Say I have a std::vector of size 10 of float. This will be a windowing average, as each cycle I need to remove the oldest element and add a new element. I figured vector was good because I can pop_front() then push_back(). Is there any clever way to get the average of the vector without using a for loop?
View 5 RepliesI needed to compute average median and mode for numbers in a vector. Im having a few issues I have already figured out how to calculate average and median just not mode. Also the program crashes when 0 is entered instead of exiting nicely. Also i keep getting a error on line 47 saying primary expression expected before else.
#include <iostream>
#include <conio.h>
#include <math.h>
[Code]....
I must write a function that has a one dimensional double array and the number of values in the array as its arguments. Normalize the values. I must also print the maximum, minimum, average and numbers of values above the average in the array.
The equation that computes the normalized value from a value x is:
Normalized x= (x-min(array))/(max(array)-min(array))
My code does not print the correct normalized value, average and values above average.
Code:
#include <stdio.h>
int findMax( double array1[], int num_elements) // This function computes the maximum value of the array
{
int i, max=-32000;
for (i=0; i<num_elements; i++)
[Code] .....
I am trying to average the negative numbers and positive number and of course the total average.
This will read in a list of n values, where n is not known ahead of time. The number of values read into the array will be saved in n.
vector<int> readList() {
std::vector<int> result;
ifstream inFile;
inFile.open("setA.txt");
for (int x; inFile >> x; ) {
result.push_back(x);
[code]....
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) {
int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0;
for (auto i : array) {
sum += i;
if (i > 0) { pos_sum += i; ++pos_count; }
[code]....
I am having a hard time with some of my homework, specifically regarding how to printf floats. I can't seem to print the number i want out using float, it just becomes a jumbled mess.
Code:
#include <stdio.h>
#define TICKER "LRCX"
#define PURCHASE_DATE "01/02/13"
#define SELL_DATE "01/30/13"
#define INVESTMENT_AMOUNT "10,000.00"
[Code] .....
Thats the code I currently have, I've probably tried everything to get the number to come out, but I just cant seem to figure it out. It should look like this, but with different numbers and stock:
Stock: MCD Buy Date: 01/02/13 Sell Date: 01/29/13 Buy Share Price: $89.40 Sell Share Price: $91.50 Shares Purchased: 111.86
Amount of Investment: $10,000.00 Value of Shares Sold: $10,234.90 Amount of Gain/Loss: $234.90 Percent Gain/Loss: 2.35%
However, this is how mine turns out:
Code::Blocks
Enter share purchase price for LRCX=>23
Enter the selling price for LRCX=>23
Stock: LRCX
Buy Date: 01/02/13
Sell Date: 01/30/13
Buy Share Price: -1.#R
Sell Share Price: -1.#R
Shares Purchased: -1.#R
Amount of Investment: 10,000.00
Value of Shares Sold:-1.#R
Amount of Gain/Loss:-1.#R
Percent Gain/Loss:-1.#R%
Process returned 0 (0x0) execution time : 2.864 s
Press any key to continue.
I am new with C programming and trying to learn how to create functions such as floats. But for some reason when I try to compile this program the compiler will tell me Weight() is not a function.
Code:
#include <stdio.h>
float Weight(float Mass, float g)
{
float Weight = 0;
g = 9.81;
[Code] ....
I'm trying to compare two float ranges and it seems to be a hit and miss. I'm trying to use a object origin and dimensions comparing it to another set for collisions.
View 12 Replies View RelatedI am very new at c++ and ran into this problem.
pairPercentage = ((float)tempPair/hands) * 100;
flushPercentage = ((float)tempFlush/hands) * 100;
totalPairPercentage = pairPercentage + totalPairPercentage;
is there something I should be awarded of when adding two float(s) ? because totalPairPercentage will always return pairPercentage, not its summation.
also did (totalPairPercentage += pairPercentage);
Can we use modulo to compare two floats?
View 3 Replies View Relatedhow do you convert integers into floats / I remember there is something like ftoi, I am looking into something handy like the std
View 6 Replies View RelatedI'm getting unexpected output in 2 different cases. The 1st deals with bitfields. The C++ standard has this line about integral promotions:
An rvalue for an integral bit-field (9.6) can be converted to an rvalue of type int if int can represent all the values of the
bit-field; otherwise, it can be converted to unsigned int if unsigned int can represent all the values of the bit-field.
If the bit-field is larger yet, no integral promotion applies to it. If the bit-field has an enumerated type, it is treated as any other value of that type for promotion purposes.
This sounds like the value of a bitfield will always be treated as a signed int if the signed representation of the value will fit in the bits. This seems to hold true for my C compiler, but not my C++ compiler.
I tried storing a small negative value in a bitfield that has enough bits to store the sign bit and the value. But when I print out the bitfield, I always get a large number
In the example code below, I expect the output:
Code:
foo.x = -1
foo.y = -2
foo2.x = 31
foo2.y = 6
foo3.x = -1
foo4.x = 4294967295 But I get: Code: foo.x = 31
foo.y = 6
foo2.x = 31
foo2.y = 6
foo3.x = -1
foo4.x = -1 -------------------
The other issue I'm having is sort of similar. I'm trying to store 4294967295 into a float, but when I print it out, I get 4294967296. i've tried storing a few other large values like this and what's printed out is rarely the value I stored. I thought it might be because of some int to float conversion, so I tried 4294967295.0. Still no luck. Then I remember that defaults to a double so maybe that's the issue so I tried 4294967295.0f. Still no luck. Why can't I store the correct value here? I don't think it's an IEE format thing since I can use these values as floats on a calculator program.
The example code showing both issues is below.
Code:
#include <stdio.h>
typedef struct {
signed char x : 5;
signed char y : 3;
}my_struct_t;
[Code] .....
I can't get the values correctly parsed.
Code:
float **get(int sizeX, int sizeY) /* Allocate the array */ {
float** ary = new float*[sizeX];
for(int i = 0; i < sizeX; ++i)
ary[i] = new float[sizeY];
return ary;
[Code] ....
test.txt (without the comments).
Code:
2 3 // columns and rows of 2D array
0 0
1 1
2 2
I made this dice simulator which basically throws the dice 1 million times and outputs the frequency and percentage average for each side (1 to 6).
Everything is working fine, except my averages (floats) seem to be rounding up, causing 4% being "unassigned" at the end of the million rolls. I'm outputting with a setprecision of 2, but I only get 0's and no fractional numbers.
Im using the remquo function in the cmath library as follows:
int quotient;
double a = remquo (10.3, 4.5, "ient);
This gives the correct remainder (a = 1.3) and quotient (quotient = 2).
Infact about 50% of the answers are right when I play around, however, trying something like:
int quotient;
double a = remquo (2.25, 1.5, "ient);
yields an incorrect quotient of 2 and remainder of 0.
I do think this has something to do with float arithmetic. I recall tinkering with the float number 0.500 and that the CPU actually saves it as 0.50000000000000231. However if my suspicion of float arithmetic as the suspect is correct, I do not understand why a tenth decimal would make such a drastic difference as changing the quotient result.
How to output vector contents using the push_back function. My program reads in values just fine, but it does not output anything and I've been stuck on why.
here is my code:
#include <iostream>
#include <array>
#include <vector>
using namespace std;
int duplicate( vector < int > &vector1, const int value, const int counter)
[Code].....
I have a cpp app that reads in a number of files and writes revised output. The app doesn't seem to be able to open a file with a ' in the file name, such as,
N,N'-dimethylethylenediamine.mol
This is the function that opens the file :
Code:
// opens mol file, reads in rows to string vector and returns vector
vector<string> get_mol_file(string& filePath) {
vector<string> mol_file;
string new_mol_line;
// create an input stream and open the mol file
ifstream read_mol_input;
read_mol_input.open( filePath.c_str() );
[Code] ....
The path to the file is passed as a cpp string and the c version is used to open the file. Do I need to handle this as a special case? It is possible that there could be " as well, parenthesis, etc.
I need to create a class vector as a template and define operations on vectors.
And this is what I made.
#include<iostream>
using namespace std;
template<class T>
[Code].....
Lets say that I have a vector of vector of integers. <1,2,3,4> , <5,6,7,8>, <10,11,12,13>
How do I make a function that creates vector of vector of every different integers?
<1,5,10> , <1,5,11>, <1,5,12>, <1,5,13>
<1,6,10> , <1,6,11>, <1,6,12>, <1,6,13>
<1,7,10> , <1,7,11>, <1,7,12>, <1,7,13>
<1,8,10>, <1,8,11>, <1,8,12>, <1,8, 13>
<2,5,10>, <2,5,11>, <2,5,12>, <2,5,13>
and so on...
I have asked a related question before, and it was resolved successfully. In the past, when I wanted to use std::max_element in order to find the maximum element (or even sort by using std::sort) of a vector of structures according to one of the members of the structure, all I had to do was to insert a specially designed comparison function as the third argument of the function std::max::element. But the latter comparison function naturally accepts two arguments internally.
For instance, here is a test program that successfully finds the maximum according to just one member of the structure:
Code:
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
[Code] ....
And the output was this, as expected:
Maximum element S.a of vector<S> vec is at: 9
[I]max element of vec.a between slot 3 and slot 6 is: 6, and its index is: 6 vec[6].a = 6
[I]max element of vec.a between slot 4 and slot 7 is: 7, and its index is: 7 vec[7].a = 7
[I]max element of vec.a between slot 5 and slot 8 is: 8, and its index is: 8 vec[8].a = 8
[I]max element of vec.a between slot 6 and slot 9 is: 9, and its index is: 9 vec[9].a = 9
However, I now need to search and find an element of vector<myStruct> according to just one member of myStruct, instead of finding the maximum or sorting as before. This presents a problem because the function std::find does not accept such a comparison function as its third argument.
This was the description of the std::find function that I found: find - C++ Reference
Code:
template <class InputIterator, class T> InputIterator find (InputIterator first, InputIterator last, const T& val);
I could also find another function called std::find_if, but this only accepts a unary predicate like this: find_if - C++ Reference
Code:
template <class InputIterator, class UnaryPredicate> InputIterator find_if (InputIterator first, InputIterator last, UnaryPredicate pred);
And once again this is either inadequate of I don't see how to use it directly, because for the third argument I would like to insert a function that takes two arguments with a syntax like this:
Code:
int x=7;
std::vector<S>::iterator result;
result = std::find(vec.begin(), vec.end(), []( const (int x, const S & S_1) { return ( x == S_1.a ) ; } ) ;
Is there another std function that I can use to make search and find an element according to just one member of myStruct?
Or perhaps there is a clever way to pass two arguments to the unary predicate.
#include <iostream>
using namespace std;
int num_ints;
int num_doubles;
double running_total;
double average;
[Code] .....
Cannot divide the real output of the AVERAGE.:
Code:
#include<stdio.h>
#include<conio.h>
struct student
{
char Name[50];
[Code]....
How to power value in function too.
View 2 Replies View RelatedI have to get the average score for each student. And modify my avgmarks function and write the marks to a output txt file.
Code:
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int bubble(int*,int);
void filewrite();
void avgmarks();
void fileprint();
void filesort();
void rollin();
[Code] .....
"Write a program that prompts the user for an integer number from the keyboard, and store it in a variable num. After each number is typed in, add num to a total.
Do this six times, each time adding num to a total. (Be sure to reuse the same variable named num for each of the six numbers entered.) When all six numbers have been entered from the keyboard, calculate an average. Display the total and average calculated. "
Here is what I have so far:
Code:
#include<stdio.h>
int main() {
int num, total1, total2, total3, total4, total5, total6, avg;
printf("Enter first number:");
scanf("%2d",&num);
[Code] .....
Howe can i display the average of 100 values in c++ 2008....
View 4 Replies View RelatedI am attempting to write a program that takes a number(picked by the user) of test scores in an array then calculates the average and outputs the number of passed and failed tests.
On a side note I am attempting to use array notation in the main function and pointer notation in the other functions
#include<iostream>
#include<iomanip>
using namespace std;
int numScores;
int counter = 0;
double *scores;
//Function Prototypes
[Code]...