I am trying to create an array with the size of the first value of one file wich is the same of the first line because the first line only have one value. Here is how i am trying to do it ...
FILE * fich;
int test;
fich=fopen(nome_ficheiro,"r");
fscanf_s(fich,"%d",&test);
int np=test;
No*aux=primeiro;
[Code] .....
I am interested in creating a file of a given size and then randomly accessing the file to populate it. Is there a way to quickly create, for instance, a 4 GByte file in C++, initially populated with garbage?
View 4 Replies View RelatedI have to create array with size that returns from method
int val=test();
int arr[val];
int test()
{
// Some logic and getting result as 5
return 5;
}
I would like to create arr with 5. how can i do this.
I'm doing a Text-based RPG game and it will include some checkpoints, on those checkpoints the game will save the progress, so I need to write all my variables to a text file and then read them all when the player loads the game.
Some of my variables, like enemyNames, dont have any determined size, they're like this: "int enemyNames[];"
So how do I write an array to a text file without determining a size?
And how do I read them when the player loads the game?
Goal:
Read contents from a file and use as the size of a 2d array.
Problem:
C2087: Line 27 : "a1" : missing subscript
C2133: Line 27 : "a1" : unknown size
Code :
int rows;
int columns;
ifstream fObject("inputdata.dat");
fObject>>rows;
fObject>>columns;
char a1[rows][columns];
I am not sure why this is occurring, or if there is a better way to do it.
how to create an unordered map of fixed size vectors?
Code:
unordered_map<string, vector<int>> x;
x["mumb 5"][7] = 65; // this does not work since my vector size is not set.
An ImageList_Create() function (see here) takes 2 parameters: cx and cy which are the width and height of each image.
Everything is good if I know in advance what size my images will have. But what if I don't?
Let's say I select 32x32 and my images are sized as 16x16. What will happen with the image list? Or my images are 48x48 and the image list should grow to accomodate the extra space. Since on Windows image list is just one big bitmap, will the height of the image list shrink/grow to 16/48 or not? Is there a way to test such behavior?
The problem I'm having is to check whether the actual images will be truncated when they are bigger that the image list initial size or not or whether I will see some extra space if the images are smaller.
The closest way I see is this function, but I am not sure its the right one to apply to the image list itself and not to the image inside the list.
How to test this properly and reliably on Windows XP+?
Working on an assignment and I've hit TWO stumbling blocks. I now have to take the first line from a .txt file and use that number to determine the size of rows to create in my program. I am using fscanf but the program hangs. How can I read in this number, store it and use it in a for loop?
The second issue is after reading this number I have to print each number in the .txt file under a different column. (Note that it skips a line after reading the row count.) The .txt file is set up as follows:
9 1 3 6 4 7 8 8 6 1
The output should look sort of like:
Number 1 3 6 4 7 8 8 6 1
Here's my attempt:
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <math.h>
typedef struct{
int number;
[Code] .......
So the plan is to create a word search by reading in characters from a file into an array. This is my code so far, nowhere near finished but have encountered a problem already:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define ROWS 20
#define COLUMNS 20
int main()
{
[Code]...
My question is to do with the section highlighted in red... I can't really see why it is not printing out my array (wordsearch), it's probably very basic but I have no C experience so am not too confident in what I'm doing.
This is my code!! but it's not working at all.
#include <iostream>
#include <fstream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main () {
ofstream fout("datain.txt",ios::out);
int array[6][6];
[Code] .....
I have a struct called Array and I'm to create a function to create a dynamic array that's fill with randomly generated integers from 0 to 50 (inclusive) and a function to destroy the array for freeing its memory. Below the code that I have written so far.
Code:
* Struct */
typedef struct {int *pArray; //the dynamic array
int length; //the size of the dynamic array}Array;
/* Function to create a dynamic array */
Array *initializeArray (int length) {int i;
}
[code]....
I need to create a project that create a automated backup of a file.
i will get the file from C:/Folder/file.exe and move for a other created folder, but.. in every time that user make this backup, a folder will be created with year, month and date, like: C/Folder2/2014/April/16:42/file.exe.
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
I'm trying to put all of the words in a text document into an array but this text document is 2,138 kb, and when my program is crashing when I try to put it into an string array. Could the file be too big to put into the array?
View 2 Replies View RelatedHere is what I've tried:
int numbers[] = {8, 2, 0, 4, 100, 5};
for(int i = 0; i < sizeof(numbers); i++){
cout << numbers[i] << endl;
}
However the results in the console is: 8 2 0 4 ,What am I doing wrong? Am I using the wrong built in function or something? I googled this and one of the links that came up stated to just do something like
arrayName.size()
but that didnt work for me either...
[URL]
Also, I know that I just enter the size of the list manually, in this case make i < 6 but I still want to know if there is a built in function or something.
I am not sure why I am receiving the error message:
Error C2466: cannot allocate an array of constant size 0
When I run the code:
Code:
int s;
cout<<"Enter the size:
";
cin>>s;
int array[s];
C++ masters,
I am trying to sort an array of size 10. If I was given:
Code: int List[Size] = {29, 11,12,10,3,26,13,15,19,2};
I need the program to sort all the odd integers and put the even integers to the back of the array. Like so:
Index: 0 1 2 3 4 5 6 7 8 9
Value:29 11 3 13 15 19 12 10 26 2
And it returns the number of even integers in the List. In this case it returns 4. All I am given to start with is
Code:
int evensToRead(int* const List, const int Size){
//body
}
I remember in C++, when a dynamic array is allocated, the size of this array is stored right before the array in memory. Therefore compiler knows exactly how long, when this array is deleted.
Do all compilers store the size this way? Is it a safe method to get the size of a dynamic array?
Here is a example code, it works fine on Visual Studio 2012.
#include <iostream>
using namespace std;
class dummy {
public:
dummy() {
cout<<"dummy created"<<endl;
[Code]...
arrays with dynamic sizes. That being said, I'm working with a simple code which seems to work just fine, my only concern is that once I display the 'char array', not only displays the user's inputs but some extra data, symbols and what not.
why, if to my understanding the first user's input already sets the size of the array
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
char A[]={}; this is the array in c++ of unknown size, now I want to enter some alphabets via loop and want to be the no. of elements i entered the size of the array. .
View 8 Replies View Relatedhow declaring this: { {1, 2}, {1, 2, 3} } Both outer and inner array had known size.
View 19 Replies View RelatedI've been looking into the file structure of BMP images and everything I'm reading says that the 4 bytes following the signature are designated as the filesize of the bmp file... It's always zero for me regardless of the BMP file. The signature is always correct though.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <errno.h>
#include <stdint.h>
[Code]....
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) {
if (cards[0]) {
hideFirstCard=true;
cards[0] = '**';
} for(int a = 0; a <= numCards; a++) {
cout >> showCard(cards[a]);
} }
to return the array i shall make a pointer function thats ok.. but how do I get the size return if i dont know the size?
if I need to make AXB=C and output C my new array doesnt have a size..
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....