#include<iostream>
#include<conio.h>
using namespace std;
int main(void){
clrscr();
[Code] ....
I am trying to print ascii characters but problem is If i put a limit in for loop to 255 or more than 126 the output don't stop it keeps on going
I know there is another way to this program but what i want to know this why this happen in this logic....it doesn't happen if a<=125 or less then 125.
I am looking for a way to sort a string just by the alpha characters, not by the ASCII table. Therefore
string sort(string name) {
sort(name.begin(), name.end());
return name;
}
will not work. And I am looking for the most simple way to go about it!
I'm trying to write a lot of sample code to practice but I can not figure out how to take a string and sort each character in order of their increasing ASCII codes. I'm getting stuck trying to separate each letter to determine it's ASCII code. I know I have to use an array somehow, So far, this is my code:
#include <stdio.h>
#include <stdlib.h>
#define _CRT_SECURE_NO_WARNINGS
[Code].....
What's actually wrong with the program....I'm trying to print the primes in limit of L1 and L2 ;L1<L2.... */
Code:
#include<stdio.h>
#include<math.h>
void main(){
int L1,L2,n=0
printf("Enter Limits by a space:
}
[code]....
What shall I learn in order to send values from 0.00 to 5.00? I'm working with they Hitachi 16x2 LCD display.I've been sending/displaying literal values on it all day.
Code:
SendCharater(unsigned char val)
where the variable val corresponds to the LCD character table.I can also send Hello World to the display, like so:
Code:
void putsXLCD(unsigned char *buffer){
while(*buffer) // Write data to LCD up to null
{
while( BusyXLCD() ); // Wait while LCD is busy
SendCharacter(*buffer); // Write character to LCD
buffer++; // Increment buffer
}
return;
}
I could type in putsXLCD("5.00") in order to display it on the LCD, but how do I implement this automatically for values, e.g. 0.00 to 5.00?It appears I can only pass literal values through the function SendCharacter, meaning that in order to display "0" I have to pass the value 0x30 (the hex value of "0" on the LCD Table).
My current thought process:Much like passing "Hello World" in the function putsXLCD(), I need to assign a pointer that points at each value in the "array" that I need to send. E.g., I need to send 3.24, so I need to point to "3", fetch the corresponding hex value in the LCD table, in this case 0x34, and the pass this 0x34 into the SendCharacter function, and so on. So, if this is the case, how can I fetch the corresponding hex value?
I'm writing a program that reads and counts all the printable characters (ASCII 32-126)found in a text file.
For example if the text file read: Why so serious?
The output to the screen would display(in order of ascii value however):
Character-----Total
W--------------1
h--------------1
y--------------1
s--------------3
o--------------2
etc...
However, I don't think it's reading any of the characters.
#include <iostream>
#include <iomanip>
#include <fstream>
#include <cmath>
#include <string>
using namespace std;
int main() {
int i, count[127];
[Code] .....
Write a program that reads alphanumeric characters from the keyboard, and computes the average ascii value of the alpha numeric characters, the average alphabetical character, the average numeric character and the average uppercase character. Outputting each, you program should terminate reading once it read a non-alphanumeric character.
Here's what i have so far.
Code:
#include <stdio.h>
#include <ctype.h>
int main(void) {
int value = 'a';
int digit_loop = 0;
int alpha_loop = 0;
int upper_loop = 0;
[Code] ....
The code is supposed to convert characters from an array into their respective ascii integers, and append a 0 if the number is less than 3 digits long. It then supposed to put it all together into one string.
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
char file[] = "This is a test";
char *ptr = file;
int length = strlen(file);
int i, numbers[length];
[Code] .....
I need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
is there a function or something that take HEX and print it's corresponding ASCII Character ..
Here is my Code to take Character Array [4] and Print it's HEX to File ..
but i don't know how to reverse ! ?
#include <iostream>
#include <fstream>
#include <cstring>
using namespace std;
int main(){
char buffer[4];
[Code] .....
I cant print the characters in the end.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
FILE *arquivo1,*arquivo2,*arquivo3;//files i will open//
char texto;//texto= character i will read.
[Code]...
is there any function to print a string with all the escape characters in it?
For example, instead of printing:
This is a string.
It would print:
This is a string.
Or in Windows:
This is a string.
I know that you can debug the code to find the variable contents, but is there any way to accomplish this with some standard library function?
This program is supposed to compare 2 strings and print out a 1 if the characters match and a 0 if they dont. It compiles but doesnt give me the correct output.
Code:
#include <stdio.h>
#include <string.h>
void func();
int main () {
func();
return 0;
[Code] ....
I'm new to C and was wondering if it was possible to print multiple characters to the same file using the fprintf function provided in one of the C standard libraries?
View 1 Replies View RelatedQ1. Recursive function that receives an integer x and prints the alternating alphabetic characters.
Write a main function to test the function;
ENTER NUMBER : 4
A C E G
Q2. Define a void function that finds the smallest value in the array and number of its occurrences. Also, it finds the largest value in the array and number of its occurrences.
ENTER 4 NUMBERS:
1 12 5 41 41
THE BIGGEST IS 41 AND IT OCCURS 2 TIME
THE SMALLEST IS 1 AND IT OCCURS 1 TIME
I'm trying to put an if-else statement in a do-while loop and when I put the correct answer in the if statement I get that error. Here's the program:
#include <iostream>
using namespace std;
int main() {
int answer;
char repeat;
[Code] .....
I have to make a function that i'll later be able to use for a ceasar cypher. The letters should shift a user inputted number. This is what I have so far:
char shiftChar(char c, int s) {
char ch = c;
int shift = s;
int newC;
newC = int(ch) + shift;
return newC;
}
The problem with this, is that it doesn't loop back to the start of the alphabet once i get past z.
So I have been assigned a program that counts keystrokes, alphabetical characters, and vowels. I have the program working as desired but I just can't figure out how to make it end upon ONLY the "return" key being pressed.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main ( void ) {
[Code] .....
I am making a program that takes the user's family names, their ages, and where they live. At the end I will be eventually averaging out their age and also printing the names of anyone who lives in Kansas.
I can't seem to get the Kansas part to work properly though.. When I execute the code, everything else works perfectly, but the Kansas part doesn't even print. Is there something different I need to do when strings are involved rather than integers/floats?
Code:
#include <stdio.h>
int main ()
{
/* variable definition: */
[Code].....
I am making a program that takes the user's family names, their ages, and where they live. At the end I will be eventually averaging out their age and also printing the names of anyone who lives in Kansas.
I can't seem to get the Kansas part to work properly though.. When I execute the code, everything else works perfectly, but the Kansas part doesn't even print. Is there something different I need to do when strings are involved rather than integers/floats?
#include <stdio.h>
int main () {
/* variable definition: */
[Code].....
I would like the following code to print: "Why doesn't this print?" and "I would like to print the sum of nc: 5". What am I doing wrong.
#include <stdio.h>
//Use to test ideas and formats//
main() {
int c, nc;
nc = 0;
[code]....
My result as compiled by gcc -o testing testing.c
This prints.
test
t1,e2,s3,t4,
5,
I have not figured out how to sum and print as the above code indicates, which complicates my ability to do many of the exercises in "The C Programming Language". I am using a MacBook gcc compiler and X code as well. I cannot get the last two printf functions to work. I did the temperature example with "while (fahr <= upper)" and the printf printed.
I'm attempting to print a series of text from this loop, but for some reason all I am getting is the sum total and the number 1, like this
1 5175.11
When I want to get it for each iteration of the loop. I've cycled over this and compared it to my other loops I've used and I'm lost as to why this isn't working. I also tried using a do while but that didn't work as well.
for (double total1 = 0; total1 < goal; total1 + save_amt) {
total2 = ((factor - one) * save_amt);
total3 = (total2 / fr_interest);
total1 = total1 + total3;
months_dis = (months_dis + one);
cout << months_dis << " " << total1 << endl;
}
Q.print triangle pattern using one loop and recursion
eg: 5
Code:
#include <stdio.h>#include <conio.h>
void pattern(int n,int N) {
int i,c=1;
[Code]....
10101
01010
10101
01010
I want print above series using for loop.
Write a count controlled loop than can print "i" char. The user is supposed to input a integer and that integer is how many asterisks there is on the blade, in this case it is 5.
* *
** ** **---------------
*******
** ** **
* ** * -10 Rows high
** -blade always connects on second row of handle
**
**
**
**------------------
These are the steps he told us to do it in.
1) *
**
***
****
*****
2) *
**
***
****
*****
****
***
**
*
3) * *
** **
*** ***
**** ****
**********
4) * *
** **
*** ***
**** ****
**********
**** ****
*** ***
** **
* *
5)* *
** ** **
*******
** ** **
* ** *
**
**
**
**
**