C :: Print Correct Normalized Value / Average And Values Above Average
Nov 14, 2013
I must write a function that has a one dimensional double array and the number of values in the array as its arguments. Normalize the values. I must also print the maximum, minimum, average and numbers of values above the average in the array.
The equation that computes the normalized value from a value x is:
My code does not print the correct normalized value, average and values above average.
Code:
#include <stdio.h>
int findMax( double array1[], int num_elements) // This function computes the maximum value of the array
{
int i, max=-32000;
for (i=0; i<num_elements; i++)
write a c++ program that reads an unknown number of integer values and then print count, sum and average of odd values, even values, positive values, negative values!!
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) { int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0; for (auto i : array) { sum += i; if (i > 0) { pos_sum += i; ++pos_count; }
I am attempting to write a program " that has a function that is passed an array of int and its size, and with that it prints out only the numbers that are above average. "
I have included my code so far, but I am only getting one value as output, and that value seems to be completely off. I keep trying, but I am really stuck.
#include <iostream> using namespace std; int average(int values[],int size); int main(){ int size; int values[] = {1,2,3,4,5,6};
[Code] ....
Added the floats in the average() function. But there is still a value problem.
i wrote following code to calculate average of the values entered to the array.After displaying the output following error was displayed.
"Run-Time Check Failure #2 - Stack around the variable 'marks' was corrupted.
A buffer overrun has occurred in q 3 410005111.exe which has corrupted the program's internal state. Press Break to debug the program or Continue to terminate the program. "
//Average mark of student 1 cout<<"Avarage mark of the student 1 :"<<(marks[0][0]+marks[1][0]+marks[2][0]+marks[3][0]); cout<<endl;
I seem to have reached a dead end in a program I am attempting to write.The purpose of the program is find the smallest, largest, and average values in a collection of N numbers. It needs to get the value of N before scanning each value in the collection of N numbers.I'm having trouble creating comparisons for each set. I have a feeling because of the way I structured my program, I'm unable to make a proper comparison. Maybe my approach was wrong as soon as I got to the for statement to loop N sets and N numbers.Here is my code so far:
Code:
#include <stdio.h> int main (void) { int num_sets, num_of_integers; int count, count2, set, sum = 0; int num, avg; }
[code]....
/* Here is where I would continue to attempt to make a comparison between sets to determine smallest to largest */
I have this code that im stuck on what i need to do is Extend the code such that when it starts the user is asked to input values to specify each of the three ranges before moving on to accept and tally the main values how do i do that Using a for loop to input and output array values Also calculate the average
*/ #include <stdio.h> int main(void) { /* Declare an array of integers */ int Grades[5]; int nCount; int nTotal = 0; /* Declare and initialise the value */ float fAverage;
#include <stdio.h> float total, avg, max, min; float judge[4]; int index; int array[4]; int main() { total = 0.0; max = array[0]; min = array[0];
[Code] ....
I dont understand how to make the array when it prints out only print out the final average and the final maximum score with the final minimum score but what its doing at the moment is just giving an average for each individual score taken...
Minimum and maximum scores are displaying 0.0
And it displays these things 4 times in a row i just want it to be displayed once.
"Write a program that prompts the user for an integer number from the keyboard, and store it in a variable num. After each number is typed in, add num to a total.
Do this six times, each time adding num to a total. (Be sure to reuse the same variable named num for each of the six numbers entered.) When all six numbers have been entered from the keyboard, calculate an average. Display the total and average calculated. "
Here is what I have so far:
Code: #include<stdio.h> int main() { int num, total1, total2, total3, total4, total5, total6, avg;
I am attempting to write a program that takes a number(picked by the user) of test scores in an array then calculates the average and outputs the number of passed and failed tests.
On a side note I am attempting to use array notation in the main function and pointer notation in the other functions
#include<iostream> #include<iomanip> using namespace std; int numScores; int counter = 0; double *scores; //Function Prototypes
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
#include<iostream> using namespace std; int main(){ int k,num,sum=0,GreaterNO=0; double average;
[Code] .....
above is my program, I have received an assignment which the lecturer request us to find a series of k numbers then
-display the average -display the total of numbers greater than the average
our lecturer request us do in 2 version, one is by using array, one is without using array, I have facing the coding problem when doing the VERSION WITHOUT USING ANY ARRAY to get the display the total numbers greater than the average, is there possible to get it?? because there are only one variable keep on looping, but the average will only get after get all the user input....?
What i need it to do is ask the user for a number of cases. The user will input numbers and the program should add the inputs until zero or a negative number is entered and then out put the average of those inputs. The amount of cases is pretty much how many times an average will be done. so if the amount of cases is 4. and the inputs are 1,3,(1+3/2)0 then it should output 2. and that would be ONE case, next inputs are 5,6,4,0(5+6+4/3) the output is 5 and that is case two. etc.
Here is my code:
#include <iostream> using namespace std; double avgVal(int, int); int main() { int amountOfCases; cin >> amountOfCases; int* numbers = new int[amountOfCases]; int input=0;
My program works fine in all areas but adding the average every loop. It gives me a weird -1.#IND as an output, and it's supposed to calculate the total mileage each time I enter new values per trip.
// Automobile Mileage.cpp : Defines the entry point for the console application. // //Programmer: Ryan Youngen
I was trying to make a program that asks the number of grades, get the grades and then get the average. I know I have to save the grades in an array but i don't know exactly how.
Write a program to compute average grades for a course. The course records are in a single file and are organized according to the following format: Each line contains a student's first name, then one space, then the student's last name, then one space, then some number of quiz scores that, if they exist, are separated by one space. Each student will have zero to ten scores, and each score is an integer not greater than 100. Your program will read data from this file and write its output to a second file. The data in the output file will be nearly the same as the data in the input file except that you will print the names as last_name, first_name and there will be one additional number at the end of each line: the average of the student's ten quiz scores.
The output file must be formatted such that first and last names appear together in a left justified column that is 20 characters wide where the last name comes first, then a comma and a space and then the first name. Use your read string function to read each name separately and then put them together into a larger correctly formatted string before trying to output them. Each quiz score should be listed in a right justified column that is 4 characters wide, and the average should appear in its own right justified column that is 10 characters wide.
Note that if a student has fewer than 10 scores, the average is still the sum of the quiz scores divided by 10; these students are assumed to have missed one or more of the quizzes. The output file should contain a line (or lines) at the beginning of the file providing appropriate column headings.
