C++ :: Determining Size Of Array?
Oct 24, 2013char A[]={}; this is the array in c++ of unknown size, now I want to enter some alphabets via loop and want to be the no. of elements i entered the size of the array. .
View 8 Replieschar A[]={}; this is the array in c++ of unknown size, now I want to enter some alphabets via loop and want to be the no. of elements i entered the size of the array. .
View 8 Repliesi have to read a file with between 5 and 10 pairs of numbers, each on a different line. i can read the file, and wrote something to save the length of the file as a variable, but when i use it i start returning crazy data. the problem is in the do while loop and i want to change the i< in the for loop to "lines" so the code stops when the last digit is read. if i use i<10 the file has extra digits is the file is only 8 or 5 pairs of numbers.
FILE *Fpointout;
FILE *Fpointin = fopen ("test.txt","r"); //read this one
Fpointout = fopen ("out.txt","w"); //write this one
if (Fpointin == NULL) //if no file in source {
printf ("File does not exist."); //tell user it is not there
[Code] .....
determining if a value entered in loop is an odd or even number. Also, the value can't be int because it may be a decimal value(therefore i cant use the if(x%==0).
I need to replace the if(value%2 ==0) else num_even++ statement in my code with something else that will work with float to determine odd vs even.
#include <iostream>
using namespace std;
int main() {
int num_values;
float sum_values = 0;
int num_neg_values = 0;
int num_pos_values = 0;
[code]....
I need function to determine where to place new element in sorted array. I want to use binary search to find index where element should be placed, when push all others.
Prototype should be something like
int WhereToPlaceElement(ElementType hash); // uses private atribute ElType** elements
I have tried my best to write, but all tries ended in inf loops and reading invalid locations of array.
I am trying to extract the numbers from Numbers.txt, and then put them in the correct file, either Odd.txt or Even.txt, depending on what they are. And I have gotten to a point where I am not sure what to do; right now it just reads Numbers.txt and then the program ends.
#include <iostream>
#include <fstream>
#include <string>
[Code].....
I am new at c++ and I am trying to write a code to determine the maximum deflection at the end of a cantilevered beam. I am given the formula : deflection= (4 W L^3)/(E B H^3) where W is the load weight, L is the beams length, E is the modulus of elasticity, B is the beams base, and H is the beams height.
// Included Header Files
#include <iostream>
#include <iomanip>
#include <cmath>
#include <string>
#include <fstream>
#include <cstdlib>
#include <cstdio>
[code]....
I have to make a program to read a file with strings and determine if they are palindromes. The problem is that the program says that they're all palindromes.
int main() {
ifstream inFile;
ofstream outFile;
inFile.open("in.data");
outFile.open("out.data");
if (!inFile || !outFile) //to display error if input files are invalid
[code]....
I am trying to write a function that determine if a file in a directory is of a gif/bmp/png/jpg extension. Right now I think I have correctly written my code all the way up to listing the files in the directory and opening them in binary mode.
Now, I am struggling with figuring out how to determine what extension the image is. Right now i am just focusing on writing my "bool isGif();" function... To determine if a file is a .gif extension using binary, the first 6 bytes of the file will contain either GIF87a or GIF89a.So, to do this I would read the first six bytes of the file using the function below, correct?
fin.read((char *) &a_file, 6)
Then, once I read in the first six bytes how would I conditionally compare it to determine if it is a .gif? Would I just use
if(fin == "GIF87a II GIF89a) {
\do something here
}
Because that doesn't seem to be working...
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
I'm trying to put all of the words in a text document into an array but this text document is 2,138 kb, and when my program is crashing when I try to put it into an string array. Could the file be too big to put into the array?
View 2 Replies View RelatedHere is what I've tried:
int numbers[] = {8, 2, 0, 4, 100, 5};
for(int i = 0; i < sizeof(numbers); i++){
cout << numbers[i] << endl;
}
However the results in the console is: 8 2 0 4 ,What am I doing wrong? Am I using the wrong built in function or something? I googled this and one of the links that came up stated to just do something like
arrayName.size()
but that didnt work for me either...
[URL]
Also, I know that I just enter the size of the list manually, in this case make i < 6 but I still want to know if there is a built in function or something.
I am not sure why I am receiving the error message:
Error C2466: cannot allocate an array of constant size 0
When I run the code:
Code:
int s;
cout<<"Enter the size:
";
cin>>s;
int array[s];
C++ masters,
I am trying to sort an array of size 10. If I was given:
Code: int List[Size] = {29, 11,12,10,3,26,13,15,19,2};
I need the program to sort all the odd integers and put the even integers to the back of the array. Like so:
Index: 0 1 2 3 4 5 6 7 8 9
Value:29 11 3 13 15 19 12 10 26 2
And it returns the number of even integers in the List. In this case it returns 4. All I am given to start with is
Code:
int evensToRead(int* const List, const int Size){
//body
}
I remember in C++, when a dynamic array is allocated, the size of this array is stored right before the array in memory. Therefore compiler knows exactly how long, when this array is deleted.
Do all compilers store the size this way? Is it a safe method to get the size of a dynamic array?
Here is a example code, it works fine on Visual Studio 2012.
#include <iostream>
using namespace std;
class dummy {
public:
dummy() {
cout<<"dummy created"<<endl;
[Code]...
arrays with dynamic sizes. That being said, I'm working with a simple code which seems to work just fine, my only concern is that once I display the 'char array', not only displays the user's inputs but some extra data, symbols and what not.
why, if to my understanding the first user's input already sets the size of the array
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
how declaring this: { {1, 2}, {1, 2, 3} } Both outer and inner array had known size.
View 19 Replies View Relatedto return the array i shall make a pointer function thats ok.. but how do I get the size return if i dont know the size?
if I need to make AXB=C and output C my new array doesnt have a size..
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....
I am creating a class that has a private array on the heap with a constructor that takes the size of the array and initializes it on the heap. Later I have to make a deconstructor delete the space and print out free after.In my code, I was able to heap a private array and make a deconstructor, but I don't know how to take the size of the array and initialize it on the heap. My guess is this:
int* size = new int();
Also when you initialize size on the heap, don't you also have to delete it too? If so, where, in the code, do you do that? Here is my code so far.
Class Student {
private:
int size;
int* array = new int[size];
public:
Student(); // Constructor
~Student(); // Deconstructor
[code]....
How do you make a constructor that takes the size of the array and initializes it on the heap
Student::~Student()
{
delete[] array;
cout << "Free!" << endl;
}
I have declared an array like:
/***********Creating an m*p array**********************/
B = new int *[m];
for(row=0;row<m;++row)
B[row] = new int[p];
How to find the number of elements in it?
The statement
cout << "number of elements in array B equals " << sizeof(B) << endl;
returns 4 each time the program runs
I'm trying building a new macro for change the array size:
#define redim(varname,x) ((sizeof(varname)*) realloc (varname, x * sizeof(varname)));
int b;
redim(b,3);
error message:
"error: expected primary-expression before ')' token"
what isn't right with these macro?
I am developing a program which should multiply two character arrays of length of 40 treating as signed numbers for example:
char arr[4] = {'-', '1','2','