I'm trying to put all of the words in a text document into an array but this text document is 2,138 kb, and when my program is crashing when I try to put it into an string array. Could the file be too big to put into the array?
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Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
Here is what I've tried:
int numbers[] = {8, 2, 0, 4, 100, 5};
for(int i = 0; i < sizeof(numbers); i++){
cout << numbers[i] << endl;
}
However the results in the console is: 8 2 0 4 ,What am I doing wrong? Am I using the wrong built in function or something? I googled this and one of the links that came up stated to just do something like
arrayName.size()
but that didnt work for me either...
[URL]
Also, I know that I just enter the size of the list manually, in this case make i < 6 but I still want to know if there is a built in function or something.
I am not sure why I am receiving the error message:
Error C2466: cannot allocate an array of constant size 0
When I run the code:
Code:
int s;
cout<<"Enter the size:
";
cin>>s;
int array[s];
C++ masters,
I am trying to sort an array of size 10. If I was given:
Code: int List[Size] = {29, 11,12,10,3,26,13,15,19,2};
I need the program to sort all the odd integers and put the even integers to the back of the array. Like so:
Index: 0 1 2 3 4 5 6 7 8 9
Value:29 11 3 13 15 19 12 10 26 2
And it returns the number of even integers in the List. In this case it returns 4. All I am given to start with is
Code:
int evensToRead(int* const List, const int Size){
//body
}
I remember in C++, when a dynamic array is allocated, the size of this array is stored right before the array in memory. Therefore compiler knows exactly how long, when this array is deleted.
Do all compilers store the size this way? Is it a safe method to get the size of a dynamic array?
Here is a example code, it works fine on Visual Studio 2012.
#include <iostream>
using namespace std;
class dummy {
public:
dummy() {
cout<<"dummy created"<<endl;
[Code]...
arrays with dynamic sizes. That being said, I'm working with a simple code which seems to work just fine, my only concern is that once I display the 'char array', not only displays the user's inputs but some extra data, symbols and what not.
why, if to my understanding the first user's input already sets the size of the array
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
char A[]={}; this is the array in c++ of unknown size, now I want to enter some alphabets via loop and want to be the no. of elements i entered the size of the array. .
View 8 Replies View Relatedhow declaring this: { {1, 2}, {1, 2, 3} } Both outer and inner array had known size.
View 19 Replies View Relatedto return the array i shall make a pointer function thats ok.. but how do I get the size return if i dont know the size?
if I need to make AXB=C and output C my new array doesnt have a size..
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....
I am creating a class that has a private array on the heap with a constructor that takes the size of the array and initializes it on the heap. Later I have to make a deconstructor delete the space and print out free after.In my code, I was able to heap a private array and make a deconstructor, but I don't know how to take the size of the array and initialize it on the heap. My guess is this:
int* size = new int();
Also when you initialize size on the heap, don't you also have to delete it too? If so, where, in the code, do you do that? Here is my code so far.
Class Student {
private:
int size;
int* array = new int[size];
public:
Student(); // Constructor
~Student(); // Deconstructor
[code]....
How do you make a constructor that takes the size of the array and initializes it on the heap
Student::~Student()
{
delete[] array;
cout << "Free!" << endl;
}
I have declared an array like:
/***********Creating an m*p array**********************/
B = new int *[m];
for(row=0;row<m;++row)
B[row] = new int[p];
How to find the number of elements in it?
The statement
cout << "number of elements in array B equals " << sizeof(B) << endl;
returns 4 each time the program runs
I'm trying building a new macro for change the array size:
#define redim(varname,x) ((sizeof(varname)*) realloc (varname, x * sizeof(varname)));
int b;
redim(b,3);
error message:
"error: expected primary-expression before ')' token"
what isn't right with these macro?
I am developing a program which should multiply two character arrays of length of 40 treating as signed numbers for example:
char arr[4] = {'-', '1','2',' '}; is equivalent to -123 in integer form.
now i have this in 40 size of array and i have two arrays . What will be the algorithm that should i employ? i can't find the way to implement this.
Same goes for Division, +1 what about 40bit numbers division.
is it possible to use this code ?
#include <iostream>
int main(int argc, const char * argv[]) {
int number = 0;
std::cout << "napis cifro za array
";
std::cin >> number;
[Code]...
It does work on xcode but doesn't in microsoft visual studio 2013. Where is the problem?
I am trying to create an array with the size of the first value of one file wich is the same of the first line because the first line only have one value. Here is how i am trying to do it ...
FILE * fich;
int test;
fich=fopen(nome_ficheiro,"r");
fscanf_s(fich,"%d",&test);
int np=test;
No*aux=primeiro;
[Code] .....
I have one array with size of 5 and passing this array to one method. I want to get size of the array inside method. If i get size of array inside method, i'm getting only "1",but not "5".
int v[5];
v[0]=1;
v[1]=2;
v[2]=3;
v[3]=4;
v[4]=5;
cout<<sizeof(v)/sizeof(&v[0])<<endl; // here i'm getting size as 5
CreateArray(v);
void CreateArray(int val[])
{
cout<<sizeof(val)/sizeof(&val[0])<<endl; // here i'm getting size as 1
}
Is there any way to get size inside method ?
I'm making a program that hold a list of strings (commands) in memory, displays it with a GUI and also sends any of these strings to a USB port.
I'm thinking of holding the strings in a vector that is initialized in a class with methods to add or delete strings (commands). Should I store these string in the vector or pointers to string? Or is there a better way?
How do I insert a array size as variable?
View 5 Replies View RelatedI made a function like follows:
void foo(const double va, const int q) {
int qaa[q];
......
return;
}
However, the compiler indicates allocator cannot allocate an array of constant size 0... how can I use the argument "q" to fix the size of array "qaa"?
I need to make a program that will let the user input values and it will only stop accepting once the user has inputted a negative number then it will display its mode and frequency.
The problem is I can't find a way to let the user input values freely without asking first for the no. of values he will enter.
#include<stdio.h>
int main() {
int i,j,k=1,p,a[20],b[20],n,cnt=1,big;
clrscr();
printf("Enter the number of elements:
[Code] .....
I have the following code:
Code:
unsigned int bh = 3;
unsigned int b= 2*bh+ 1;
float s[b];
I get the following 3 compilation errors:
error C2057: expected constant expression
error C2466: cannot allocate an array of constant size 0
error C2133: 's' : unknown size
I am using Visual Studios 2010. What is wrong?
Change the frame window size according to font size increases.
View 3 Replies View RelatedI must take an old MFC project in VC++ 6.0 and make changes.
The problem is text size in screen is different from size in print preview.
for example with this font
Code:
CFont f50;
f50.CreateFont(100,0,0,0,FW_BOLD,0,0,0,DEFAULT_CHARSET,OUT_DEFAULT_PRECIS,
CLIP_DEFAULT_PRECIS,DEFAULT_QUALITY,FF_DONTCARE,"Frutiger LT Std 45 Light");
And this text
Code:
s=_T("Let's try to calculate the size of this text");
and with MM_LOMETRIC map mode
GetTextExtent() returns me:
On screen: (1595,99)
Ink printer + print preview: (1589,100)
PDFCreator + print preview: (1580,100)
comparing with screen size the height is bigger but lenght is smaller. I don't understand.
I can understand that different printers process the fonts in different way and then to have different lenghts. That's not the problem. The problem is I need to simulate in screen the same behaviour i will have on printer because these texts are being aligned in the document, and I don't want to see that the text si aligned different in text than in paper.
What can I do to render the text on screen with the same size I will have on the printer? Print preview is doing it. Should I change the font parameters? is something related with pixels per inch?
