What i need it to do is ask the user for a number of cases. The user will input numbers and the program should add the inputs until zero or a negative number is entered and then out put the average of those inputs. The amount of cases is pretty much how many times an average will be done. so if the amount of cases is 4. and the inputs are 1,3,(1+3/2)0 then it should output 2. and that would be ONE case, next inputs are 5,6,4,0(5+6+4/3) the output is 5 and that is case two. etc.
Here is my code:
#include <iostream>
using namespace std;
double avgVal(int, int);
int main() {
int amountOfCases;
cin >> amountOfCases;
int* numbers = new int[amountOfCases];
int input=0;
I have the random values down but when I try to assign randValue to another integer I get an error.I want to make an inner loop where I find 5 random number 50 times and print the average of those numbers.
I know I have the bare bones of the below, but without giving me a huge shove in the right direction can I have a poke? I have been programing for three months now. I have noticed when I do simple fun projects I learn more then what my professor assigned to me. The class is over but I want to keep building.C++ starts in one week...
I made a program that is suppose to receive 20 numbers or less and find the average, then show all numbers entered but my average does not show. It shows as 0 and a line pops up after every number returned. I am stuck and dont know how to fix the logical errors.
#include <iostream> #include <cmath> using namespace std; int main() { float num[20]; int amount_num;
5. Find the deviation of each score, and display the score and its deviation.
6. Find the Standard Deviation and Display
7. How many scores are within One Standard Deviation
So I have the average down, but I am getting stuck at the part of displaying the highest and lowest score. Every time I run the program I get two giant negative numbers for both of them. I put all the scores into a .txt file and I just opened in through the program.
I need to write a program that prompts the user for 10 grades and then find the average. I have that part but I need to average to not include -1. How can I tell the program to not calculate -1 into the average.
#include <iostream> using namespace std; int main() { //Declare variables float grade[10]; // 10 array slots int count; float total = 0; double average;
This is a simple program I am building to find the average of 5 grades where the lowest grade is dropped. I created a function findLowest() which accepts the 5 grades as arguments, finds the lowest grade and returns it as "lowest". I have tried many different way to find the lowest number. Right now, I am working with if...then statements.
#include <iostream> using namespace std; void printMessage(); //Prototype for printMessage void getScore(int&); //Prototype for getScore with reference variable int findLowest(int,int,int,int,int,int &); //Prototype for findLowest with reference variable
I seem to have reached a dead end in a program I am attempting to write.The purpose of the program is find the smallest, largest, and average values in a collection of N numbers. It needs to get the value of N before scanning each value in the collection of N numbers.I'm having trouble creating comparisons for each set. I have a feeling because of the way I structured my program, I'm unable to make a proper comparison. Maybe my approach was wrong as soon as I got to the for statement to loop N sets and N numbers.Here is my code so far:
Code:
#include <stdio.h> int main (void) { int num_sets, num_of_integers; int count, count2, set, sum = 0; int num, avg; }
[code]....
/* Here is where I would continue to attempt to make a comparison between sets to determine smallest to largest */
I'm trying to write a program that will allow a user to enter infinite numbers (one at a time) with a way to stop entering values, and once it stops it immediately displays:
Lowest number: Highest number: Number of values entered: Average of numbers:
what I can't figure out is:
-how to end the loop with something other than a number, preferably a char, so that it doesn't affect the average/lowest/highest
-how to output the lowest and highest numbers in a loop (would be easier to figure out were it finite and I could just type a bunch of printf/scanf)
What I have so far:
Code:
#include <stdio.h>#include <stdlib.h> #define pause system("pause") main(){ //n = amount of numbers input //x = number given by user //s = smallest number //l = largest number }
I am working on a program that calculates the average of a list of test scores entered, with the list ended with a negative score (which is not calculated), as long as a user enters a name.
#include<iostream> #include<string> using namespace std; int main() { string name; double score = 0.0; //user input score
[code]....
I have gotten the while loop to function. The problem lies in the calculation in the average of the test scores, such as when I enter the scores 87 76 90 -1 , which is supposed to give an average of 84.3 but my result when outputted is 86. what the problem is and what I can do to fix this error?
I got an assignment which asked me to create a program that asks user to input 10 numbers (positive and negative) integer. The program would be using loop to compute sum and average of all positive integers, the sum and average of negative numbers and the sum and average of all the number entered. But, the new problem is after I've entered all the number, the answer that the program gave me wasn't the answer that the program supposed to give. I don't know how to describe it, I would attach a picture and the code below:
#include <iostream> #include <cstdlib> using namespace std; int main() { //Declaration int x, value, sum, average, SumPositive, SumNegative, Positive, Negative; float AveragePositive, AverageNegative;
We were discussing how to find average time complexity of different algorithms. Suppose I've a the following nested loop
for(int i=0;i<n;i++) { min = i;
[Code].....
Now the outer loop will iterate N times. the inner loop will always iterate 3 times no matter what the value of N is. so the worst case time complexity should be O(n^2) but what about the average case and the best case? I mean in terms of searching we can figure out and distinguish between the worst,best and average as it depends upon the number of comparisons. But here how can the average and best case be different then the worst case.
im trying to write a source code that find the smallest, largest and average of numbers in array. the code runs fine, but it is not giving the highest number and the the average should include only four number excluding highest and smallest number from the array.
void OlympicJudging() // Olympic Judging { int numbers [6]; double average, sum = 0; int temp; for(int i = 0; i < 6; i++){ cout << "Please type a value for scores: "; cin >> numbers[i];
I have this code that im stuck on what i need to do is Extend the code such that when it starts the user is asked to input values to specify each of the three ranges before moving on to accept and tally the main values how do i do that Using a for loop to input and output array values Also calculate the average
*/ #include <stdio.h> int main(void) { /* Declare an array of integers */ int Grades[5]; int nCount; int nTotal = 0; /* Declare and initialise the value */ float fAverage;
Write a program that calculates the average of a stream of positive numbers. The user can enter as many positive numbers as they want, and they will indicate that they are finished by entering a negative number. For this program, treat zero as a positive number, i.e., zero counts as a number that goes into the average. Of course, the negative number should not be part of the average. You must use a function to read in the numbers, keep track of the running sum and count, compute the average, and return the average to the main() function. Note that you must use a loop to do this, as you don't know how many numbers the user will enter ahead of time. I am having problem writing a loop program for it..
Write a program that uses two functions; one finds the largest number and second largest number; and second function finds the average. The data, comprising of 20 different temperature values, is available on a file.
I must write a function that has a one dimensional double array and the number of values in the array as its arguments. Normalize the values. I must also print the maximum, minimum, average and numbers of values above the average in the array.
The equation that computes the normalized value from a value x is:
My code does not print the correct normalized value, average and values above average.
Code: #include <stdio.h> int findMax( double array1[], int num_elements) // This function computes the maximum value of the array { int i, max=-32000; for (i=0; i<num_elements; i++)
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) { int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0; for (auto i : array) { sum += i; if (i > 0) { pos_sum += i; ++pos_count; }
Ok my assignment has me doing vector math with some canned code provided for me by the instructor This is the header file to the class I'm working with and the .cpp file as far as I've gotten it.
#pragma once #include "Scalar.h" class Vector2D { public:
Vector2D(); Vector2D( const Vector2D& ) ;// copy constructor Vector2D( Scalar element[2] ) ; // initialize with an array
[Code] ....
I'm having trouble seeing which data members I'm multiplying together and what the initial state, continuing state, and after loop action I'm supposed to be using in the for loop.
