C/C++ :: Why Does Printf Not Print After A While Or For Loop
Jul 1, 2012
I would like the following code to print: "Why doesn't this print?" and "I would like to print the sum of nc: 5". What am I doing wrong.
#include <stdio.h>
//Use to test ideas and formats//
main() {
int c, nc;
nc = 0;
[code]....
My result as compiled by gcc -o testing testing.c
This prints.
test
t1,e2,s3,t4,
5,
I have not figured out how to sum and print as the above code indicates, which complicates my ability to do many of the exercises in "The C Programming Language". I am using a MacBook gcc compiler and X code as well. I cannot get the last two printf functions to work. I did the temperature example with "while (fahr <= upper)" and the printf printed.
Numbers are 3d6 Rolling die no.1... RolledDie: 4 DieTotal: 4 Rolling die no.2... RolledDie: 5 DieTotal: 9 Rolling die no.3... RolledDie: 5 DieTotal: 14
This is supposed to output t=m and then m is plugged into a function say for -3, plugging it into function f gives 23, well i want 22 blank spaces and then a asterik and go to next line. that is why i put -1 after %'f(m)-1's i
The asterisk appear right next to the t value here but they are way to the right of it when i made this post.
I am having trouble with the printf in this function:
Code: void print_orig_array(char string_array[MAX_PEOPLE][NAME_SIZE], int ages[MAX_PEOPLE], int length) { int counter; printf("Original list"); printf("
[URL] ....
Here is the output:
Am I missing something with the format specifier? How do I fix the 84 that gets pushed out?
Code: char Answer; printf(" To search for a specifc word, type (Y), to use a dictionary file, type (N):
[Code] .....
When I run the program, it gives:
To search for a specific word, type (Y), to use a dictionary file, type (N):
Sorry, the given input is invalid, please try again:
I can then input the number. Typing n,N,y or Y goes to the next part of the program without any problems, but if I type something else, I get:
Sorry, the given input is invalid, please try again:
Sorry, the given input is invalid, please try again:
I've fiddled about with the code for a while now, but nothing I do seems to work. What is causing it to be printed twice, or why the first getchar() is ignored.
I am making a program that takes the user's family names, their ages, and where they live. At the end I will be eventually averaging out their age and also printing the names of anyone who lives in Kansas.
I can't seem to get the Kansas part to work properly though.. When I execute the code, everything else works perfectly, but the Kansas part doesn't even print. Is there something different I need to do when strings are involved rather than integers/floats?
Code:
#include <stdio.h> int main () { /* variable definition: */
I am making a program that takes the user's family names, their ages, and where they live. At the end I will be eventually averaging out their age and also printing the names of anyone who lives in Kansas.
I can't seem to get the Kansas part to work properly though.. When I execute the code, everything else works perfectly, but the Kansas part doesn't even print. Is there something different I need to do when strings are involved rather than integers/floats?
#include <stdio.h> int main () { /* variable definition: */
I'm attempting to print a series of text from this loop, but for some reason all I am getting is the sum total and the number 1, like this
1 5175.11
When I want to get it for each iteration of the loop. I've cycled over this and compared it to my other loops I've used and I'm lost as to why this isn't working. I also tried using a do while but that didn't work as well.
#include<iostream> #include<conio.h> using namespace std; int main(void){ clrscr();
[Code] ....
I am trying to print ascii characters but problem is If i put a limit in for loop to 255 or more than 126 the output don't stop it keeps on going
I know there is another way to this program but what i want to know this why this happen in this logic....it doesn't happen if a<=125 or less then 125.
Write a count controlled loop than can print "i" char. The user is supposed to input a integer and that integer is how many asterisks there is on the blade, in this case it is 5.
* * ** ** **--------------- ******* ** ** ** * ** * -10 Rows high ** -blade always connects on second row of handle ** ** ** **------------------
I want to create a vertical histogram in my code. I already made it go vertical but not the way I want it.
Example: I want it like this:
Range1 Range2 Range3 Range4
And asterisks under each one, depending on the user input. (My code is below and doing it on here doesn't make it come out correctly)
But what I've managed to do is this:
Range1 * * *
Range2 * *
Range3 * * * *
Range4 * *
Which I don't want. I want everything else to stay pretty much the same since I can only use some features such as Arrays and really basic functions.
Here is my code: (Worked fine last time I used it and I am doing it on Visual Studio 2010 (at uni) and 2013 (on my laptop)).
#include <iostream> //Start of code using namespace std; int MarkValueInput; //Mark entered by user //Counter variables for ranges in While Loop int counterlow; //Counter for low range int countermidlow; //Counter for mid-low range int countermidhigh; //Counter for mid-high range int counterhigh; //Counter for high range
The function uses a "for" loop to print the given character the number of times specified by the integer.
How can I make a for loop to do that?
So.. my code looks like this:
// cpp : Defines the entry point for the console application // #include "stdafx.h" #include <iostream> using namespace std; void printMyInteger(int myInteger, char myChar) {
[Code] ....
So.. here is my error:
Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6 Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6 3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6
I am working on a small simple program my program fills up a air plane with customers there is 2 levels 1 and 2 and it will put that person in the spot depending on being picked.
So far i made a boolean airplane with 10 spots I can enter 1 person into the airplane with no problem but then after he sits down i get a infinite loop? I assume i maybe have to use the continue statement I feel like there is something simple that im missing i want to add more people. here is what i have
I'm trying to make a percentage counter inside a loop, printing each completed percent of the loop as it goes. I've managed to write such code, but when I run it the percentage output breaks down (becomes negative!) for large loops. I have an example below.
Code: #include <iostream> #include <sstream> #include <string> #include <stdlib.h> #include <stdio.h> using namespace std ; int main() {
[code].....
Compiling and running the above yields the output:
I'm new to programming and i'm trying to do a certain task. I want to use a for loop to read certain data from a txt file and print them to a console. I'm trying to read student names and their grades.
Something like 3 // 3 represents the number of students. George 97 Sarah 70 Maya 88
I need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h> int main(int argc, char **argv) { int i; printf("")
I am having a hard time with some of my homework, specifically regarding how to printf floats. I can't seem to print the number i want out using float, it just becomes a jumbled mess.
Thats the code I currently have, I've probably tried everything to get the number to come out, but I just cant seem to figure it out. It should look like this, but with different numbers and stock:
#include <stdio.h> struct database { int id_number; int age; float salary;
[Code] ....
When I compile, I get an error: test.c|18|error: incompatible type for argument 1 of 'printf'| note: expected 'const char *' but argument is of type 'float'|
I thought employee.salary is a float but the compiler expected 'const char'. How do I make this work?
I have the following line of the code. Now I want to save the content to a string. Is there a quick way for me to do the conversion using the same arguments/codes of printf?
