I am developing a program which should multiply two character arrays of length of 40 treating as signed numbers for example:
char arr[4] = {'-', '1','2',' '}; is equivalent to -123 in integer form.
now i have this in 40 size of array and i have two arrays . What will be the algorithm that should i employ? i can't find the way to implement this.
Same goes for Division, +1 what about 40bit numbers division.
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
I have an array of characters. I am trying to find "houston". The only way I can think of to do this is to use a for loop and check each individual character. Is there an easier way to do this?
char string[] = "Fishing tourism miami atlanta dallas houston";
I want to declare a 2D 4*4 array, and fills the array with the multiplication table of an integer x from the user, for example: x*1,x*2,x*3, ....., x*16 and how to pass that array to a function to print the array and to another function that swaps a column with another column chosen by the user.
View 3 Replies View RelatedAssume you want to use a loop to process an array of characters starting from the beginning of the array. You want the loop to stop when you read the null terminator character from the array. Fill in the loop test condition that will make this work correctly.
index = 0;
ch = array[index];
while ( _____________________________)
{
// process the character
index++;
ch = array[index];
}
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I have an array titled: char TypeOfSong[arraySize] where the array size is 15. I am reading data from a file into this array and the characters can be either 'C', 'D', 'E', or 'R'. Each of these characters stands for a word (sting) and when I output the array, I need the strings to show up, not the characters. I have been reading online and in my book but I can only find information on turning one array with the same characters into a string. How would I go about changing this character array with different characters into a sting?
The characters stand for:
C = Country
D = Dance Party
E = Elevator
R = Rock
I am currently having an issue with validating user input for a state abbreviation. I have an array where a list of abbreviations is stored to use as a comparison for whatever the user inputs. I have been able to get the list loaded properly but whenever i go to compare, it always comes back as true even if it isn't. Here is some relevant code:
static char stateTable[STATE_TABLE_SIZE][STATE_SIZE];
int main() {
char buffer[40], *testCustName[40], testState[5], testCode;
buffer[0] = ' ';
int quit = 0;
int p = 0;
[code].....
I am trying to initialize an array of pointers to an array of characters, I can do it in 3 lines but I really want to do it in one line at the same time keeping the #define.
3 lines initialization (can compile)
======================
#define A 1
#define B 2
char row1[] = {A|B, B, A};
char row2[] = {B, A};
char *test[]= {row1, row2};
1 line initialization (failed)
===============================
char *test[] = { {A|B, B, A}, {B, A} }; // <- how do i do this??
I do not want this because it waste ROM space
=============================================
char test[][3] = { {A|B, B, A}, {B, A} };
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
I am trying to write a function compress() that takes in an input of a 2-dimensional array (5x10) of character data, compresses each row of the array by replacing each run of character with a single character and the number of times it occurs, and prints on each line the result of compression in the function. For example, the row with data aabbcdddee may be compressed into a2b2c1d3e2.
Input (5x10 of characters):
aaacccdeee
sssseeeedd
aaaaaaaccc
eeedddasee
ddeeeeeggg
Output:
a3c3d1e3
s4e4d2
a7c3
e3d3a1s1e2
d2e5g3
I could achieve the compression part, but behind the compressed array, it printed out 5 extra lines of alien ASCI code, followed by printing out 5 times of everything .
Code:
void compress(char data[SIZE1][SIZE2])
{
int i,j, k,l ,count;
char data123;
printf("Enter your data (5x10 of characters): ");
for (i=0; i < SIZE1; i++) {
for (j=0; j < SIZE2; j++)
data[i][j] = getchar();
fflush(stdin);
}
[code]....
I have written this program to copy all the characters input from the keyboard into the array till a "?" mark is entered. what is the error i am doing. I am getting a run time error in this case.
Code:
void word_reversal(void) {
char array[100];
int index=0;
printf("Enter the number of characters less than 100
");
do {
scanf("%c",&array[index++]);
}while(array[index] != '?');
}
I have tried to search all about strings,I have the occurrences and have worked out what letter corresponds with which. I have searched that much i can remove the vowels and reverse my string but I dont know how to swap them. This is what i have this far. When it compiles it just prints the decipher is:
If i even find out am i on the right track ive used caps when swapping to try and stop the doubles over writing,...
#include<stdio.h>
#include<string.h>
int main(void){
int i,count=0;
char secretText[] = "lopsy, hssepokd wl okrhsowk:
[code]....
Here's the question: Create a program that accepts an array of characters. And displays the converted array of characters into Upper case if it is given in Lowercase and vice versa. Don't use string, but char.
Example: mychar ="I am A conQUeror."
Code: //My Codes:
#include <iostream>
#include <conio.h>
using namespace std;
int main()
[Code] ....
my question is located as a comment beside the last printf ! ? check the comment near the last printf the comment is ==>here i get a sequence of numbers the question is how can i copy this sequence to an array and the print the array out ?
Code:
#include <stdio.h>
#define N 30
#define n 100
[Code]....
here i get a sequence of numbers the question is how can i copy this sequence to an array and the print the array out ?
Code:
#include <stdio.h>
#include <string.h>
#include <conio.h>
#include <math.h>
void reverseAr(char ar[], int n);
int main() {
int choice;
char *abc= ar[];
[Code]...
My codes keep couldn't get the reverse array of characters.
I am trying to learn how to declare a pointer to an array of characters. And here is the code i have written. But iam getting a warning saying assignment from incompatible pointer type p = s.
Code:
#include <stdio.h>
int main(int argc, char *argv[]) {
char (*p)[10]; // pointer to an array of 10chars
char s[10] = "Hello"
p = s;
printf("%s",p);
return 0;
}
I have initialized a multidimensional array eg char fruit[5][10]...Then I would need to read in 3 words with spaces in between from user and store in fruit[5][10] e.g "pear apple orange"
The thing is that after typing orange, when I press Enter it still prompts me to enter more characters. How can I end the scanning of characters after orange ?
I have the following string array
string[] output= input.toArray();
each index has a set of two characters, for example:
output[0] has 'th', output[1] has 'is'
I want to take t and h and compare them or do anything with them, but it must be in pairs.
I tried foreach but I don't know if there is a way to compare the element with the next element .
I'm trying to put all of the words in a text document into an array but this text document is 2,138 kb, and when my program is crashing when I try to put it into an string array. Could the file be too big to put into the array?
View 2 Replies View RelatedHere is what I've tried:
int numbers[] = {8, 2, 0, 4, 100, 5};
for(int i = 0; i < sizeof(numbers); i++){
cout << numbers[i] << endl;
}
However the results in the console is: 8 2 0 4 ,What am I doing wrong? Am I using the wrong built in function or something? I googled this and one of the links that came up stated to just do something like
arrayName.size()
but that didnt work for me either...
[URL]
Also, I know that I just enter the size of the list manually, in this case make i < 6 but I still want to know if there is a built in function or something.
I have been looking everywhere, but the only place I have seen it done is Objective C. The Question: how do I split a string, input by the user, into an array of characters? No code shown because I know no commands that do this.
--Input by user as in fgets, or scanf().
Eg. User input : abcde
Program Output : edcba
I keep on getting weird ASCI symbol in return, I couldn't achieve what I need, and tried debugging for days,
Code: char ar[20];
int len,n=0;
printf("enter the string to be reversed :
");
[Code].....
My question is how create a function to remove all vowels defined as characters('a' 'e', 'i', 'o', and 'u') from the array provided to it.
An example of how the function should work:
input: Hello world, how are you?
output: Hll wrld, hw r y?
Code:
int removeVowels(char arr[]) {
int i;
//move through each element of the array
for(i = j; arr[i] != '/0'; i++) {
//if the last character was a vowel replace with the current
//character
[Code] .....
Below is an extracted portion of an example exercise from the C Programming Language book:
Code:
void escape(char * s, char * t) {
int i, j;
i = j = 0;
while ( t[i] ) {
switch( t[i] ) {
[Code] ....
Here's my problem with this. s is a pointer to a char array. That means each index stores 1 byte. A backslash character '' is one byte. In above example, we escape it with a second backslash character: ''. That means we have two bytes there. So why does it allow inserting two bytes into a one byte index?
I am trying to store the HTML codes for different characters in an array, but I am not sure how to do this, so that when using the keybd_event it can be plugged in.
If you try to do it with a string for storing the HTML code, you get this error.
string HTML[1];
HTML[0] = "A"; //A
keybd_event(HTML[0], 0, 0, 0);
I could do it in a very long if/else statement, but this would be much easier to call and get data from, and take up less space.
