I want to remove a particular character from a string. Say '.'. I've tried the following:
void removeDots(std::string &x)
{
std::remove_if(x.begin(),x.end(),[](char c){return (c == '.');});
}
This has the effect of removing the dots but keeping the length of the string the same, so old characters are left over at the end. Is there an extra action to do to x to make it the right size or is there a better way of doing it?
I currently have a .csv file that should only contain numerical values however there are errors in some columns that mean there is text included. I am wondering what the best way of going about removing these characters would be.
I am looking at using : str.erase(std::remove(str.begin(), str.end(), 'xxxxxxx'), str.end());
For this I will need to read my data into a string and then remove the alphabet from that string. I am currently doing this like so (I use the '?' as a delimiter because I know there are none in my file).
#include <iostream>
#include <fstream>
#include <algorithm>
using namespace std;
string Weather_test;
char chars[] =
[Code] ....
The problem with this is I don't know what to do around the chars[!eof] part.
My question is how create a function to remove all vowels defined as characters('a' 'e', 'i', 'o', and 'u') from the array provided to it.
An example of how the function should work:
input: Hello world, how are you?
output: Hll wrld, hw r y?
Code:
int removeVowels(char arr[]) {
int i;
//move through each element of the array
for(i = j; arr[i] != '/0'; i++) {
//if the last character was a vowel replace with the current
//character
[Code] .....
I'm working on a problem in which I've to design a program in which the punctuations should be removed from the string. For eg., if input str is: "Hello!!"; the output must be: "Hello".
I'm not sure how to remove a sub-string (if that's the right word!!) from a string. So, I designed a program which print out the punctuations. For eg., if input str is: "Hey!!"; the output would be: ! !
Here it is:
#include <iostream>
#include <string>
using namespace std;
int main (){
cout << "Enter a string" << endl;
[Code] ....
So, I want to know what should be added to this program so that the punctuations can be removed; or should I rewrite another program for that?
I have many random strings that look something like this:
" 55.343 Char 1.3825 asdf 0.1853 500 1.1359 4.0000 1 100 4.5043"
Notices how there are ints and chars and doubles in the string.
How do I remove all non-doubles for a string like this? The chars and ints may be anywhere within the string.
I'm trying to go search through my linked list for a passed string and if it matches, remove it...but obviously link everything back together properly. This is what I have so far but when i pass it to my display function, which is properly working, it goes into an endless loop
Code:
void llRemoveString(LinkedList** ll, char* string) {
LinkedList* newNode = (LinkedList*)malloc(sizeof(LinkedList));
newNode->value = string;
LinkedList* n = *ll;
[Code] ....
In formatting strings, how would I only get the decimals?
So, 1.456 would be .456(no digit before the decimal). I have seen a lot on removing the decimals or rounding to a certain place.
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char str1[20], str2[20],remp = ' ';
int size1,i,j,temp;
printf ("Input the first string");
[Code]...
I am stuck in this program, Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...). For every char of the given alphabet, count how many times in the string
1-- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
[Code]...
2-what is the longest substring of characters strictly rising interm of ASCII code(the following is greater (>) of the previous)
3- what is the longest substring of successive characters interm of given string rannge (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
i have a string which is n characters long. i need to read say 20 characters at a time, wait for the user to type OK and then send another 20 characters. wait for the user to type OK and send 20 characters again until we get to the nth character.
View 3 Replies View RelatedI have a string like str="ABCDEFGHIJK";
need o/p like this str="CBAFEDIHGJK"
am getting "CBA" correctly after that its not printing anything.
int main()
{
string str="ABCDEFGHIJK";
char str1[10],rev[10];
int n=str.length(),count=0,c=3,k=0,j=0;
[Code].....
I'm working on a programming challenge and i need to uppercase all characters of the string.
string upperCaseIt(string& name){
for(int index = 0; index < name.length(); index++){
name[index] = toupper(name[index]);
return name;
}
}
My problem is that it only uppercase the first character of the string.
Iam working with arrays and i cant get to the write solution to cout the characters.
the Question is : Write a program that inputs a character string from the user as an input (using cin.get())and store it in myStr[ ] array.Assume that the length of the input string is less than 100 characters and the string may contain lower case, upper case, and/or symbols.The program should then print the number of lower case, upper case, digits, and symbols along with the characters themselves.
my code :
#include <iostream>
#include <string>
#include<iomanip>
using namespace std;
int main() {
int ctr1=0, ctr2=0, i=0, ctr3=0;
[Code] ...
What i have now, how can i cout the uppercase characters and the lower case characters and the symbol characters !
I am trying to cout just the first 5 characters the user enters into a string. I'm not sure how I can discard or not show the rest of the characters they try to enter after 5.
#include <iostream>
#include <string>
using namespace std;
int main() {
string random;
cout << "Enter any word." << endl;
cin >> random;
cout << random; //want to ignore everything after first 5 characters entered.
return 0;
}
x="A4478596895";
Delete last four characters.
1. The debugger shows that the characters are entered into the word pointer, and when a punctuation or space character is encountered, I terminate the string with a ''. But when I use puts to print the string, garbage is printed. Why is this?
2. Also, if I don't allocate memory for word the compiler gives a warning about it being used uninitialised. But I didn't allocate memory for the array of pointers(words), and the compiler didn't give any warnings. Whats the difference between a pointer and an array of pointers?
Code:
// wordcount.c - count words.
#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
[Code]....
So I'm writing a function isPalindrome() that can accept a string as an argument, and copy from it only the alphabetic characters in the argument (original) string to another string named alpha_array which contains only the alphabetic characters. Then the function should be able to call the isPurePalindrome function to determine if alpha_array is an ordinary palindrome.
The problem is that when I call isPalindrome in main, the program crashes.
Here's the code I have for isPurePalindrome and isPalindrome:
Code:
/* 1 */
int isPurePalindrome( const char * sentence ) // Can accept strings, array and pointer arguments
{
// Declarations
[Code].....
I can not cope with the task.Create a function that will take a string of characters (including spaces) and print the numbers of characters (including commas, periods, etc.) in it. The output will be arranged alphabetically. Distinguish case sensitive!
View 6 Replies View Relatedis there any function to print a string with all the escape characters in it?
For example, instead of printing:
This is a string.
It would print:
This is a string.
Or in Windows:
This is a string.
I know that you can debug the code to find the variable contents, but is there any way to accomplish this with some standard library function?
#include<fstream>
#include<Windows.h>
#include<cstdlib>
#include<iostream>
#include<string>
#include<iomanip>
#include<sstream>
using namespace std;
void add_matrix(int row1,int row2,int col1,int col2,double m1[30][30],double m2[30][30],double m3[30][30]);
[Code] .....
This program is suppose to read a matrix file , and the first getline is suppose to get the file header but it appears that 'line' doesn't take in any value other than empty thus causing all the problem , I tried to put cin.getline() in front of it to take away the /n created by the cin before it , but it doesn't work . When I debug the program when the arrow points to the string line , this error appears
line<Error reading characters of string.>std::basic_string<char,std::char_traits<char>,std::allocator<char> >
I tried to initialize string line=NULL too , doesn't work either.
may i know how do i read a string 2 characters at a time?
lets say i have a for loop like this
for(int i=0;i<stringLen;i++)
{
for(int j=0;j<???;j++)
{
//insert code
}
}
what i want to do is i want to read a string 2 characters at a time and store them into a vector.
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words
#include<iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number between 0 and 9999: ";
[Code] ....
I have the following string array
string[] output= input.toArray();
each index has a set of two characters, for example:
output[0] has 'th', output[1] has 'is'
I want to take t and h and compare them or do anything with them, but it must be in pairs.
I tried foreach but I don't know if there is a way to compare the element with the next element .
The print statement below I commented prints out unusual characters. I have two strings from the command line that I pass to the TKCreate function. Inside the function the strings print out fine, but when I return a pointer to the struct back to the main method one of the strings prints out fine, but the other one prints out unusual inconsistent characters.
#include <stdio.h>
#include <stddef.h>
#include <stdlib.h>
#include <string.h>
[Code]....
bool isUnique(string _str)
{
bool char_set[256];
int len = _str.length();
memset(char_set, '/0', 256);
for(int i = 0; i < len; ++i)
[Code] .....
I came across this code to find if string has unique characters...i didnt understand why they subracted ascii value of character '0' in the statement int val = _str[i]- '0' and what is happening with the statements...
if(char_set[val])
{
return false;
}
char_set[val] = true;
I take each character in the sting and traverse the whole string .and if count is 2 i use break and conclude that its not unique and not otherwise...can i use this method or this is not efficient????