C :: Removing Vowels Defined As Characters From Array
Dec 5, 2013
My question is how create a function to remove all vowels defined as characters('a' 'e', 'i', 'o', and 'u') from the array provided to it.
An example of how the function should work:
input: Hello world, how are you?
output: Hll wrld, hw r y?
Code:
int removeVowels(char arr[]) {
int i;
//move through each element of the array
for(i = j; arr[i] != '/0'; i++) {
//if the last character was a vowel replace with the current
//character
[Code] .....
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Oct 7, 2013
The output I'm getting here just counts every letter in the sentence and counts them as vowels. I'm trying to make the user defined function return the amount of vowels within the sentence.
#include <iostream>
#include <iomanip>
#include <cmath>
[Code].....
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Nov 1, 2013
I want to remove a particular character from a string. Say '.'. I've tried the following:
void removeDots(std::string &x)
{
std::remove_if(x.begin(),x.end(),[](char c){return (c == '.');});
}
This has the effect of removing the dots but keeping the length of the string the same, so old characters are left over at the end. Is there an extra action to do to x to make it the right size or is there a better way of doing it?
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Jul 14, 2014
In this assignment, you must enter a file and get out of it this:
Summary
Total characters: 8282
Vowels: 2418
Consonants: 3970
Letters: 6388
Digits: 174
Left parentheses: 17
Right parentheses: 17
Single quotes: 17
Double quotes: 14
Other: 1655
Here is my code:
#include <iostream>
#include <fstream>
#include <cctype>
using namespace std;
char ch;
bool isVowel (char);
[Code] .....
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Apr 3, 2014
I currently have a .csv file that should only contain numerical values however there are errors in some columns that mean there is text included. I am wondering what the best way of going about removing these characters would be.
I am looking at using : str.erase(std::remove(str.begin(), str.end(), 'xxxxxxx'), str.end());
For this I will need to read my data into a string and then remove the alphabet from that string. I am currently doing this like so (I use the '?' as a delimiter because I know there are none in my file).
#include <iostream>
#include <fstream>
#include <algorithm>
using namespace std;
string Weather_test;
char chars[] =
[Code] ....
The problem with this is I don't know what to do around the chars[!eof] part.
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Jan 9, 2013
//Sorting Vowels, Consonants, Digits and Other Characters in a String in C++
#include <iostream>
#include <string>
using namespace std;
int main() {
int vow,con,d,s;
vow=con=d=s=0;
[Code] ....
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Oct 28, 2014
So I have been assigned a program that counts keystrokes, alphabetical characters, and vowels. I have the program working as desired but I just can't figure out how to make it end upon ONLY the "return" key being pressed.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main ( void ) {
[Code] .....
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Nov 4, 2013
While removing duplicate elements from an array, if more than 4 array elements are same then removal does not work. however my logic seems to be alright. i reckon there is a problem with the conditions and assignments in the three for loops that i have used. the program is as follows:
Code:
/*c program to remove duplicate elements in an array*/
#include<stdio.h>
int main(void)
{
int array[30],i,j,k,n;
printf("
[Code] ....
Take for instance if the input elements are 1,1,1,1,1,2,2,3,5 then after removal of duplicacy the array is 1,1,2,3,5.
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Mar 20, 2014
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
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Mar 26, 2014
I have an array of characters. I am trying to find "houston". The only way I can think of to do this is to use a for loop and check each individual character. Is there an easier way to do this?
char string[] = "Fishing tourism miami atlanta dallas houston";
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Jul 23, 2014
The instructions call for the user to define the size of the array and all I have ever done is use a predefined size for the array and then let the user fill it. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void Display (void);
void random (int *, int);
void Ascending (int *, int);
void Descending (int *, int);
[code]....
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Apr 6, 2014
I got an array class, but I'm getting this error:
Error1error C2953: 'Array2D' : class template has already been defined
Here's the code:
#include "Tools.h"
template <typename T>
class Array2D {
T** arr;
int xSize;
int ySize;
[Code] .....
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Apr 17, 2014
STRING s1 = “FOOBAR”
Here STRING is a user defined class. how to assign a constant char array "FOOBAR" to string object? Copy constructor need to be same class type as parameter. and overloading assignment operator also need to be same class type. I think 'friend' can let pass another type of object rather than STRING to do operation on overloaded '=' operator. How could it be done if it is possible at all?
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Apr 24, 2012
We had to write a "selling program for computers, laptops and tablets", which I did but for the extra credit, we have to have those three points in the application and I have tried but how to do the "extra credit" part, which I really need.
1.) A loop to prompt the user if they would like to place another order
2.) At least one user-defined function
3.) An enumerated data type, array or struct (structure)
I did one of these three, it's a "DO WHILE" loop asking users if they want to make another order, it's right at the beginning of the code.
Code:
#include <iostream>
#include <string>
#include <iomanip>
#include <fstream>
using namespace std;
double desktop();//function prototype
double laptop();
double tablet();
[Code] ....
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Jul 24, 2013
im tasked with creating a linear search script using functions on a 10 element array. the elements are to be supplied by the user as is the search target.
I understand how to create the array and gather that information from the user as well as howto set a variable for "target", this is what im calling it. Those two parts are simple enough.
I am not fully understanding the calling of an array in a function as a pointer. i semi understand the use of a pointer and howto call a normal pointer in a function. i also understand that an array is nothing more then a "special" pointer with a set of consecutive address blocks for the size of the array.
My first user defined function is simple enough
Code:
ReadArray(int A[], int size){
int i;
printf("Please enter %d integer numbers separated by spaces:
", size);
for (i = 0; i < size; i++)
scanf("%d", &A[i]);
}
Sso nothing out of the ordinary there. that should be a standard for loop and use of scanf, sadly prof has not covered ssanf or any of the other options so i am stuck using scanf for now. maybe someday down the line in a other program or after this course ill get the chance to learn about better options for gathering data from the user.
I am confused as to my next function:
Code:
void SearchArray(int A[], int target, int size);
I've not written any code here yet as im not sure if i should call the A[], or *A for the first type of the function?
If i call *A do i then use something like this for my search:
Code:
for (*A = 0; *A < size; *A++)
if (*A < target) or use A[] insteadA?
Code:
for (i = 0; i < size; i++)
if (A[i] = target)
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Jan 28, 2015
How do I convert just the number from position 4 to 15 from this char array and convert to int and save to variable
char numbers[]="54155444546546545643246543241465432165456";
the real char got 1000 digits this is just example how do i convert chars from numbers[4] to numbers[15] and save them as one number ? in this case i will get int x = 5444546546545643 as u can see char numbers as a example above
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May 3, 2014
Assume you want to use a loop to process an array of characters starting from the beginning of the array. You want the loop to stop when you read the null terminator character from the array. Fill in the loop test condition that will make this work correctly.
index = 0;
ch = array[index];
while ( _____________________________)
{
// process the character
index++;
ch = array[index];
}
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Jan 18, 2015
I'm completely new to pointers and have a homework assignment due where I'm supposed to create a user defined dynamic array for player scores. The only errors I'm experiencing is a C2109: subscript requires pointer type and only on the lines that use the int *score; variable (57, 62, 64, 69, 71, and 82). I've already tried adding = nullptr to the variable and that didn't work.
#include<iostream>
#include<string>
#include<iomanip>
using namespace std;
void players(string[], int[], int);
void average(int[], int);
[Code] ....
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Apr 7, 2013
I have an array titled: char TypeOfSong[arraySize] where the array size is 15. I am reading data from a file into this array and the characters can be either 'C', 'D', 'E', or 'R'. Each of these characters stands for a word (sting) and when I output the array, I need the strings to show up, not the characters. I have been reading online and in my book but I can only find information on turning one array with the same characters into a string. How would I go about changing this character array with different characters into a sting?
The characters stand for:
C = Country
D = Dance Party
E = Elevator
R = Rock
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Apr 16, 2014
I am currently having an issue with validating user input for a state abbreviation. I have an array where a list of abbreviations is stored to use as a comparison for whatever the user inputs. I have been able to get the list loaded properly but whenever i go to compare, it always comes back as true even if it isn't. Here is some relevant code:
static char stateTable[STATE_TABLE_SIZE][STATE_SIZE];
int main() {
char buffer[40], *testCustName[40], testState[5], testCode;
buffer[0] = '