I am having a hard time with some of my homework, specifically regarding how to printf floats. I can't seem to print the number i want out using float, it just becomes a jumbled mess.
Thats the code I currently have, I've probably tried everything to get the number to come out, but I just cant seem to figure it out. It should look like this, but with different numbers and stock:
I am new with C programming and trying to learn how to create functions such as floats. But for some reason when I try to compile this program the compiler will tell me Weight() is not a function.
I'm trying to compare two float ranges and it seems to be a hit and miss. I'm trying to use a object origin and dimensions comparing it to another set for collisions.
Say I have a std::vector of size 10 of float. This will be a windowing average, as each cycle I need to remove the oldest element and add a new element. I figured vector was good because I can pop_front() then push_back(). Is there any clever way to get the average of the vector without using a for loop?
I'm getting unexpected output in 2 different cases. The 1st deals with bitfields. The C++ standard has this line about integral promotions:
An rvalue for an integral bit-field (9.6) can be converted to an rvalue of type int if int can represent all the values of the bit-field; otherwise, it can be converted to unsigned int if unsigned int can represent all the values of the bit-field.
If the bit-field is larger yet, no integral promotion applies to it. If the bit-field has an enumerated type, it is treated as any other value of that type for promotion purposes.
This sounds like the value of a bitfield will always be treated as a signed int if the signed representation of the value will fit in the bits. This seems to hold true for my C compiler, but not my C++ compiler.
I tried storing a small negative value in a bitfield that has enough bits to store the sign bit and the value. But when I print out the bitfield, I always get a large number
The other issue I'm having is sort of similar. I'm trying to store 4294967295 into a float, but when I print it out, I get 4294967296. i've tried storing a few other large values like this and what's printed out is rarely the value I stored. I thought it might be because of some int to float conversion, so I tried 4294967295.0. Still no luck. Then I remember that defaults to a double so maybe that's the issue so I tried 4294967295.0f. Still no luck. Why can't I store the correct value here? I don't think it's an IEE format thing since I can use these values as floats on a calculator program.
The example code showing both issues is below.
Code: #include <stdio.h> typedef struct { signed char x : 5; signed char y : 3; }my_struct_t;
I made this dice simulator which basically throws the dice 1 million times and outputs the frequency and percentage average for each side (1 to 6).
Everything is working fine, except my averages (floats) seem to be rounding up, causing 4% being "unassigned" at the end of the million rolls. I'm outputting with a setprecision of 2, but I only get 0's and no fractional numbers.
Im using the remquo function in the cmath library as follows:
int quotient; double a = remquo (10.3, 4.5, "ient);
This gives the correct remainder (a = 1.3) and quotient (quotient = 2).
Infact about 50% of the answers are right when I play around, however, trying something like:
int quotient; double a = remquo (2.25, 1.5, "ient);
yields an incorrect quotient of 2 and remainder of 0.
I do think this has something to do with float arithmetic. I recall tinkering with the float number 0.500 and that the CPU actually saves it as 0.50000000000000231. However if my suspicion of float arithmetic as the suspect is correct, I do not understand why a tenth decimal would make such a drastic difference as changing the quotient result.
#include <stdio.h> struct database { int id_number; int age; float salary;
[Code] ....
When I compile, I get an error: test.c|18|error: incompatible type for argument 1 of 'printf'| note: expected 'const char *' but argument is of type 'float'|
I thought employee.salary is a float but the compiler expected 'const char'. How do I make this work?
I have the following line of the code. Now I want to save the content to a string. Is there a quick way for me to do the conversion using the same arguments/codes of printf?
I am having trouble with the printf in this function:
Code: void print_orig_array(char string_array[MAX_PEOPLE][NAME_SIZE], int ages[MAX_PEOPLE], int length) { int counter; printf("Original list"); printf("
[URL] ....
Here is the output:
Am I missing something with the format specifier? How do I fix the 84 that gets pushed out?
Code: char Answer; printf(" To search for a specifc word, type (Y), to use a dictionary file, type (N):
[Code] .....
When I run the program, it gives:
To search for a specific word, type (Y), to use a dictionary file, type (N):
Sorry, the given input is invalid, please try again:
I can then input the number. Typing n,N,y or Y goes to the next part of the program without any problems, but if I type something else, I get:
Sorry, the given input is invalid, please try again:
Sorry, the given input is invalid, please try again:
I've fiddled about with the code for a while now, but nothing I do seems to work. What is causing it to be printed twice, or why the first getchar() is ignored.
I'm making my way through most of this assignment that I have, but now it seems like I've run into a bit of a roadblock. The issue that I'm having is not being able to printf a series of ints that I thought I had previously defined in another function. I don't want to clog up this post with the entire code, so I'll just post one function that defined an int to give an example. I will upload the whole thing upon request however.
Code:
#include <stdio.h> #include <stdlib.h> //Prototypes int AGrade1(int* grade1); int AGrade2(int* grade2); int AGrade3(int* grade3);
[Code] .....
I've tried many many things, but I just cant figure it out. This is what it's supposed to look like.
I just checking but confused with float. in that code same size int, and same type double are working but float showing nothing in printf..why?? i'm using GCC compiler int 32bit win7 os
I would like the following code to print: "Why doesn't this print?" and "I would like to print the sum of nc: 5". What am I doing wrong.
#include <stdio.h> //Use to test ideas and formats// main() { int c, nc; nc = 0;
[code]....
My result as compiled by gcc -o testing testing.c
This prints.
test t1,e2,s3,t4, 5,
I have not figured out how to sum and print as the above code indicates, which complicates my ability to do many of the exercises in "The C Programming Language". I am using a MacBook gcc compiler and X code as well. I cannot get the last two printf functions to work. I did the temperature example with "while (fahr <= upper)" and the printf printed.
Numbers are 3d6 Rolling die no.1... RolledDie: 4 DieTotal: 4 Rolling die no.2... RolledDie: 5 DieTotal: 9 Rolling die no.3... RolledDie: 5 DieTotal: 14
Okay so I am programming an 8051 variant to interact with an SD card. In a separate initialization routine in SD_CARD.c I pull out the vital information of the card into global variables. I then call Menu() which is in another source file but includes a header file with all of the variables declared as extern. Now here is the weird, part this is from my Menu.c
Now the output of the first printf is 16384 but the conditional evaluates to false. If I put this code in SD_CARD.c (Where VOLUME_1_SECTOR is defined) the conditional evaluates to true. I am confused why the printf works correctly in Menu.c but not the conditional.
I am trying to compare 2 strings of characters The users input containing 5 chars is compared to a table If the input is already be existent in the table the index of those chars in the table is printed Quest: how to copy the result of a printf() into an array ? The last printf() gives a sequence of numbers and I am trying to save that sequence to another array for further operation ! I have not been able to do that so far even with tmp[]=i ;
Code: #include <stdio.h> #include <string.h> #define N 30 #define n 100 int main (void) [code]....
I'm trying to create a program that will show what the 12th digit of a UPC code would be. However, once the user enters the first 11 digits the program doesn't execute the last call of printf. The program compiles with no issues.
Code:
#include<stdio.h> int main() { int o1, e2, o3, e4, o5, e6, o7, e8, o9, e10, o11, oddsum, evensum, twelve; printf
I cannot get the following to compile. The problem is the printf on the last line. I understand that printf requires a char (or pointer to char). I understand that I can convert between datatypes by putting the target data type in parenthises in front of the variable. But how do I cast the integer into a character and then get it's pointer to pass into printf?
Following is my code. I compile with gcc temp.c -o temp.
Note that I have tried many attempts at that last line and this is just the one that I really, really think should work (or is at least the closest to the correct answer).
This code shown below, using printf("%s", &(char)nextChar); returns
temp.c:26: error: lvalue required as unary '&' operand
If I try to use printf("%s", *(char)nextChar); I get the error
temp.c:26: error: invalid type argument of 'unary *' (have 'int')
This line printf("%s", (char)nextChar); returns the obvious
format '%s' expects type 'char *', but argument 2 has type 'int'
Code:
#include <stdio.h> int main() { printf("hello, world "); #if defined(SUNDIALS_EXTENDED_PRECISION)
