is there any function to print a string with all the escape characters in it?
For example, instead of printing:
This is a string.
It would print:
This is a string.
Or in Windows:
This is a string.
I know that you can debug the code to find the variable contents, but is there any way to accomplish this with some standard library function?
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char str1[20], str2[20],remp = ' ';
int size1,i,j,temp;
printf ("Input the first string");
[Code]...
I cant print the characters in the end.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
FILE *arquivo1,*arquivo2,*arquivo3;//files i will open//
char texto;//texto= character i will read.
[Code]...
This program is supposed to compare 2 strings and print out a 1 if the characters match and a 0 if they dont. It compiles but doesnt give me the correct output.
Code:
#include <stdio.h>
#include <string.h>
void func();
int main () {
func();
return 0;
[Code] ....
#include<iostream>
#include<conio.h>
using namespace std;
int main(void){
clrscr();
[Code] ....
I am trying to print ascii characters but problem is If i put a limit in for loop to 255 or more than 126 the output don't stop it keeps on going
I know there is another way to this program but what i want to know this why this happen in this logic....it doesn't happen if a<=125 or less then 125.
I'm new to C and was wondering if it was possible to print multiple characters to the same file using the fprintf function provided in one of the C standard libraries?
View 1 Replies View RelatedQ1. Recursive function that receives an integer x and prints the alternating alphabetic characters.
Write a main function to test the function;
ENTER NUMBER : 4
A C E G
Q2. Define a void function that finds the smallest value in the array and number of its occurrences. Also, it finds the largest value in the array and number of its occurrences.
ENTER 4 NUMBERS:
1 12 5 41 41
THE BIGGEST IS 41 AND IT OCCURS 2 TIME
THE SMALLEST IS 1 AND IT OCCURS 1 TIME
I'm doing some file input/output work here in C and received this warning during compilation (GCC). My research indicates that this error is in response to white space or a character cancellation function or something like that. I'm not 100% sure exactly what it means. My code works fine, but the following warning does appear.
Code:
warning: unknown escape sequence: '40'
Here's my code (excluding a bunch of comments at the bottom of the file).
Code:
#include <stdio.h>
int main(void){
FILE *file;
file = fopen("Running Practice.c", "a");
fprintf(file, "Testing...
");
fclose(file);
}
I believe the error I received has to do with either the ' ' I used when appending text to my file, or something to do with there being a space in the file name itself.
I'm trying to get the current position of the cursor in the terminal window. I know that the ansi escape sequence " 33[6n" will display the current x and y location of the cursor. But what I can't figure out is how to store the x and y locations into their respective integer variables.
This is what I've done so far:
Code:
#include <stdio.h>
int main(void) {
int line, column;
char cursor_curr_pos[9];
char escape_sequence[] = " 33[6n"; //outputs x and y location of cursor e.g. ^[[18;1R
snprintf(cursor_curr_pos, 9, "%s", escape_sequence); //save output to string
sscanf(cursor_curr_pos, "^[[%d;%dR", &line, &column); //only read numbers from string
}
I want to send control codes for Epson printer with c# application, I wrote some code, I have the connection with the printer, but when I am sending codes it not responding. On the other side, I found Java application for sending control codes, from that app some of the codes is working but not all of them. For example I want to use ESC EM 66 control code but when I am sending this code, printer not responding or just print the code in numbers.
The code who I use is:
class Program {
public const short FILE_ATTRIBUTE_NORMAL = 0x80;
public const short INVALID_HANDLE_VALUE = -1;
[Code]....
When I am using the method GetDocument() printer is not responding, but it prints only text when I call the buffer variable:
lpt.Write(buffer, 0, buffer.Length);
I am stuck in this program, Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...). For every char of the given alphabet, count how many times in the string
1-- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
[Code]...
2-what is the longest substring of characters strictly rising interm of ASCII code(the following is greater (>) of the previous)
3- what is the longest substring of successive characters interm of given string rannge (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
In this code, i declared a string constant and trying to print the length of string. I know that if i write char a1[7] or char a1[] than it runs and give aggregate output, but in this case it is giving double length of string.
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
}
[code]....
i have a string which is n characters long. i need to read say 20 characters at a time, wait for the user to type OK and then send another 20 characters. wait for the user to type OK and send 20 characters again until we get to the nth character.
View 3 Replies View RelatedI want to remove a particular character from a string. Say '.'. I've tried the following:
void removeDots(std::string &x)
{
std::remove_if(x.begin(),x.end(),[](char c){return (c == '.');});
}
This has the effect of removing the dots but keeping the length of the string the same, so old characters are left over at the end. Is there an extra action to do to x to make it the right size or is there a better way of doing it?
I have a string like str="ABCDEFGHIJK";
need o/p like this str="CBAFEDIHGJK"
am getting "CBA" correctly after that its not printing anything.
int main()
{
string str="ABCDEFGHIJK";
char str1[10],rev[10];
int n=str.length(),count=0,c=3,k=0,j=0;
[Code].....
I'm working on a programming challenge and i need to uppercase all characters of the string.
string upperCaseIt(string& name){
for(int index = 0; index < name.length(); index++){
name[index] = toupper(name[index]);
return name;
}
}
My problem is that it only uppercase the first character of the string.
Iam working with arrays and i cant get to the write solution to cout the characters.
the Question is : Write a program that inputs a character string from the user as an input (using cin.get())and store it in myStr[ ] array.Assume that the length of the input string is less than 100 characters and the string may contain lower case, upper case, and/or symbols.The program should then print the number of lower case, upper case, digits, and symbols along with the characters themselves.
my code :
#include <iostream>
#include <string>
#include<iomanip>
using namespace std;
int main() {
int ctr1=0, ctr2=0, i=0, ctr3=0;
[Code] ...
What i have now, how can i cout the uppercase characters and the lower case characters and the symbol characters !
I am trying to cout just the first 5 characters the user enters into a string. I'm not sure how I can discard or not show the rest of the characters they try to enter after 5.
#include <iostream>
#include <string>
using namespace std;
int main() {
string random;
cout << "Enter any word." << endl;
cin >> random;
cout << random; //want to ignore everything after first 5 characters entered.
return 0;
}
x="A4478596895";
Delete last four characters.
1. The debugger shows that the characters are entered into the word pointer, and when a punctuation or space character is encountered, I terminate the string with a ''. But when I use puts to print the string, garbage is printed. Why is this?
2. Also, if I don't allocate memory for word the compiler gives a warning about it being used uninitialised. But I didn't allocate memory for the array of pointers(words), and the compiler didn't give any warnings. Whats the difference between a pointer and an array of pointers?
Code:
// wordcount.c - count words.
#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
[Code]....
So I'm writing a function isPalindrome() that can accept a string as an argument, and copy from it only the alphabetic characters in the argument (original) string to another string named alpha_array which contains only the alphabetic characters. Then the function should be able to call the isPurePalindrome function to determine if alpha_array is an ordinary palindrome.
The problem is that when I call isPalindrome in main, the program crashes.
Here's the code I have for isPurePalindrome and isPalindrome:
Code:
/* 1 */
int isPurePalindrome( const char * sentence ) // Can accept strings, array and pointer arguments
{
// Declarations
[Code].....
I can not cope with the task.Create a function that will take a string of characters (including spaces) and print the numbers of characters (including commas, periods, etc.) in it. The output will be arranged alphabetically. Distinguish case sensitive!
View 6 Replies View Related#include<fstream>
#include<Windows.h>
#include<cstdlib>
#include<iostream>
#include<string>
#include<iomanip>
#include<sstream>
using namespace std;
void add_matrix(int row1,int row2,int col1,int col2,double m1[30][30],double m2[30][30],double m3[30][30]);
[Code] .....
This program is suppose to read a matrix file , and the first getline is suppose to get the file header but it appears that 'line' doesn't take in any value other than empty thus causing all the problem , I tried to put cin.getline() in front of it to take away the /n created by the cin before it , but it doesn't work . When I debug the program when the arrow points to the string line , this error appears
line<Error reading characters of string.>std::basic_string<char,std::char_traits<char>,std::allocator<char> >
I tried to initialize string line=NULL too , doesn't work either.
may i know how do i read a string 2 characters at a time?
lets say i have a for loop like this
for(int i=0;i<stringLen;i++)
{
for(int j=0;j<???;j++)
{
//insert code
}
}
what i want to do is i want to read a string 2 characters at a time and store them into a vector.
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words
#include<iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number between 0 and 9999: ";
[Code] ....
