array had known size.
View 19 Replies View Relatedto return the array i shall make a pointer function thats ok.. but how do I get the size return if i dont know the size?
if I need to make AXB=C and output C my new array doesnt have a size..
I am creating a class that has a private array on the heap with a constructor that takes the size of the array and initializes it on the heap. Later I have to make a deconstructor delete the space and print out free after.In my code, I was able to heap a private array and make a deconstructor, but I don't know how to take the size of the array and initialize it on the heap. My guess is this:
int* size = new int();
Also when you initialize size on the heap, don't you also have to delete it too? If so, where, in the code, do you do that? Here is my code so far.
Class Student {
private:
int size;
int* array = new int[size];
public:
Student(); // Constructor
~Student(); // Deconstructor
[code]....
How do you make a constructor that takes the size of the array and initializes it on the heap
Student::~Student()
{
delete[] array;
cout << "Free!" << endl;
}
I have declared an array like:
/***********Creating an m*p array**********************/
B = new int *[m];
for(row=0;row<m;++row)
B[row] = new int[p];
How to find the number of elements in it?
The statement
cout << "number of elements in array B equals " << sizeof(B) << endl;
returns 4 each time the program runs
I'm trying building a new macro for change the array size:
#define redim(varname,x) ((sizeof(varname)*) realloc (varname, x * sizeof(varname)));
int b;
redim(b,3);
error message:
"error: expected primary-expression before ')' token"
what isn't right with these macro?
